MATHEMATICS HIGH SCHOOL

Which description is correct for the polynomial −5x^2−3x+3 ?quadratic trinomial

quadratic binomial

quartic binomial

cubic binomial

Answers

Answer 1

Answer: quadratic trinomial
The x^2 term makes it quadratic
Since there are 3 terms, that makes it a trinomial

Answer 2

Answer:

Answer:

quadratic trinomial

Step-by-step explanation:

Related Questions

a square patio has an area of 225m2. the owner wants to put lights around the patio each string of lights is 25m long. how many strings of lights are needed?
PLEASE HELP!!! WILL GIVE CROWN!!!
The probability that Shelly will go to a movie (event A) on Friday is 0.78, and the probability that Danielle will go to a movie (event B) the same day is 0.63. The probability that Shelly will go to a movie, given that Danielle goes to a movie, is 0.87. Which statement is true? a. Events A and B are independent because P(A|B) ≠ P(A). b. Events A and B are independent because P(A|B) = P(B). c. Events A and B are dependent because P(A|B) = P(A) x P(B). d. Events A and B are dependent because P(A|B) ≠ P(A). e. Events A and B are dependent because P(A|B) = P(A).
What is the approximate volume of a cylinder with a diameter of 10 meters and a height of 5 meters
Please help me i dont get it

Over a two-hour time period, a snail moved 108 inches. How far is this in yards?

Answers

In two-hour time period, a snail moved 3 yards.

Given that, over a two-hour time period, a snail moved 108 inches.

Metric Conversion refers to the conversion of the given units to desired units for any quantity to be measured.

We know that, 1 yard = 36 inches

Here, in yards = 108/36

= 3 yards

Therefore, in two-hour time period, a snail moved 3 yards.

To learn more about the metric conversion visit:

brainly.com/question/21244256.

#SPJ6

the snail moved 108 inches
108/36=3 yards
as 1 yard=36 in

What is the total cost of a $12.49 item with a sales tax of 5%?

Answers

Answer: $13.11

Step-by-step explanation:

hope this helps!

For brainiest:):):):):):)

Answers

Answer:

4=12%

5=7

6=12.25

7=82%

8=15.36

Step-by-step explanation:

youre welcome

The volume Equals Four thirds pi r cubed of a spherical balloon changes with the radius. a. At what rate (cubed/in) does the volume change with respect to the radius when r equals 9 in question mark b. Using the rate from part a, by approximately how much does the volume increase when the radius changes from 9 to 9.5 in question mark

Answers

Answer:

Step-by-step explanation:

Given

Volume of spherical Balloon is given by

$V=(4)/(3)\pi r^3$

(a)Rate of change of balloon w.r.t to radius is given by

$\frac{\mathrm{d} V}{\mathrm{d} r}=3* (4)/(3)\pi r^2=4\pi r^2$

at $r=9\ in.$

$\frac{\mathrm{d} V}{\mathrm{d} r}=324\pi\ in.^2$

(b)Using the rate Volume change when radius increases from r=9 in. to r=9.5 in.

$\Delta V=4\pi (9)^2(9.5-9)=162\pi\ in.^3$

An action movie production team needs glass spheres to hold a green liquid that looks like an explosive. If all of the available 3,392.92 cubic inches of the liquid is to be poured into 30 glass spheres, what should the diameter of each sphere be? Assume that each sphere is filled to the top.

Answers

The volume of a sphere:
$V=(4)/(3) \pi r^3$
r - the radius

3392.92 cubic inches are poured into 30 spheres.
$3392.92=30 * (4)/(3) \pi r^3 \n \n3392.92=40\pi r^3 \ \ \ \ \ \ \ \ \ \ \ \ |/ 40 \n \n84.823=\pi r^3 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |/ \pi \n \nr^3=(84.823)/(\pi) \n \nr=\sqrt[3]{(84.823)/(\pi)} \n \nr \approx \sqrt[3]{27} \n \nr \approx 3$

The diameter is twice the radius.
The diameter of each sphere should be approximately 6 inches.

Answer:

6 inches

Step-by-step explanation:

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Question 11Choose the true statements about transformations. Select all that apply.
A
If the pre-image is dilated, the image will be symmetrical to the pre-image.
B
If the pre-image is translated, the image will be congruent to the pre-image.
C
If the pre-image is reflected across the x-axis or y-axis, the pre-image will be symmetrical to the image, along the line of the axis.
D
If the pre-image is dilated, the image will be similar to the pre-image.
E
If the pre-image is dilated, the image must be congruent to the pre-image.