@HelixBlades
Thank you!!!1
Answers
Part A,
I would assume the triangles are similar so
6y=4y+18
minus 4y both sides
2y=18
divide 2
y=9
Part B
sub for y
6(9)=54
the angle is 54
2nd attachment
4. I actually forgot proofs, let me think
dunno this one
I would say cory is wrong
3rd attachment
5. since 8≠9, it is not a bisector of any sort nor is it equidistant from T and R
answer is point A is not on a bisector
4th attachment
it is not perpendicular in any way
if we assume that TXA=RXA, then the first and last options are right
5th attachment
7.
those 2 triangles are equal because of Side-angle-side
they have to be equal 2x=3x-5
minus 2x both sides
0=x-5
add 5
5=x
x=5
8.
it would be isocelseese
because the 2 sides are equal
Related Questions
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State the next term of each sequencea) 1, 16, 81, 256....b) 1, 1, 2, 4, 7, 13, 24....
A line graph shows the relationship between three variables.a. Trueb. False
How many times larger is 220 than 22
Answers
Answer:
April Beginning Balance $ 1,633,427
Step-by-step explanation:
The closing balance of January is the opening balance of February
February,
Opening Balance $1,234,567
Add Payment received on invoices $825k
Less Cost of sales $198k,
Less Overheads $356k ,
Less Other Expenses $92k .
February Ending Balance $ 1,413, 567
March
Beginning Balance $ 1,413, 567
Add Payment received on invoices $825k *1.12= 924 k
Less Cost of sales $198k *1.09= 215.82k
Less Overheads $356k *1.09= 388.04k
Less Other Expenses $92k *1.09= 100.28k
March Ending Balance = $ 1,633,427
April Beginning Balance $ 1,633,427
Treating the Costs of Sales, Overheads and the other expenses as the expenses paid out of the Bank Balance meaning no accounts payable or other cash paid.
4 ^sqrt 400/ 4^ sqrt 5
Answers
-3x+2y=10
-2x-y=-5
Answers
-3x + 2y = 10
-4x - 2y= -10
And then you minus
x = 20
Now you can substitute x in to one of the equations to find y:
-60 + 2y = 10
+ 60
2y = 70
÷ 2
y = 35
So your values are y = 35 and x = 20. Hope this helps!
Answers
Final answer:
Using the concepts of complementary angles and bisecting angles, we find that Angle KLM measures 60 degrees and Angle MLN measures 30 degrees.
Explanation:
In this problem, we're dealing with complementary angles and bisecting an angle. Complementary angles are two angles whose measures sum to 90 degrees. When an angle is bisected, it is split into two equal smaller angles.
Firstly, as angle KLM and angle MLN are complementary, the sum of their measures equals 90 degrees, so Angle KLM + Angle MLN = 90 degrees.
Secondly, as angle LM is bisecting angle KLM, this means that angle KLM is split into two equal parts. Let's assume each of those parts is x, that means Angle KLM = 2x.
Given that angle KLM and angle MLN are complementary, we can substitute angle KLM = 2x into the equation, leading us to 2x + Angle MLN = 90 degrees. Since angle MLN is also x because it's a part of bisected angle KLM, we can substitute in Angel MLN = x into this equation, ending up with 2x + x = 90 degrees or 3x = 90 degrees. Solving for x, we find that x = 90 / 3 = 30 degrees.
Therefore, the measure of Angle KLM (2x) is 60 degrees and the measure of Angle MLN (x) is 30 degrees.
Learn more about Angle Measures here:
#SPJ2
5x
5x2
6x
6x2
Answers
If you would like to solve (g ° f)(x), you can calculate this using the following steps:
(g ° f)(x) = g(f(x))
(g ° f)(x) = g(f(x)) = g(3x) = 2 * 3x = 6x
The correct result would be 6x.
Answers
quadrilateral-4 sides
1. not a paralellogram
A. trapezoid (1 pair of paralell sides)
2. paralellogram (2 pairs of paralell sides)
A. rectangle-4 right angles
B. rhombus-4 equal sides
C. squaer - 4 equal sides and 4 right angles (both a rhombus and rectangle)
D. kite. 2 pairs of paralell sides that are next to each other (looks like a kite)
5. 4 equal sides, no right angle: rhombus
6. 4 right angles, all sides equal legnth:squaer
7. 1 pair of paralel sides:trapezoid
8. 4 right angles:rectangle
9. if a rectangle has 4 equal sides it is technically a squaer and a rhombus
all squares are recangles and rhombuses, but not all rhombuses and rectangles are squaers
5. rhombus
6. square
7. trapezoid
8. rectangle
9. it is has 4 equal sides, then yes