MATHEMATICS COLLEGE

Raj recorded the scores of six of his classmates in the table.Math Scores
98
76
100
88
82
70

What is the range of their test scores?

Answers

Answer 1

Answer: The answer is 30. Range: largest number - smallest number = range

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If you draw a tree to show the number of ways to spin a spinner with three regions twice, how many possibilitdies would there be? There would be possibilities. Enter your answer in the answer box here to search Y W N

Enter the number that belongs in the green box

Answers

Answer:

8

Step-by-step explanation:

8

(12pts) Inequalities please help me !?

Answers

The correct answer would be C, or x > -2.

Because the line is going up from -2, we know that x is going to be greater than 2 for a fact.

We can tell that it wont be greater than or equal to because the circle is clear and not filled.

Thus, C is the correct answer.

What is the distance between the points (-4, 7 ) and (2, 7 )

Answers

Answer:

6.

Step-by-step explanation:

Since the y-value is the same, the two points make a horizontal line. You can think of it as a number line, where the first point is at -4 and the second is at 2. So, the distance between -4 and 2 is 6.

If two objects travel through space along two different curves, it's often important to know whether they will collide. (Will a missile hit its moving target? Will two aircraft collide?) The curves might intersect, but we need to know whether the objects are in the same position at the same time. Suppose the trajectories of two particles are given by the vector functions for t 0. Do the particles collide? If they collide find t. If not enter NONE.r1(t)=r2(t)=<9t-14,t^2,13t-42>t=

Answers

Answer:

The particles collide when t = 7 at the point (49, 49, 49).

Step-by-step explanation:

We know the trajectories of the two particles,

$r_1(t)=\langle t^2,16t-63,t^2\rangle\nr_2(t)=\langle 9t-14,t^2,13t-42\rangle$

To find if the tow particles collide you must:

Equate the x-components for each particle and solve for t

$t^2=9t-14\nt^2-9t+14=0\n\left(t^2-2t\right)+\left(-7t+14\right)=0\nt\left(t-2\right)-7\left(t-2\right)=0\n\left(t-2\right)\left(t-7\right)=0$

The solutions to the quadratic equation are:

$t=2,\:t=7$

Equate the y-components for each particle and solve for t

$16t-63=t^2\n^2-16t+63=0\n\left(t^2-7t\right)+\left(-9t+63\right)=0\nt\left(t-7\right)-9\left(t-7\right)=0\n\left(t-7\right)\left(t-9\right)=0$

The solutions to the quadratic equation are:

$t=7,\:t=9$

Equate the z-components for each particle and solve for t

$t^2=13t-42\nt^2-13t+42=0\n\left(t^2-6t\right)+\left(-7t+42\right)=0\nt\left(t-6\right)-7\left(t-6\right)=0\n\left(t-6\right)\left(t-7\right)=0$

The solutions to the quadratic equation are:

$t=6,\:t=7$

Evaluate the position vectors at the common time. The common solution is when t = 7.

$r_1(7)=\langle 7^2,16(7)-63,7^2\rangle=\langle 49,49,49\rangle\n\nr_2(7)=\langle 9(7)-14,7^2,13(7)-42\rangle=\langle 49,49,49\rangle$

For two particles to collide, they must be at exactly the same coordinates at exactly the same time.

The particles collide when t = 7 at the point (49, 49, 49).

I have an exam for science edexcel pls help what should i revise its physics help plslslslslsl

Answers

~First, which topics that you very weak, revise it

~Don't read in sentence form , read in I-Think form

~Don't feel nervous and just be like normal

Hope it helps!! Good luck for your exam❤️

Help? Question are above. 15 points

Answers

Answer:

1).

7, rational

2).

2.36 (repeating), irrational

3).

$Simplify:(734)/(1000) / (2)/(2) = (367)/(500)$

4).

$Simplify: (2588)/(1000) /(4)/(4) =(647)/(250) \nIf.you.want.to.convert.it.to.a.mixed.fraction: 2(147)/(250)$

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