If the perimeter of an equilateral triangle is 60 cm, then what is its area?

Answers

Answer 1
Answer: Hello! The Perimeter is = 60cm
1 side = 60/3 = 20 cm
√s(s-a)(s-b)(s-c)s(s−a)(s−b)(s−c)

s = 30

√30(30-20)(30-20)(30-20)

=√30×10×10×10=√30000cm²

The Area is = 100√3 cm²
Answer 2
Answer: P=60/3
=20
a+b=c
C-b=a
40p-100=root 300
100root3

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What is the scientific notation of 0.0121

Answers

You move to the right, so the exponent is gonna be negative.
1.21 * 10-²

What is the word phrase for 25 - 0.6x

Answers

An equation is the word phrase for 25-0.6x

A city planner is measuring the distance of one city block. Which unit of measure should she use: 1 mile, 1 meter, 1/2 inch. Explain.​

Answers

Answer:

Meters

Step-by-step explanation:

Miles are to big to measure the distance of a city block, and inches are too small.

If she were to use inches, the number of the measure would be too large, and not easy to imagine and of she were to use miles, it would be a  little number (like a fraction or decimal number), that wouldn't be as easy to understand. Instead, using meters, the measurements wouldn't be too little or to big, they would be between 50 or 150 meters on average, so these are numbers more usable and practical.

Answer:

Step-by-step explanation:

The city planner should use distance to measure the city block

Evaluate the expression
(2/5+11)x(10-(-3))

Answers

Answer: 741/5

Step-by-step explanation:

57/5*(10/3)

57/5*13

Answer: answer is 741/5x

Step-by-step explanation:

Aliyah had some candy to give to her four children. She first took ten pieces for herself and then evenly divided the rest among her children. Each child received two pieces. With how many pieces did she start?

Answers

18 pieces.  You multiply 2 and 4 and get 8. then add 8 to teen because she took ten pieces for herself. the final answer is 18.


Select ALL of the expressions that are equivalent to
16 (5)/(2)

Answers

Answer:

A, B, C

Step-by-step explanation:

a^(m)/(n)=\sqrt[n]{a^m}\n\n(a^n)^m=a^(nm)\n\na^n\cdot a^m=a^(n+m)\n\n========================

16^(5)/(2)=\sqrt[2]{16^5}=√(16^5)\to\boxed{B}\n\n16=4^2\to16^(5)/(2)=\left(4^2\right)^(5)/(2)=4^{2\cdot(5)/(2)}=4^5\to\boxed{A}\n\n16^(5)/(2)=16^{2(1)/(2)}=16^{2+(1)/(2)}=16^2\cdot16^(1)/(2)=\left(16^2\right)\left(16^(1)/(2)\right)\to\boxed{C}