Last year the enrollment of genoa middle school was 465 students. this year the enrollment is 525.

Answers

Answer 1
Answer:

Answer:

The amount of change is 60

The percent of change is 13%, increase.

Step-by-step explanation:

Consider the provided information.

Last year the enrollment of genoa middle school was 465 students. this year the enrollment is 525.

The amount of change is: 525-465=60

That means this yr 60 more student get enrollment.

Now find the percentage change.

\text{Percent of change}=\frac{\text{Amount of change}}{\text{Orignal amount}}

Substitute the respective values:

\text{Percent of change}=(60)/(465)\approx0.13

\text{Percent of change}=13\%

Hence, the percent of change is 13% and percentage is positive so this is a percent of increase.

Answer 2
Answer: The enrollment Count Went Up By 60 Student Enrollments :3

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Answers

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Could you please solve me this exercice: :3x^2-5x+√(x^2-5x+7)=5

Thank you a lot! :3 :3 :3

Answers

Domain:x^2-5x+7\geq0\n\na=1;\ b=-5;\ c=7\n\n\Delta=b^2-4ac\to\Delta=(-5)^2-4\cdot1\cdot7=25-28=-3 < 0\n\ntherefore\ D:x\in\mathbb{R}


Find\ minimum\ value\ of\ x^2-5x+7\n\ny_(min)=(-\Delta)/(4a)\to y_(min)=(-(-3))/(4\cdot1)=\boxed{(3)/(4)}\n-----------------------------\nx^2-5x+√(x^2-5x+7)=5\ \ \ \ \ |add\ 7\ to\ both\ sides\n\nx^2-5x+7+√(x^2-5x+7)=12\n\nsubtitute\ t=x^2-5x+7\ (t\geq(3)/(4))\n\nt+√(t)=12\ \ \ \ |subtract\ t\ from\ both\ sides\n\n√(t)=12-t\ \ \ \ \ \ |square\ both\ sides

t=(12-t)^2\n\nt=12^2-2\cdot12\cdot t+t^2\n\nt=144-24t+t^2\n\nt^2-24t+144=t\ \ \ \ \ |subtract\ t\ from\ both\ sides\n\nt^2-25t+144=0\n\nt^2-9t-16t+144=0\n\nt(t-9)-16(t-9)=0\n\n(t-9)(t-16)=0\iff t-9=0\ or\ t-16=0\n\nt=9\ or\ t=16

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Answer:\n\boxed{x=(5-√(33))/(2)\ or\ x=(5+√(33))/(2)}
 if xy=0 then x or/and y must be 0 so we try to get it to zero later

so first we get the square root on one side by itself
so subtract x^2-5 from both sides (-x^2+5 to both sides)

√(x^2-5x+7)=-x^2+5x+5
square both sides (or both sides to the ^2 power)
gets rid of the √
x^2-5x+7=(-x^2+5x+5)^2=x^4-10x^3+15x^2+50x+25
so subtract x^2 from both sides
-5x+7=x^4-10x^3+14x^2+50x+25
add 5x to both sides
7=x^4-10x^3+14x^2+55x+25
subtract 7 from both sides
0=x^4-10x^3+14x^2+55x+18
factor
(x^2-5x-9)(x^2-5x-2)=0
(x^2-5x-9)=0
(x^2-5x-2)=0
I'm not sure how to proceed but if you can find the factors of (x^2-5x-2) and (x^2-5x-9) and set them to zero, you can get the answers

A line passes through (2, −1) and (4, 5). which answer is the equation of the line? −3x y=−7−3x y=−7 −3x y=17−3x y=17 −3x 5y=13−3x 5y=13 −3x 5y=−13

Answers

Equation of a line through two points is given by y - y1 = ((y2 - y1)/(x2 - x1))(x - x1)
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Answers

Answer:F(1)=-2x-2

Step-by-step explanation:

The line's slope intersects the Y-axis at -2, and it passes through the point (-2,2). If you remember the rule of run over rise, you can find the slope. The rise is 4 units as the line moves up from the point (-2,2), and the run is 2 units as the line moves over to the point where it intersects the Y-axis at -2. So, the slope is 4/2, which simplifies to 2 or -2(-2). I apologize for any grammar errors in my previous message, but the answer is correct either way.

What is 4-6h-8h=60 answer

Answers

First you can subtract 6h-8h =-2h
4-2h=60
-4-2h=-4
------------
2h=56
Now divide and you get 56/2 =28