Chuanxi planned a rectangular sidewalk with a length of 21 ft. He made a scale drawing using a scale factor of 1 in. = 7 ft. He decided to change the length of the actual sidewalk to 27 ft.If the scale drawing still has a length of 3 in., what does 1 in. represent in the new scale in feet?
StartFraction 1 over 9 EndFraction
One-third
4.5
9

Answers

Answer 1
Answer:

The value of the 1 inch on the scale will be 9 ft.

What is an expression?

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that Chuanxi planned a rectangular sidewalk with a length of 21 ft. He made a scale drawing using a scale factor of 1 in. = 7 ft. He decided to change the length of the actual sidewalk to 27 ft.

The value of 1 inch will be calculated as,

Original Ratio of 1 in = 7 ft so 3 in = 21 ft

Now, New ratio 1 in = x ft so 3 in = 27ft

1/x = 3/27

Cross multiply a/b = c/d ad = bc

1/x = 3/27

3x = 27

x = 9

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Answer 2
Answer:

Answer:

Original Ratio of 1 in = 7 ft so 3 in = 21 ft

Now, New ratio 1 in = x ft so 3 in = 27ft

1/x = 3/27

cross multiply a/b = c/d ad = bc

1/x = 3/27

3x = 27

x = 9

1 in represents 9 ft

Step-by-step explanation:


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Paula caught a tarpon with a weight that was 10 times as great as the weight of a permit fish she caught . The total weight of the two fish was 132 pounds. How much did each fish weight?

Answers

x equals weight of permit fish
x + 10X = 132
11x = 132
x= 12

permit fish= 12
tarpon=120

x \rightarrow the \ weight \ of \ permit \ fish \n 10x \rightarrow tarpon \n  \n x+10x=132 \n 11x=132 \n x= (132)/(11)  \n x=12 \n  \n The \ weight \ of \ permit \ fish \ is \ 12. \n The \ weight \ of \ the \ tarpon \ is \ 12 *10=120 \n  \n  \n Checking : 12+120=132

there are 22 roses, 12 daisies, and 16 carnations in a bouquet. what is the ratio of roses to the total number of flowers in the bouquet? How many carnations must be added to the bouquet so that the ratio of daisies to carnations becomes 1:3?

Answers

Given:
Roses:       22
Daisies:     12
Carnation: 16

22 + 12 + 16 = 50 flowers in one bouquet

The ratio of the roses to the total number of flowers in the bouquet is 22/50 or simplified to 11/25

Ratio of daisies to carnations is 12:16 or 3:4. 

Number of carnations to add to make the ratio into 1:3

12:x = 1:3
12*3 = x
36 = x

36 - 16 = 20 additional carnations.

There must be an additional 20 carnations to make the ratio of daisies to carnation 1:3.

12:36 = 1:3

Need help ASAP1) A new truck that sells for $42,000 depreciates 11% each year. write a function that models the value of the truck. Find the value of the truck after 8 years. Round to the nearest dollar.

2) Earl mows lawns one weekend. He earns $15 for each lawn that he mows. He spends $50 on gas and other supplies. What function equation represents Earl's profit from mowing x lawns?

A)f(x)=50x-15
B)f(x)=50x+15
C)f(x)=15x-50
D)f(x)=15+50

3) find the common geometric series.
-2,-4,-8,-16.....

Answers

Answer:

\boxed{1) V = 40 000(0.89)^(n), \text{\$15 746; }\text{2) C) f(x) = 15x - 50 ; 3) }a_(n) = -2^(n)}

Step-by-step explanation:

1) Depreciation

The formula for the value V of an asset after depreciation by an annual percentage rate is  

V = P(1 - r)ⁿ

where

P = present value

r = annual percentage rate

n = number of years

Data:

V = 40 000

r = 11 % = 0.11

n = 8 yr

Calculations:

(a) Function model

V= 40 000(1 - 0.11)ⁿ = 40 000(0.89)ⁿ

The function model is \boxed{ V= 40 000(0.89)^(n) }

(b) Future value

V = 40 000(0.89)ⁿ = 40 000 × 0.393 659 = $15 746

In eight years, the truck will be worth \boxed{ \text{\$15 476}}.

2) Profit function

Income from 1 lawn = $15

  Income from x lawns =  15x

Less gas and supplies =         -50        

                 Net income = 15x – 50

The function is \boxed{f(x) = 15x - 50}.

3) Geometric series

(a) Calculate the common ratio

a₁ = -2

a₂ = -4

a₃ = -8

a₄ = =16

The ratios of consecutive pairs are

a₄/a₃ = -16/(-8)  = 2

a₃/a₂ =   -8/(-4)  = 2

a₂/a₁ =   -4/(-2)  = 2

All adjacent pairs have the same common ratio r = 2.

(b) Write the formula for the series

The formula for the nth term of a geometric series is

aₙ = a₁rⁿ⁻¹

If a₁ = -2, the formula for the series is

aₙ = -2(2)ⁿ⁻¹ = -2ⁿ

The formula for the series is \boxed{a_(n) = -2^(n)}.

A newspaper has more than 30 pages and fewer than 40 pages the newspaper is divided into sections and each section has actually eight pages how many sections does the newspaper have

Answers

4 and a half sections , maybe 5 but it said fewer than 5 soo

Monica is making 2 loaves of banana bread she needs 3/4 cup of sugar for each lot. Her measuring cup can only hold 1/4 cup of sugar. How many times will JESSICA need to fill the measuring cup in irder to get enough sugar for both loaves of bread

Answers

She'll have to fill it up 6 times.

Answer:

3 times

Step-by-step explanation:

Jess needs 3/4 cup of sugar.  Note that 3/4 is the same as 1/4 + 1/4 + 1/4, which in turn is the same as 3(1/4).

Jess will need to fill her 1/4-cup measure 3 times to end up with 3/4 cup of sugar in the banana bread batter.

Mitch lost 10/3
pounds in
5/7 of a week. Which complex fraction when simplified will compute the unit rate of pounds per week?
A)
10/3
5/7
B)
10/3
7/5
C)
3/10
5/7
D)
5/7
10/3

Answers

The answer is A)10/3 over 5/7.

Answer:

Step-by-step explanation:

The answer is A)10/3 over 5/7.