Answer:
=16 squashes.
Answer:
x = 2 is a zero of f(x)
Step-by-step explanation:
if x = 2 is a zero of f(x) , then f(2) = 0
given
f(x) = - 4x³ + 2x² - 3x + 14 , then
f(2) = - 4(2)³ + 2(2)² - 3(2) + 14
= 16 - 4(8) + 2(4) - 6 + 14
= 16 - 32 + 8 - 6 + 14
= 0
since f(2) = 0 then x = 2 is a zero of f(x)
Using substitution, we can determine whether 2 is a zero of the given function.
To determine whether 2 is a zero of the function f(x)=x^(4)-4x^(3)+2x^(2)-3x+14, we can use substitution. We substitute x = 2 into the function and check if the resulting expression equals zero.
f(2) = (2)^(4)-4(2)^(3)+2(2)^(2)-3(2)+14 = 16-32+8-6+14 = 0
Since the result is zero, we can conclude that 2 is indeed a zero (root) of the function.
#SPJ11
Line
4
has a steeper slope.
Line A
N
Line B
X
-6
4
-2.
2
4
6
-2
4
-6
The steeper line is determined by comparing the slopes of the two lines. The line with the larger slope value is the steeper line. However, the actual slopes of Line A and Line B in the question are not provided.
From the question, it seems like there are two given lines - Line A and Line B but no specific data is provided about their slopes. Therefore, with the information given, we can't determine which line has the steeper slope. Essentially, the steeper line would be the one with the higher slope value when represented in the form: y = mx + c, where 'm' is the slope. For instance, if Line A had an equation of y = 2x +1 and Line B an equation of y = 4x + 1, Line B's slope is steeper because it has a larger 'm' value compared to Line A.
#SPJ2
–10
–9
–8
–7
Answer:
its -7 GG's to all
Step-by-step explanation:
hmm
the question doesn't look clear