What is the best approximation of the solution to the system, to the nearest integer values?( , ) Graph of a System of Linear Equations. Line 1 is x plus 2y equals 10. Line 2 is 2x minus 3y equals negative 9. The lines intersect at about 1.7, 4.1.

x+2y=10 2x-3y=-9

Answers

Answer 1
Answer:

Answer

Solution of the system:

x=2,y=4  or as ordered pair: (2, 4)

Explanation

Remember that the point of intersection of two lines is the solution of the system of linear equations. We know from our graph that our lines intersect at the point (1.7, 4.1), so the solution of our system of linear equations is (1.7, 4.1).

Now, to obtain the nearest integer of a decimal, we focus on the number after the decimal point: if the number is five or bigger than five, we add 1 to our integer; if the number is less than five, we keep the integer as it is.

For 1.7

The number after the decimal point is 7. Since 7 is bigger than 5, we add 1 to our integer, so the nearest integer of 1.7 is 2

For 4.1

The number after the decimal point is 1. Since 1 is less than 5, we keep our integer as it is, so the nearest integer of 4.1 is 4

Answer 2
Answer: 1.7\approx2\n4.1\approx4\n\n(2,4)

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Of the following, which statement or statements accurately represent possible effects of a long-term credit purchase on your credit score?l. Showing a willingness to pay high interest rates increases your score ll. Making only minimum payments for an extended time can hurt your score. Ill. Regularly paying off a credit balance can boost your score. a. I and Ill b. ll only c. ll and I d. l, ll, and III
(-2x) 4O A. – 16x4O B. -8x4O C. -2xtO D. 84O E. 16x4

The relative frequency of green on a spinner is 5/6. How many times would you expect a green in 300 spins?

Answers

5/6*300=250
250 spins

Ex 2.11
20) A curve y''=12x-24 and a stationary point at (1,4). evaluate y when x=2.

Answers

So, dy/dx=0 at the point (1, 4) - that is where x=1 and y=4.

\int { 12x-24dx } \n \n =\frac { 12{ x }^( 2 ) }{ 2 } -24x+C\n \n =6{ x }^( 2 )-24x+C

\n \n \therefore \quad { f }^( ' )\left( x \right) =6{ x }^( 2 )-24x+C

But when x=1, f'(x)=0, therefore:

0=6-24+C\n \n 0=-18+C\n \n \therefore \quad C=18

\n \n \therefore \quad { f }^( ' )\left( x \right) =6{ x }^( 2 )-24x+18

Now:

\int { 6{ x }^( 2 ) } -24x+18dx\n \n =\frac { 6{ x }^( 3 ) }{ 3 } -\frac { 24{ x }^( 2 ) }{ 2 } +18x+C

=2{ x }^( 3 )-12{ x }^( 2 )+18x+C\n \n \therefore \quad f\left( x \right) =2{ x }^( 3 )-12{ x }^( 2 )+18x+C

Now when x=1, y=4:

4=2-12+18+C\n \n 4=8+C\n \n C=4-8\n \n C=-4

\n \n \therefore \quad f\left( x \right) =2{ x }^( 3 )-12{ x }^( 2 )+18x-4

Now when x=2,

f\left( x \right) =2\cdot { 2 }^( 3 )-12\cdot { 2 }^( 2 )+18\cdot 2-4\n \n =16-48+36-4\n \n =0

So when x=2, y=0.
y''=12x-24\ny'=\int 12x-24\, dx\ny'=6x^2-24x+C\n\n0=6\cdot1^2-24\cdot1+C\n0=6-24+C\nC=18\ny'=6x^2-24x+18\n\ny=\int 6x^2-24x+18\, dx\ny=2x^3-12x^2+18x+C\n\n4=2\cdot1^3-12\cdot1^2+18\cdot1+C\n4=2-12+18+C\nC=-4\n\n 2x^3-12x^2+18x-4

y(2)=2\cdot2^3-12\cdot2^2+18\cdot2-4\ny(2)=16-48+36-4\n\boxed{y(2)=0}

Venn diagrams can be used to represent the relationship between two categorical claims but not three. True/ False

Answers

Answer:

False!

Step-by-step explanation:

A Venn diagram can represent the relationship between several categorical claims, not only two. For example: One bubble is labeled "cats only", another is labeled,"dogs only", and the third -- "birds only". The middle section would be "dog and cats and birds".

If the vertices of triangle bcd are b(-3,3), c(3,5), and d(-1,0), what is the perimeter

Answers

distance formlula
D=\sqrt{(x2-x1)^(2)+(y2-y1)^(2)}

when you want to find the distance between points (x1,y1) and (x2,y2)


we nee
distace from
b to c
c to d
d to b


b to c is (-3,3) to (3,5)
D=\sqrt{(3-(-3))^(2)+(5-3)^(2)}=2√10

c to d is (3,5) to (-1,0)
D=\sqrt{(-1-3)^(2)+(0-5)^(2)}=√41

d to b is (-1,0) to (-3,3)
D=\sqrt{(-3-(-1))^(2)+(3-0)^(2)}=√13

add

b to c+c to d+d to b=2√10+√41+√13

perimiter=2√10+√41+√13 units





Solve the equation A = 2LW + 2LH + 2WH for H.a) H = A - 2LW/2L + 2W
b) H = A + 2LW/2L + 2W
c) H = A - 2LW/4LW
d) H = A/2L + 2W - 2LW

Answers

H = A - 2LW / 2 (L+W)

there were 19 ppl on the bus on the journey home there were 23 more ppl on the bus how many ppl are on the bus home

Answers

there were 42 pp rfffffffffffffffffffffffffffffffffff

Answer:

42 ppl

Step-by-step explanation: