Answer:
Yes, it is correct
Step-by-step explanation:
Check attachment below:
B.0 = (x – 3)(x – 3)
C.0 = 2.4(x – 2)(x + 2)
D.0 = (x – 2)(x – 1)
Answer:
30 and 21
Step-by-step explanation:
To find the triples of the 3 positive integers (x,y,z) that are products of 24, consider the prime factorization of 24 and distribute these prime factors among x, y and z. Remember to consider permutations.
The student is asking about triples of positive integers (x,y,z) whose product is 24. To find these triples, consider the prime factorization of 24, which is 2^3*3.
Triplet possibilities are created by distributing these prime factors among x, y, and z. For instance, (1,1,24), (1,2,12), (1,3,8), (1,4,6), (2,2,6), and their permutations.
When considering permutations, remember each triple can be ordered in 3! = 6 ways. Making each distinct triple six separate triples. For example, (1,1,24) becomes [(1,1,24), (1,24,1), (24,1,1), (1,24,1), (1,1,24), (24,1,1)]. Repeat this process for all the distinct triples.
To get the total number of triples, count all the distinct permutations. Keep in mind the triple where all numbers are equal, such as (2,2,6), should be counted only once, as its permutations do not produce distinct triples.
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