Help please, I’ll mark brainylest or what ever it’s called .

Answer:

Here we have:

IxI < 7

This also can be written as:

-7 < x < 7

and:

IyI < 2.

As above, we can write this as:

-2 < y < 2.

Then the graph of this region will be a rectangular area, where the perimeter is a dashed line (because here we use the strictly smaller or strictly larger symbols)

Such that the vertical component goes from -2 to 2, and the horizontal component goes from -7 to 7.

The area would be the area inside that rectangle, where i did not shade it so it is easier to read.

Final answer:

To sketch and shade the region defined by the inequalities |x| < 7 and |y| < 2, identify the boundaries and sketch the rectangle, shading the region within it.

Explanation:

To sketch and shade the region defined by the inequalities |x| < 7 and |y| < 2, we first identify the boundaries of the region. The inequalities |x| < 7 and |y| < 2 represent lines parallel to the x-axis and y-axis, respectively. The region is bounded by these lines and lies within the rectangle with vertices (-7, -2), (-7, 2), (7, -2), and (7, 2). We sketch the rectangle and shade the region within it.

Learn more about Sketching and shading region in the xy-plane here:

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Answer:

Credit cards typically have high interest rates compared to most other types of loans. That means it’s potentially expensive to borrow money with a credit card. When you don’t pay your full credit card balance every month, it’s easy to accumulate boatloads of interest fees quickly.

What is a credit card minimum payment? It’s the minimum amount of money a credit card company is willing to accept each month to keep your account in good standing.

Don’t make the mistake of thinking the minimum due is a “monthly payment” you should be making to pay off your credit card bill. When you only pay the minimum due on your credit card statement, your credit card issuer will make a lot of extra money from you.

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

the line is going down so we know it has to be a negative slope narrowing the answer choices down to a and c but when you pick a point to check for the reigon (i used 0,0 as a basic point) only c satisfies the inequality while keeping the point , not a.

Answer:

See deductions below

Step-by-step explanation:

1)

a) p(y)∧q(y) for some y (Existencial instantiation to H1)

b) q(y) for some y (Simplification of a))

c) q(y) → r(y) for all y (Universal instatiation to H2)

d) r(y) for some y (Modus Ponens using b and c)

e) p(y) for some y (Simplification of a)

f) p(y)∧r(y) for some y (Conjunction of d) and e))

g) ∃x (p(x) ∧ r(x)) (Existencial generalization of f)

2)

a) ¬C(x) → ¬A(x) for all x (Universal instatiation of H1)

b) A(x) for some x (Existencial instatiation of H3)

c) ¬(¬C(x)) for some x (Modus Tollens using a and b)

d) C(x) for some x (Double negation of c)

e) A(x) → ∀y B(y) for all x (Universal instantiation of H2)

f)  ∀y B(y) (Modus ponens using b and e)

g) B(y) for all y (Universal instantiation of f)

h) B(x)∧C(x) for some x (Conjunction of g and d, selecting y=x on g)

i) ∃x (B(x) ∧ C(x)) (Existencial generalization of h)

3) We will prove that this formula leads to a contradiction.

a) ∀y (P (x, y) ↔ ¬P (y, y)) for some x (Existencial instatiation of hypothesis)

b) P (x, y) ↔ ¬P (y, y) for some x, and for all y (Universal instantiation of a)

c) P (x, x) ↔ ¬P (x, x) (Take y=x in b)

But c) is a contradiction (for example, using truth tables). Hence the formula is not satisfiable.

Answer:

Its B

Step-by-step explanation: