Maggie's brother is 3 years younger than twice her age the sum of their ages is 24. how old is Maggie?
Answers
For this case, the first thing we must do is define variables.
We have then:
x: Maggie's age
y: Age of Maggie's brother
We write the system of equations that models the problem.
We have then:
We solve the system of equations.
For this, we use substitution:
From here, we clear the value of x:
Answer:
Maggie is 9 years old
Maggie's age is 9
Further Explanation
One variable linear equation is an equation that has a variable and the exponent number is one.
Can be stated in the form:
or
ax + b = c,
where a, b, and c are constants, x is a variable
Whereas the two-variable linear equation is a linear equation that has 2 variables and the exponent is one
Can be stated in the form:
x, y = variable
Let Maggie's age = x
Maggie's brother = y,
In the statement of the task:
- Maggie's brother is 3 years younger than twice her age
we translate this sentence into the equation
y = 2x-3 ... equation 1
- The sum of their ages is 24
we translate this sentence into the equation
x + y = 24 ...equation 2
Both of these equations are equations that have 2 variables, so the solution can be used in 3 ways:
- 1. graph system
the solution is the intersection point of the two equations / lines.
- 2. substitution
the solution is we change one variable into another variable form of an equation, then substitutes that variable in another equation
- 3. elimination
the solution is to eliminate one variable from the equation system.
to determine the variable x we eliminate the variable y first, or vice versa.
We use the second method: substitution
we substitute equation 1 into equation 2 :
So Maggie's age:
Learn more
each of their ages
Three times b less than 100
6 = 4x + 9y solve for y
Keywords: variable, equation, substitution, elimination, graph, Maggie's age
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Answers
Answers
cos a= √(1-sin²a)
= √(1-16/25)
= √(9/25)
= 3/5
sin b=5/13
cos b= √(1-sin²b)
= √(1-25/169)
= √(144/169)
= 12/13
sin(a+b)= sin a· cos b + cos a · sin b
= 4/5· 12/13 + 3/5· 5/13
= 48/65+15/65
= 63/65
hope it helps
Answer:
[A] sin(a + b) =
Answers
Answer (it has two solutions):
- k > 4
- k < -4
I hope this helps!
Answers
The expressionrepresents the number of hours Mrs. Nakos worked during the last week of school. When expression evaluated, it equals 6 hours. So, Mrs. Nakos worked 6 hours that week.
To find the number of hours Mrs. Nakos worked during the last week of school, you can evaluate the expression step by step:
1. Start by evaluating the expression inside the parentheses:
2. Now, you have the expression To calculate this, multiply 12 by
since dividing by 2 is the same as multiplying by
So, Mrs. Nakos worked 6 hours during the last week of school.
The expression represents the number of hours worked, and when evaluated, it equals 6 hours. Therefore, Mrs. Nakos worked 6 hours that week.
For more such questions on evaluating expressions:
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4+8=12
12divide2=6
6times7=42
*for 1\2 you can divide by 2 or multiply by .5
Answers
95 + 92 + 89 + x ≥ 93 * 4 where 4 is the number of data points.
x ≥ 96. Test score should be equal or greater than 96.
4 scores
(95+92+89+x)/4>93
times 4 both sides
276+x>372
minus 276 both sides
x>96
A
Answers
Answer:
Option C is correct
It is a stratified random sample because parents were randomly selected from each group.
Step-by-step explanation:
I'll talk about the different types of sampling.
1) Random Sampling
In random sampling, each parent would have an equal chance of being surveyed. If this particular scenario wanted to use random sampling, they would have used computer generated random numbers for the parents and surveyed them, not just pick random parents equally from two cities.
2) Systematic sampling is easier than random sampling. In systematic sampling, a particular number, n, is counted repeatedly and each of the nth parent is picked to be sampled.
3) Convenience Sampling
This is the worst sampling technique. It is also the easiest. In Convenience sampling, they just survey the first set of parents that they find.
4) Stratified Sampling
Stratified sampling divides the population into groups called strata. A sample is taken from each of these strata using either random, systematic, or convenience sampling.
So, for this question, random sampling is used to pick a sample from the two strata (from the 2 cities). This is why the sampling used in this question is a stratified random sampling technique.
5) Cluster sampling
Cluster Sampling divides the population into groups which are called clusters or blocks (the different cities). The clusters are selected randomly, and every element in the selected clusters is surveyed (each parent in the selected cities, is surveyed!).
Hope this Helps!!!