The probability that Shelly will go to a movie (event A) on Friday is 0.78, and the probability that Danielle will go to a movie (event B) the same day is 0.63. The probability that Shelly will go to a movie, given that Danielle goes to a movie, is 0.87. Which statement is true?
a. Events A and B are independent because P(A|B) ≠ P(A).
b. Events A and B are independent because P(A|B) = P(B).
c. Events A and B are dependent because P(A|B) = P(A) x P(B).
d. Events A and B are dependent because P(A|B) ≠ P(A).
e. Events A and B are dependent because P(A|B) = P(A).

Answers

Answer 1
Answer: The right answer for the question that is being asked and shown above is that: "c. Events A and B are dependent because P(A|B) = P(A) x P(B)."The probability that Shelly will go to a movie, given that Danielle goes to a movie, is 0.87. 
Answer 2
Answer:

Answer:

Events A and B are independent because P(A and B) = P(A) × P(B).

Step-by-step explanation:

plato/edmentum


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Find the coordinates of the midpoint of the segment whose endpoints are H(2, 1) and K(10, 7)

Answers

\bf \textit{middle point of 2 points }\n \quad \n \begin{array}{lllll} &x_1&y_1&x_2&y_2\n % (a,b) H&({{ 2}}\quad ,&{{ 1}})\quad % (c,d) K&({{ 10}}\quad ,&{{ 7}}) \end{array}\qquad % coordinates of midpoint \left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)

you tell us

Answer:

Find the coordinates of the midpoint of the segment whose endpoints are H(2, 1) and K(10, 7).

Step-by-step explanation:

41)533
What is 533 divided by 41 using Partial Quotients?

Answers

Answer:

13

Step-by-step explanation:

533÷41=13 just use a calculator

Final answer:

To divide 533 by 41 using the Partial Quotients method, you first determine how many times 41 goes into 533, which is 10 times, then with the remainder, you repeat the process and find 41 goes 3 times. When you add these partial quotients together, you get the final answer: 13.

Explanation:

The problem here is to divide 533 by 41 using the Partial Quotients method.

The first step is to determine how many times 41 can go into 533 without going over. In this case, it's 10 times, because 10*41 is 410, which is less than 533. So, 10 is part of our answer, and we subtract 410 from 533, which gives us 123.

The next step is to repeat this process with the remainder, 123. 41 can go into 123 three times (since 3*41=123) without going over. So, 3 is another part of our answer. Now, we subtract 123 from 123, which equals 0.

Finally, to get the final answer, we add the partial quotients: 10+3=13. So, 533 divided by 41 using the Partial Quotients method is 13.

Learn more about Partial Quotients here:

brainly.com/question/1893702

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What is the slope between two points 12,6 and 20,22

Answers

The slope of a line between 2 points is given by the formula

m = y2 - y1/x2 - x1

m= 22-6/20-12

m= 16/8= 2

slope is 2
slope is 2 hoe it helped

Point I is on line segment H
J

HJ
. Given
I
J
=
3
x
+
3
,
IJ=3x+3,
H
I
=
3
x

1
,
HI=3x−1, and
H
J
=
3
x
+
8
,
HJ=3x+8, determine the numerical length of
H
J

.
HJ
.

Answers

Answer:

Step-by-step explanation:

the answer is 14

Algebraic ExpressionsWhich of the following sets of ordered pairs represents a function?

{(-2,1),(-1,3),(2,1),(-2,2)}
{(-1,4),(1,4),(2,4),(-2,4)}
{(-1,3),(-1,4),(-1,5),(-1,6)}
{(2,2),(3,3),(4,4),(2,1)}

Use complete sentences to describe the relationship between sets A and B if A is a subset of or is equal to B.
A = {8}
B = {7, 8, 9}

Which of the following properties is a(b · c) = (a · b)c an example of?
associative property
commutative property
multiplicative identity
distributive property

Given: A = {a, e, i, o, u}, B = {a, l, g, e, b, r}, C = {m, y, t, h}, A ∩ C is
m, a, e, i, o, u, t, h
the empty set
i
a, e, i, o, u, y

If G = {(-1, 7),(-8, 2),(0, 0),(6, 6)}, then the range of G is
{(7, -1),(2, -8),(0, 0),(6, 6)}
{-8, -1, 0, 6}
{0, 2, 6, 7}

Given B = {a, l, g, e, b, r} and C = {m, y, t, h}, find B ∪ C.
{}
{a}
{a, b, e, g, h, l, m, r, t, y}

If A ⊂ B and A ∩ B = θ then which of the following can be concluded about the sets A and B?
Set A has more elements in it than set B.
Set A is the set containing zero.
Set A is the empty set.
Both sets A and B are the empty set.

Given A = {a, e, i, o, u} and B = {a, l, g, e, b, r}, find A ∪ B.
{}
{a,e}
{a, b, e, g, i, l, o, r, u}

Which of the following properties is 5(3 + 2) = 15 + 10 an example of?
associative property
commutative property
multiplicative identity
distributive property

Given f(x) = 3x - 1 and g(x)= -x + 6, find f(-2) + g(5).
-6
6
8

List all of the elements of set A if A = {x|x is an integer and -6 ≤ x <0}
{-6, -5, -4, -3, -2, -1, 0}
{-6, -5, -4, -3, -2, -1}
{-5, -4, -3, -2, -1}

Answers

1. (-1,4)(1,4)(-2,4)(2,4) is a function because it has no repeating x values.

2. A is a subset of B because everything in A is in B ?? not sure exactly what u r looking for 

3. a(b*c) = (a*b)c.....associative property

4. the intersection of A and C is { empty set } because they have no letters in common

5. range is all ur y values....so the range of G is { 0,2,6,7 }

6. the union of B and C is { a,b,e,g,i,l,o,r,u }

7. set A is an empty set

8. the union of A and B is { a,b,e,g,i,l,o r,u }

9. 5(3 + 2) = 15 + 10....distributive property

10. f(x) = 3x - 1.......f(-2) = 3(-2) - 1 = -6 - 1 = -7
      g(x) = -x + 6.....g(5) = -5 + 6 = 1
      f(-2) + g(5) = -7 + 1 = -6 <==

11. { -6,-5,-4,-3,-2,-1 }

Civil engineer wants to estimate the maximum number of cars that can safely travel on a particular road at a given speed. He assumes that each car is 14 feet long, travels at speed S, and follows the car in front of it at a safe distance for that speed. He finds that the number N of cars that can pass a given spot per minute is modeled by the function N=(89s)/(14+14(s/17)^2))

At what speed can the greatest number of cars travel safely on that road? Assume that the maximum possible speed of a car is less than 300.

Answers

N(s)= (89s)/(14+14( (s)/(17))^2 )\n\nN'(s)= ((89s)/(14+14( (s)/(17))^2 ) )'= (89* 14(1+( (s)/(17))^2)-89s*  (28)/(17) )/(14^2(1+( (s)/(17))^2)) \n\nN'(s)=0\n\n89* 14(1+( (s)/(17))^2)-89s*  (28)/(17)=0\n\n1+( (s)/(17))^2- (2s)/(17) =0\n\n289+s^2-34s=0\n\ns^2-34s+289=0\n\n(s-17)^2=0\n\ns=17