Which are acceptable names for the plane?Choose all answers that are correct.



A.
plane AU

B.
plane JAU

C.
plane R

D.
plane ABC
Which are acceptable names for the plane? Choose all answers - 1

Answers

Answer 1
Answer: answers is d,and c but i am not positive  

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The circumference, or perimeter, of a circle can be found by multiplying its diameter by 3.14. What is the circumference of a circle that has a diameter of 1\2 inch? Express your answer as a decimal.

Answers

C=πd

π≈3.14
------------

If d=1/2 inches

C=(1/2 inches)*π

=1/2π inches
The answer to your question is 1.57

What are the solutions of 3(x – 4)(2x - 3) = 0? Check all that apply.

Answers

Answer:

x=4     x = 3/2

Step-by-step explanation:

3(x – 4)(2x - 3) = 0

We can use the zero product property

x-4 =0   2x-3=0

Solve each equation

x-4 =0     2x-3=0

x=4         2x=3

              x =3/2

Jackie has a puzzle book that contains a total of 65 puzzles. She has completed 2/5 of the puzzle. If Jackie completes 13 more puzzles, what is the total number of puzzles that she will have to completed in the book ( please right how to solve this)

Answers

ok well 2/5 of 65 = 26
and so if jackie does 13 more then in total they've done 39 puzzles. so 65-39 = 26 more puzzles to do

34 packages are randomly selected from packages received by a parcel service. The sample has a mean weight of 25.9 pounds and a standard deviation of 3.8 pounds. What is the 95% confidence interval for the true mean weight, μ, of all packages received by the parcel service?24.6 < μ < 27.2

24.8 < μ < 27.0

24.2 < μ < 27.6

24.4 < μ < 27.4

Answers

The 95% confidence interval for the true mean weight, μ, of all packages received by the parcel service is;

Option A; 24.6 < μ < 27.2

We are given;

Sample mean; x' = 25.9 pounds

Standard deviation; σ = 3.8 pounds

Confidence level; CL = 95%

Sample size; n = 34

Now formula for confidence interval is;

CI = x' ± z( σ/√n)

Where z is critical value at given confidence level.

z at CL of 95% is; z = 1.96

Thus;

CI = 25.9 ± 1.96(3.8/√34)

CI = 25.9 ± 1.3

CI = (25.9 - 1.3), (25.9 + 1.3)

CI = (24.6, 27.2)

Read more at; brainly.com/question/12970960

Answer:

24.6 < μ < 27.2

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = (1-0.95)/(2) = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the margin of error M as such

M = z*(\sigma)/(√(n))

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96(3.8)/(√(34)) = 1.3

The lower end of the interval is the sample mean subtracted by M. So it is 25.9 - 1.3 = 24.6 pounds.

The upper end of the interval is the sample mean added to M. So it is 25.9 + 1.3 = 27.2 pounds.

So the correct answer is:

24.6 < μ < 27.2

5/9×3/4 in simplest form

Answers

5/9* 3/4
= 5/(3*4)
= 5/12

The final answer is 5/12~

Answer:

r3523w5r23w5

Step-by-step explanation:

a.S= 230T– 110; 1500 lbc.T= 230S– 110; 1500 lbb.S= 230T+ 110; 1720 lbd.S= 199T– 110; 1280 lba.S= 230T– 110; 1500 lbc.T= 230S– 110; 1500 lbb.S= 230T+ 110; 1720 lbd.S= 199T– 110; 1280 lba.S= 230T– 110; 1500 lbc.T= 230S– 110; 1500 lbb.S= 230T+ 110; 1720 lbd.S= 199T– 110; 1280 lba.S= 230T– 110; 1500 lbc.T= 230S– 110; 1500 lbb.S= 230T+ 110; 1720 lbd.S= 199T– 110; 1280 lba.S= 230T– 110; 1500 lbc.T= 230S– 110; 1500 lbb.S= 230T+ 110; 1720 lbd.S= 199T– 110; 1280 lb

Randy currently has a batting average of .388. What two fractions is this decimal between?

Answers

The answer is 

(3)/(8) and (5)/(12)


3/8 and 5/12 is my answer and what I got.