T=v /6 + 5
a) Work out the value of T when v = 42

Answers

Answer 1
Answer:

The value of T in the equation if v = 42 is 12

How to solve algebra

Given:

T= v /6 + 5

If v = 42, find T

  • substitute 42 for v in the equation

T= v /6 + 5

T = 42/6 + 5

  • solve the fraction first

T = 7 + 5

T = 12

Therefore, the value of T in the equation if v = 42 is 12

Learn more about algebra:

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(Circle one) A negative decimal multiplied by a positive decimal then multiplied again by a negative decimal will give a positive/negative answer.

Answers

Positive

Step-by-step explanation:

A positive and a negative add up to a negative so if you add the sum of the first two then add the negative it will be positive

.

Coopers & Lybrand surveyed 210 chief executives of fast-growing small companies. Only 51% of these executives had a management succession plan in place. A spokesperson for Cooper & Lybrand said that many companies do not worry about management succession unless it is an immediate problem. However, the unexpected exit of a corporate leader can disrupt and unfocus a company for long enough to cause it to lose its momentum. Use the data given to compute a 92% confidence interval to estimate the proportion of all fast-growing small companies that have a management succession plan.

Answers

Answer:

92% Of confidence intervals to estimate the proportion of all fast-growing small companies that have a management succession plan.

(0.46154 , 0.558)

Step-by-step explanation:

Given sample size 'n' = 210

The sample proportion 'p' = 51% = 0.51

Confidence intervals are determined by

(p^(-) - z_(\alpha ) \sqrt{(p^(-) (1-p^(-) )/(n) }  , p^(-) +Z_(\alpha ) \sqrt{(p^(-) (1-p^(-) ))/(n ) } )

The 92% of z-score value

Z_{(\alpha )/(2) } = Z_{(0.08)/(2) } = Z_(0.04) = 1.405

92% Of confidence intervals to estimate the proportion of all fast-growing small companies that have a management succession plan.

(0.51 - 1.405 \sqrt{(0.51 (1-0.51 )/(210) }  , 0.51 +1.405 \sqrt{(0.51 (1-0.51))/(210 ) } )

on calculation , we get

(0.51-0.048 , 0.51 + 0.048)

(0.46154 , 0.558)

Final answer:-

92% Of confidence intervals to estimate the proportion of all fast-growing small companies that have a management succession plan.

(0.46154 , 0.558)

5. What is the value of x if the quadrilateral is a kite? B X+2 C С 13 A Xth12 D​

Answers

Answer: just had this problem! X = 11

PLEASE HELP IF YOU KNOW THIS!!!!!

Answers

Answer:

7cm

Step-by-step explanation:

3cmx3cm=9cm

9cmx3.14=28.26

28.26/197.9=7 (plus a bunch of decimals!)

So 7cm is your height

Answer:

7.50 is the answer so either 7 or 8

Step-by-step explanation:

h= (A/2piR) -r

Plug in the area and the radius and you got the answer. Use 3.14 as pi

PLEASE HELP!The moose population in a New England forest can be modeled by the function y = 60x/ 1 + 0.625x . What is the value of the horizontal asymptote? Describe it's meaning in the context of the problem. 


A) y = 96; The maximum number of moose that the forest can sustain at one time. 
 
B) x = 96; The maximum number of moose that the forest can sustain at one time. 

C) x = -1.6; The minimum number of moose that the forest can sustain at one time. 

D) y = -1.6; The minimum number of moose that the forest can sustain at one time.

Answers

The horizontal asymptote is y = 96 and its the maximum number of moose that the forest can sustain 

Its A

The integral \pi\int\limits^2_1 {(1-(lnx)^(2)) } \, dx represents the volume of a solid obtained by rotating a region around y=-1. Evaluate.

Answers

Answer:

V = π (-2 (ln 2)² + 4 ln 2 − 1)

V ≈ 2.55

Step-by-step explanation:

V = π ∫₁² (1 − (ln x)²) dx

V/π = ∫₁² (1 − (ln x)²) dx

V/π = ∫₁² dx − ∫₁² (ln x)² dx

V/π = x |₁² − ∫₁² (ln x)² dx

V/π = 1 − ∫₁² (ln x)² dx

To evaluate the second integral, integrate by parts.

If u = (ln x)², then du = 2 (ln x) / x dx.

If dv = dx, then v = x.

∫ u dv = uv − ∫ v du

= (ln x)² x − ∫ x (2 (ln x) / x) dx

= x (ln x)² − 2 ∫ ln x dx

Integrate by parts again.

If u = ln x, then du = 1/x dx.

If dv = dx, then v = x.

∫ u dv = uv − ∫ v du

= x ln x − ∫ x (1/x dx)

= x ln x − ∫ dx

= x ln x − x

Substitute:

∫ (ln x)² dx = x (ln x)² − 2 ∫ ln x dx

∫ (ln x)² dx = x (ln x)² − 2 (x ln x − x)

∫ (ln x)² dx = x (ln x)² − 2x ln x + 2x

Substitute again:

V/π = 1 − ∫₁² (ln x)² dx

V/π = 1 − (x (ln x)² − 2x ln x + 2x) |₁²

V/π = 1 + (-x (ln x)² + 2x ln x − 2x) |₁²

V/π = 1 + (-2 (ln 2)² + 4 ln 2 − 4) − (-1 (ln 1)² + 2 ln 1 − 2)

V/π = 1 − 2 (ln 2)² + 4 ln 2 − 4 + 2

V/π = -2 (ln 2)² + 4 ln 2 − 1

V = π (-2 (ln 2)² + 4 ln 2 − 1)

V ≈ 2.55