What is 1/8 in percentage

Answers

Answer 1

Answer: 12.5%

I hope I helped please leave thanks

Answer 2

Answer: That would be 12.5%. All you have to do is divide 100 by 8.

Related Questions

You are standing 44 meters from the base of a building. You estimate that the angle of elevation to the top of the 86th floor (the observatory) is 82°. If the total height of the building is another 121meters above the 86th floor, what is the approximate height of the building? (Round your answers to one decimal place.)metersOne of your friends is on the 86th floor. What is the distance between you and your friend?meters
If the midpoint between (18, y) and (20, -15) is (19, -5), find the value of y.
tina and jim work at a different car wash. tina is paid $37 per day plus 1.50 for each car she washes. jim is paid $40.00 per day plus 1.00 for each car she washes.write an expression that represents the amount tina is paid each day given the number of cars she washes. I put 37+1.5cwrite an expression that represents he amount jim is paid each day given the number of cars he washes. I put 40+1.00c Did I do this correct???
HELPPP PLEASE!!Three research departments have 10, 7 ,6 and members, respectively. If each department is to select a delegate and an alternate to represent the department at a conference, in how many ways can this be done?
Please help ASAP 25 pts

A 20m ladder and a 15m ladder were leaned against a building. The bottom of the longer ladder was 7m farther from the building than the bottom of the shorter ladder, but both ladders reached the same distance up the building. Find this distance.6m

12m

10m

9m

Answers

Answer:

The correct answer is: d=9m

Step-by-step explanation:

Ok, the ladders leaned against a building make two right triangles with same the same height, which we will call h. For the 20m ladder, its leg is (7+d) and for the 15m ladder, its leg is d, and the two hypotenuses are 20 and 15 respectively.

Then, using the Pythagorean Theorem we have:

20m ladder:

20^2 = h^2 + (d+7)^2 (Eq. 1)

400 = h^2 + d^2 + 2*7*d + 7^2 (expanding the theorem)

400 = (h^2 + d^2) + 14*d + 49 (Eq. 2)

15m ladder:

15^2 = h^2 + (d)^2 (Eq. 3)

Since h^2 + (d)^2 is equal to 15^2, we can substitute (2) into (3):

400 = (15^2) + 14*d + 49

400 = 225 + 14*d + 49

14*d = 400 - 225 - 49 (clearing the variable d)

14*d = 126

d = 9 m

And since we now know that d is equal to 9m. For the longer ladder is (d+7)=(9+7)=16m.

And, then the shorter ladder is 9m from the building and the longer ladder is 16m from the building

A carpenter added a diagonal brace to gate. The gate is 8ft. Wide and 10 ft. Tall. How long is the brace

Answers

Answer:

The brace is $2√(41)$ ft ≅ 12.806 ft long

Step-by-step explanation:

The length of the diagonal of a rectangle can be found using this rule

$d=\sqrt{l^(2)+w^(2)}$ , where

l is its length

w is its width

∵ The gate has shaped a rectangle

∵ Its length = 10 ft

∵ Its width = 8 ft

∴ l = 10 and w = 8

∵ The brace is the diagonal

→ By using the rule above

∴ $d=\sqrt{(10)^(2)+(8)^(2)}=√(100+64)=√(164)$

∴ The length of the brace = $2√(41)$ ≅ 12.806 ft

∴ The brace is $2√(41)$ ≅12.806 ft long

PLEASE HELP!!!!!The data set represents the heights of players on a soccer team.

5.75, 5.16, 6, 5.25, 5.5, 6.25, 5.66, 5.33, 5.33, 6, 5.75. 5.66, 5.16

What is the interquartile range (IQR) of the data set?

A. 0.585
B. 1.09
C. 5.6
D. 5.875

Answers

Answer:

Option: A(0.585)

Step-by-step explanation:

After arranging our data in ascending order we get that:

5.16 5.16 5.25 5.33 5.33 5.5 5.66 5.66 5.75 5.75 6 6 6.25

Quartiles divide a rank-ordered data set into four equal parts. The values that divide each part are called the first, second, and third quartiles; and they are denoted by Q1, Q2, and Q3, respectively.

$Q_1$ is the "middle" value in the first half of the rank-ordered data set.

$Q_2$ is the median value in the set.

$Q_3$ is the "middle" value in the second half of the rank-ordered data set.

The interquartile range is equal to Q3-Q1.

So, the Median( $Q_2$ )of data is given by: 5.66

also the lower half is:

5.16 5.16 5.25 5.33 5.33 5.5

Hence, the middle value or median of this lower half of this data lie between 5.25 and 5.33 which is 5.29.

Hence, $Q_1$ =5.29

Similarly the upper half is:

5.66 5.75 5.75 6 6 6.25

Hence, the middle value or median of this upper half of this data lie between 5.75 and 6 which is 5.875

Hence, $Q_3$ =5.875

Hence, the interquartile range= $Q_3-Q_1=5.875-5.29=0.585$

Hence, option A is correct.

Answer: Option: A(0.585)

Step-by-step explanation:

A film set designer is using white and colored tiles in a pattern to create paths of different lengths. If x is the length of the path in feet, the number of colored tiles needed to make it is calculated using the rule (3xy)(7xy²), where y represents the number of white tiles.Which simplified expression represents the number of colored tiles used for a path of length x feet?

Answers

the number of colored tiles needed to make it is calculated using the rule: (3xy)(7xy²) where x is the length of the path in feet y represents the number of white tiles

(3xy) (7xy^2)

= 21(x^2)(y^3) is the simplified expression represents the number of colored tiles

Is this equation standard form of an ellipse or circle?-3x^2-3y^2-12x-12y+24=0
What's the center?

Answers

The standard form equation for a circle is

$(h-x)^2+(k-y)^2=r^2$

where (h, k) is the center and r is the radius.

The standard form equation for an ellipse is

$((x-h)^2)/(a^2)} + ((y-k)^2)/(b^2) = 1$

(center h, k and major and minor axes a and b)

This equation is standard form for neither, but might be general form for one.

$-3x^2-3y^2-12x-12y+24=0 \n -3(x^2+y^2+4x+4y)=-24 \n x^2+4x+y^2+4y=8\ (complete\ the\ squares)\n (x^2+4x+4)+(y^2+4y+4)=8+4+4\n (x+2)^2+(y+2)^2=16 \n Circle\ with\ radius\ 4\ and\ center\ (2,\ 2)$

Complete the square
t^2+10t=75

Answers

COMPLETING THE SQUARE (PROCESS):
Do a reverse factoring procedure to develop the following form of equation:
(t + a)^2 = b

where:
t = unknown variable
a = coefficient
b = coefficient

Then take square root of both sides to find value of unknown variable as follows:

t^2 + 10t = 75
(t^2 + 10t + 25) = 75 + 25
(t^2 + 5t + 5t + 25) = 100
(t + 5)(t + 5) = 100
(t + 5)^2 = 100
√(t + 5)^2 = √100

Two solutions exist:
+(t + 5) = 10
AND
-(t + 5) = 10

Thus:
t = 10 - 5 = 5
AND
t = -5 - 10 = -15

Answer:
t = 5
AND
t = -15

$t^2+10t=75 \n t^2+10t+25-25=75\n (t+5)^2=100\n |t+5|=10\n t+5=10 \vee t+5=-10\n t=5 \vee t=-15$

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