Answer:
150000(1.22)^t
Step-by-step explanation:
A-150000
R- 0.22 plus the 1 since it’s positive y=A(1+r)
Sooo 150000(1+0.22)^t
The problem asks for a location that is equidistant from towns A and B and lies on the given road. Calculating the midpoint of A and B, we get (5, 1.5). However, this point does not lie on the road denoted by -x + 7y = -4. So, we cannot determine the exact location of the school with the given conditions.
In this problem, the location of the school should be the midpoint of the line between towns A and B as it is equidistant from both towns. First, let's calculate the midpoint (M) coordinates. The formulas for finding the x and y coordinates of the midpoint are (x1 + x2) / 2 and (y1 + y2) / 2 respectively. Using these formulas, we get the coordinates of M as (2+8)/2, (-2+5)/2 = (5, 1.5). However, we should ensure that this point lies on the given road, which is denoted by the equation -x + 7y = -4. Substituting the coordinates of M in the equation, we get -5 + 7*1.5 = -5 + 10.5 = 5.5 which is not equal to -4. So, (5, 1.5) is not a valid location for the school. Unfortunately, with the given conditions, we cannot determine the exact location of the school. Additional information or revision of the conditions might be necessary to solve this problem.
#SPJ3
−2 2
−1 −3
0 2
1 17
Which of the following is a true statement for this function?
(A)The function is increasing from x = −2 to x = −1.
(B)The function is increasing from x = 0 to x = 1.
(C)The function is decreasing from x = −1 to x = 0.
(D)The function is decreasing from x = 0 to x = 1.
Answer:
(B) increasing from x=0 to x=1
Step-by-step explanation:
I took the test
Answer:
P ( 2 R , 4 O , 6 G ) = 0.0261
Step-by-step explanation:
Given:
- Red beans = 8
- Orange beans = 6
- Green beans = 9
Find:
What is the probability of reaching into the bag and randomly withdrawing 12 jellybeans such that the number of red ones is 2, the number of orange ones is 4, and the number of green ones is 6?
Solution:
- The question requires the number of selection of 12 jellybeans we can make from total available such that out of those 12 we choose 2 Red, 4 Orange and 6 Green.
- For selection we will use the combinations. So to choose 2 Red from 8; Choose 4 Orange from 6 and 6 green from 9 available. The number of possible outcomes with such condition is:
Outcomes ( 2 R , 4 O , 6 G ) = 8C2 * 6C4 * 9C6
= 28*15*84
= 35280
- The total number of outcomes if we randomly select 12 beans irrespective how many of each color we select from available 23 we have:
Outcomes ( Select 12 from 23 ) = 23C12
= 1352078
- Hence, the probability for the case is given by:
P ( 2 R , 4 O , 6 G ) = Outcomes ( 2 R , 4 O , 6 G ) / Outcomes ( Select 12 from 23 )
P ( 2 R , 4 O , 6 G ) = 35280 / 1352078 = 0.0261