miguels physical eduction class lasts for 3/4 of an hour. today they spent 3/4 of that time playing dodge ball. what fraction of an hour did he spend playing dodge ball?

Answers

Answer 1
Answer: the answer is 9/16

there are two ways you can get this
take 3/4 times 3/4 to get 9/16
or
3/4 of an hour = 45 min and 3/4 of 45 min = 33.75 min and 33.75/60(minutes in an hour) = 9/16
Answer 2
Answer: 3/4 of 60 minutes is 45 minutes. Then if they played dodge ball 3/4 (75%) of that time the answer is: 3/4 (75%) of 45 minutes = 33.75 minutes. Then 33.75 minutes divided by 60 minutes = 0.5625 (56.25%) of 60 minutes playing dodge ball. Liv219 has already given you the answer in fraction form.

Related Questions

Linda is paid double her normal hourly rate for each hour she works over 40 hours in a week. Last week she worked 52 hours and earned $544. What is her hourly rate? Equation = (use h as variable) Weekly Rate = $
The Westwood Warriors basketball team wants to score more points. To get better at scoring points the team is trying to improve its offensive strategies. Some opponents primarily use a zone defense, while others primarily use a man-to-man defense. When the Warriors play against teams that use a zone defense they score an average of 67 points per game with a standard deviation of 8 points per game. When they used a new offensive strategy against this defense, they scored 77 points. What is the Z-score of this value
IF U CAN HELP ME ILL BRAINIFY U AND U GET ALL MY POINTS. IT HAS TO BE A GOOD ANSWER, AS I THINKING I GOT THE CORRECT ANSWER, SO YOU CANT FOOL ME!!Sherie makes a canvas frame for a painting using stretcher bars. The retuangular painting will be 12 inches long and 9 inches wide. What should be the diagonal length of the painting in Sherie's question? Record your numerical response. Do not include words, units or spaces
Jamie mowed 7 lawns. He earned $10, $15, $12, $15, $8, and $15 for six lawns. How much did he earn the seventh time if the mean of the data is $12?And can you please provide the work? I've tried adding all and dividing by total which I got 75. I just don't know what to do on how to find the number that would give me 12 as the question asks.
Find A ∩ (BC). A = {2, 3, 5, 8} B = {3, 5, 7} C = {2, 4, 8}

two sides of an equilateral triangle measure (y+10) and (y^2(-2)). if the perimeter of the triangle is 21 units what is the value of y?

Answers

Answer:

  y = -3

Step-by-step explanation:

Each side of an equilateral triangle will have a length that is 1/3 the perimeter. This triangle has sides of length 21/3 = 7, so ...

  y + 10 = 7

  y = 7 - 10

  y = -3

This is consistent with the other given side measure ...

  y^2 -2 = (-3)^2 -2 = 9 -2 = 7

I do have a time limit. I appreciate any helpIf YB = ZA find the value of X and the length of YB

Answers

Since ZA and YB are equal in length and the two lines are parallel to each other.

Also, we can see that YZ and AB are perpendicular to both ZA and YB, thus

YZ = AB

16x - 4 = 4 - 4x

16x + 4x = 4 + 4

20x = 8

x= 8/20 = 2/5

YB = ZA = 20x - 5 = 20(2/5) - 5 = 3

Thus, the value of x is 2/5 and length of YB is 3 units.

So, the correct answer is option A


. A field will be made in the shape of a rectangle with an area of 400 square meters. One side of the field is along a river and a fence will be built along the other three sides. A brick wall perpendicular to the river will be built to divide the field into two equal halves. the wall costs $20 per meter and the fence costs $10 per meter to build. what is the lowest possible cost to build such a field?

Answers

Answer:

The correct answer is $800.

Step-by-step explanation:

Let the length and width of the field be equal to l meters and b meters respectively and l > b.

Area of the field is given by l × b = 400 square meters.

The river is supposed to be along the longest side so that the price of fencing the other three sides is minimum. Thus the total perimeter of the fence is b+ b+ l = 2b+l.

Total cost for fencing the other sides of the field = $ 10 × (2b + l)

The wall is supposed to be perpendicular to the river and thus the length of the wall is b meters.

Total cost for the wall is $ 20 × b

Therefore, the total price for making the field is given by

C = 10 × (2b + l) + 20 × b

⇒ C = 40b + 10l

⇒ C = (16000)/(l) + 10l

To minimize the cost we differentiate the cost with respect to l and equate it to zero.

(dC)/(dl) = 0 = - (16000)/(l^(2)) + 10

l^(2) = 1600

l = 40 ; [ negative sign neglected as length cannot be negative ]

b = 10

The second order derivative of C is positive giving the minimum value of the cost.

Thus the minimum cost required to make the field is given by $800.

Final answer:

To find the lowest possible cost to build the field, we need to determine the dimensions that will yield the minimum perimeter and then calculate the total cost of building the field. By differentiating the cost equation and solving for x, we can find the dimensions that minimize the cost.

Explanation:

To find the lowest possible cost to build the field, we need to determine the dimensions that will yield the minimum perimeter. Since the area of the field is 400 square meters and it will be divided into two equal halves by a brick wall, each half will have an area of 200 square meters. Let's say the length of the field is x meters. Then the width of each half will be 200/x meters.

The perimeter of the field is the sum of the lengths of the three sides:

Perimeter = 2x + 200/x + 200/x

Now, we can define the total cost to build the field as:

Total Cost = Cost of wall + Cost of fence

Cost of wall = 2x * $20 (since there are two halves)

Cost of fence = (2x + 200/x + 200/x) * $10 (since there is a fence on three sides)

Therefore, the total cost is: Total Cost = 2x * $20 + (2x + 200/x + 200/x) * $10.

To minimize the cost, we can differentiate the total cost with respect to x and set it equal to zero:

d(Total Cost)/dx = 0

Simplifying this equation will give us the value of x that minimizes the cost. We can solve this equation to find the minimum cost to build the field.

Learn more about field here:

brainly.com/question/25117322

#SPJ3

Graph and find the x-intercept, y-intercept, domain, range, and horizontal asymptote of the function y = 4x

Answers

The function y=4x is a line. As such, its domain and range is the whole real number set \mathbb{R}, and it has no horizontal nor vertical asymptotes.

Moreover, there's no constant term, so it's x and y intercept is the origin (0,0).

A young sumo wrestler decided to go on a special high-protein diet to gain weight rapidly. When he started his diet, he weighed 79.5 kilograms. He gained weight at a rate of 5.5 kilograms per month. Let y represent the sumo wrestler's weight (in kilograms) after x months. Which of the following could be the graph of the relationship? graph of an increasing linear function in quadrant 1 with a positive y-intercept (Choice B) B graph of an increasing linear function in quadrants 1 and 4 with a positive x-intercept and negative y-intercept (Choice C) C graph of a decreasing linear function in quadrants 1 and 4 with a positive x-intercept and positive y-intercept (Choice D) D graph of a decreasing linear function in quadrant 4 with a negative y-intercept

Answers

Answer:

(Choice A) A graph of an increasing linear function in quadrant 1 with a positive y-intercept.

Step-by-step explanation:

The weight of the sumo wrestler starts at a positive value of 79.5 kilograms, and we are given that the sumo wrestler gains a linear amount of weight per month at 5.5 kilograms per month.

If we were to graph this relationship, the sumo wrestler's weight would be represented on the y-axis, and the amount of time on the x-axis.

So the initial weight would occur at (0, 79.5) which is the positive y-intercept.

And since his weight is increasing at 5.5 kilograms per month, the slope of the linear function is positive.

Hence, the graph of the linear increasing function in quadrant 1 with a positive y-intercept.

Cheers.

Can someone pls help me pls

Answers

Answer:

Answer attached

Step-by-step explanation: