PLEASE HELP THIS IS TIMED !!!!!Use the graph of f(x) to explain the relationship between the real zeros of f(x) and its intercept(s).
A. ) f(x) has one real zero at –2 because the graph of the function has an intercept at (0, –2).
B. ) f(x) has two real zeros at –4 and –2 because the graph of the function has intercepts at (–4, 0) and (0, –2).
C. ) f(x) has no real zeros because the graph of the function does not pass through (0, 0).
D. ) f(x) has one real zero at –4 because the graph of the function has an intercept at (–4, 0).
Answers
Answer:
C. ) f(x) has no real zeros because the graph of the function does not pass through (0, 0).
Step-by-step explanation:
According to L'Hospital's Rule, this is true.
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Can someone help please!!!!!
If two angles are both vertical and supplementary, then the angles are
What is the volume of the square pyramid with base edges 10 in. and height 9 in.?
Solve the equation: √x+1 = x-1
Answers
Always use opposite operation with side that contains variable.
Isolate variable.
Divide 4 by 4 to get it by itself.
Now do the same to other side.
Answers
Answer: 30 grams
Step-by-step explanation: (50 mL x x%) = (1000 mL x 0.3%)
x = 6%
6% x 500 mL = 30 grams
Final answer:
The calculation for the amount of sodium chloride (NaCl) in a solution depends on the desired concentration. For instance, to prepare 50 ml of a 1M solution, one would need 2.922 g of NaCl. For a 500 ml stock solution for the same, the measurement would be ten times this, or 29.22 g.
Explanation:
The question pertains to preparing a solution of sodium chloride N(aCl). The given information indicates that we have 5.30 mol NaCl L solution. To provide an accurate answer, it's necessary to know the targeted concentration for the 50 ml solution. However, lacking this data, we can consider an example where we want to prepare a 1M solution.
In such a case, using the concept of molarity (mol/L), we'd first establish how many moles of NaCl are needed. For a 1M solution, we'd need 1 mol of NaCl per liter of solution. Therefore, in order to prepare 50 ml (or 0.05 L), we require 0.05 mol of NaCl.
The given information also states that 1 mol of NaCl weighs 58.44 g. Therefore, we would need (0.05 mol) * (58.44 g/mol) = 2.922 g of NaCl for 50 ml of a 1M solution. Therefore, if preparing 500 ml of a stock solution, we would require 10 times this amount, or 29.22 g of NaCl.
This is a general guide as the specific quantity can vary based on the desired concentration of the 50 ml solution. For other concentrations, we would use the same method, simply adjusting the moles of NaCl needed as appropriate.
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Answers
If the function is f(x) = 3 / (x + 4), a table could be
x f(x)
-8 -3/4
-7 -1
-6 -3/2
-5 -1
(-4 is no a valid input)
- 3 3
- 2 3/2
-1 1
0 3/4
1 3/5
2 3/6 = 1/2
3 3/7
4 3/8
If the function is f(x) = (3/x) + 4
Just substitute different values for x and obtain the respective outputs. In this case, x has to be different of o, i.e. 0 is not a valid input.
The answer is option B in the screenshot.
x y
−3 −15
−2 −8
−1 −1
0 3
1 6
2 10
g(x) = −4 sin(5x) + 3
Answers
The y intercept occurs when x = 0
So for first function y-intercept = 3.
Second function:-
y intercept = -4 sin (5*0) + 3
= -4(0) + 3 = 3
y - intercepts are equal.
Answers
Answer:
The statement is false.
Step-by-step explanation:
For any vector 'r' we have
The magnitude is given by
As we know that the upon squaring a term the result is always positive thus the term in right side of equation i is always positive no matter weather the terms (x,y,z) are positive or negative hence we conclude that magnitude of any vectorial quantity is always positive irrespective of it's direction.
how?
Answers
Answer:
see explanation
Step-by-step explanation:
using the identity
cos²x = 1 - sin²x
consider the left side
multiply numerator/ denominator by (1 + cosx)
= ← expand numerator
=
= ← cancel sinx on numerator/ denominator
=
= right side , thus proven