MATHEMATICS COLLEGE

Data Entry - No Scoring During your procedure to determine the uncalibrated volume near the stopcock of your buret, what was the mass in grams of water that drained out when the meniscus started just above the 25 mL mark and ended just above the stopcock? Report to the thousandth of a gram.

Answers

Answer 1

Answer:

Answer:

0.025 grams

Step-by-step explanation:

The water in the stopcock has a volume of 25 mL initially, After that, the whole water was drained out. So we have:

Volume of drained water = (25 mL)(1 x 10⁻⁶ m³/1 mL)

Volume of drained water = 25 x 10⁻⁶ m³

Density of drained water = 1000 kg/m³

So, for the mass of drained water:

Density of drained water = Mass of drained water/Volume of drained water

Mass of drained water = (Density of drained water)(Volume of drained water)

Mass of drained water = (1000 kg/m³)(25 x 10⁻⁶ m³)

Mass of drained water = 0.025 gram

Density

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A relation includes the coordinate (3,3). What other coordinate must be included in the relation if it is even?

Answers

let's not forget that when a relation is "even" f(-x) = f(x), or namely any negative of "x" yields the same result as any positive one.

if this relation is "even" and has (3 , 3), where x = 3, then if we were to plug f(-3) we should get a result or y-value of the same 3, giving us a point of (-3 , 3).

{2x
x = -6y
12x + 12y = 0
Solve the system of equations.

Answers

Answer:

The solution to the system of equations is:

$x=0,\:y=0$

Step-by-step explanation:

Given the system of equations

2x = -6y

12x + 12y = 0

solving the system of equations by elimination method

$\begin{bmatrix}2x=-6y\n 12x+12y=0\end{bmatrix}$

Arrange equation variables for elimination

$\begin{bmatrix}2x+6y=0\n 12x+12y=0\end{bmatrix}$

Multiply 2x+6y = 0 by 6: 12x+36y=0

$\begin{bmatrix}12x+36y=0\n 12x+12y=0\end{bmatrix}$

subtracting the equations

$12x+12y=0$

$-$

$\underline{12x+36y=0}$

$-24y=0$

solve -24y=0 for y

$-24y=0$

divide both sides by -24

$(-24y)/(-24)=(0)/(-24)$

Simplify

$y=0$

For 12x+36y=0 plug in y = 0

$12x+36y=0$

$12x+36\cdot \:0=0$

$12x+0=0$

$12x=0$

Divide both sides by 12

$(12x)/(12)=(0)/(12)$

Simplify

$x=0$

Therefore, the solution to the system of equations is:

$x=0,\:y=0$

Graph the function f(x) = x^3+2x^2-3

Answers

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