MATHEMATICS COLLEGE

Mikey is typing in the computer lab and typing at 23 words per minute. If he types for 11 minutes, how many words does he type?

Answers

Answer 1

Answer:

Answer:

253

Step-by-step explanation:

23 x 11 = 253

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Write a formula that will compute the final grade for the course, using G to represent the final grade, H to represent the homework average, Q to represent the quiz average, P to represent the project grade, T to represent the test average, and F to represent the final exam grade. Note: Keep in mind how you must write the percentages that show the weighting of each category when doing computations!

Answers

Answer:

To calculate final grade we use the formula:

Final grade = H( the weight of h) + Q( the weight of q) + P (the weight of project) +T (the weight of test) + F(the weight of final exams).

This formula help us to calculate the grade we need to get.

Step-by-step explanation:

Solution:

Suppose grade breakdown for certain college course is as follow:

Homework = 15%

Quizzes = 20%

Project = 10%

Test = 40%

Final exam= 15%

Let G represent the final grade

H represents homework average,

Q represents quizzes and P represent project, T represent test average and F represent final exam.

To calculate final grade we use the formula:

Final grade = H( the weight of h) + Q( the weight of q) + P (the weight of project) +T (the weight of test) + F(the weight of final exams).

This formula help us to calculate the grade we need to get.

Final answer:

The final grade, G, can be computed by adding together the weighted values of the homework average, quiz average, project grade, test average, and final exam grade. This can be represented by the formula G = 0.20*H + 0.20*Q + 0.25*P + 0.15*T + 0.20*F.

Explanation:

To compute the final grade for the course, you will need to multiply each category by its weighting percentage, then add the results together. This can be represented as the following formula:

G = 0.20*H + 0.20*Q + 0.25*P + 0.15*T + 0.20*F

In this formula, G is the final grade, H is the homework average, Q is the quiz average, P is the project grade, T is the test average, and F is the final exam grade. The coefficients (0.20, 0.20, 0.25, 0.15, and 0.20) represent the weighting percentages in decimal form for each respective category.

Learn more about final grade calculation here:

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Three times a number is less than 96.

Answers

Answer:

x is greater than sign then 32

Step-by-step explanation:

Suppose f(x,y)=xy, P=(−4,−4) and v=2i+3j. A. Find the gradient of f. ∇f= i+ j Note: Your answers should be expressions of x and y; e.g. "3x - 4y" B. Find the gradient of f at the point P. (∇f)(P)= i+ j Note: Your answers should be numbers C. Find the directional derivative of f at P in the direction of v. Duf= Note: Your answer should be a number D. Find the maximum rate of change of f at P. Note: Your answer should be a number E. Find the (unit) direction vector in which the maximum rate of change occurs at P. u= i+ j Note: Your answers should be numbers

Answers

Answers:

Gradient of f: $\nabla f = y\hat{i} + x\hat{j}$

Gradient of f at point p: $\nabla f = -4\hat{i} -4\hat{j}$

Directional derivative of f and P in direction of v: $\nabla f(P)v = -20\n$

The maximum rate of change of f at P: $| \nabla f(P)| = 4√(2)$

The (unit) direction vector in which the maximum rate of change occurs at P is: $v = -(1)/(√(2))\hat{i}-(1)/(√(2))\hat{j}$

Step by step solutions:

Given that:

$f(x,y) = xy$

$P = (-4,4)\n$

$v = 2i + 3j$

A: Gradient of f

$\nabla f = ((\partial f)/(\partial x), (\partial f)/(\partial y)) = (y,x) = y\hat{i} + x\hat{j}$

B: Gradient of f at point P:

Just put the coordinates of p in above formula:

$\nabla f = -4\hat{i} -4\hat{j}$

C: The directional derivative of f and P in direction of v:

The directional derivative is found by dot product of $\nabla f(P) \: \rm and \: \rm v$ :

$\nabla f(P)v = [-4,4][2,3]^T = -20\n$

D: The maximum rate of change of f at P is calculated by evaluating the magnitude of gradient vector at P:

$| \nabla f(P)| = √((-4)^2 + (-4)^2) = 4√(2)$

E: The (unit) direction vector in which the maximum rate of change occurs at P is:

$v = ((-4)/(4√(2)), (-4)/(4√(2))) = -(1)/(√(2))\hat{i}-(1)/(√(2))\hat{j}$

That vector v is the needed unit vector in this case.

we divided by $4√(2)$ to make that vector as of unit length.

Learn more about vectors here:

brainly.com/question/12969462

Answer:

a) The gradient of a function is the vector of partial derivatives. Then

$\nabla f=((\partial f)/(\partial x), (\partial f)/(\partial y))=(y,x)=y\hat{i} + x\hat{j}$

b) It's enough evaluate P in the gradient.

$\nabla f(P)=(-4,-4)=-4\hat{i} - 4 \hat{j}$

c) The directional derivative of f at P in direction of V is the dot produtc of $\nabla f(P)$ and v.

$\nabla f(P) v=(-4,-4)\left[\begin{array}{ccc}2\n3\end{array}\right] =(-4)2+(-4)3=-20$

d) The maximum rate of change of f at P is the magnitude of the gradient vector at P.

$||\nabla f(P)||=√((-4)^2+(-4)^2)=√(32)=4√(2)$

e) The maximum rate of change occurs in the direction of the gradient. Then

$v=(1)/(4√(2))(-4,-4)=((-1)/(√(2)),(-1)/(√(2)))= (-1)/(√(2))\hat{i}-(1)/(√(2))\hat{j}$

is the direction vector in which the maximum rate of change occurs at P.

PLEASE HELP!! ASAP NOWWWW Two races that a student runs every year are the 1492-mile race in his hometown and the -meter race in his college town. Complete parts (a) through (d) below.

Answers

Answer:

College town race is 31% of the home town race.

Step-by-step explanation:

Length of hometown race = 3 miles

Length of college town race = 1492 meters

Since 1 meter = 0.0006214 miles

Therefore, 1492 = 0.93 miles

Percentage of college town race to the hometown race,

= $\frac{\text{College town race}}{\text{Home town race}}* 100$

= $(0.93)/(3)* 100$

= 31%

Therefore, the college town race is 31% of the home town race.

The college town race is approximately 46.31% of the hometown race in length.

First, let's convert both race distances to a common unit of measurement. We'll convert the 2-mile hometown race to meters since the college town race is already in meters.

1 mile is approximately equal to 1609.34 meters. So, the 2-mile hometown race is:

2 miles * 1609.34 meters/mile = 3218.68 meters

Now, we can calculate the length ratio between the college town race and the hometown race:

College Town Race Length: 1492 meters

Hometown Race Length: 3218.68 meters

To find the percentage of the college town race length compared to the hometown race length, we can use the following formula:

(Length of College Town Race / Length of Hometown Race) * 100

(1492 meters / 3218.68 meters) * 100 ≈ 46.31%

So, the college town race is approximately 46.31% of the length of the hometown race.

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A coin is tossed and a fourth section spinner is spun once a tree diagram shows the possible outcomes for the two events what is the probability of flipping tails on a coin and spinning a two on the spinner

Answers

Answer:

2/6 or 1/3 I think

Step-by-step explanation:

you have a 1 out of 2 chances to land tails and 1 out of 4 chance to role a 2 on the spinner. so in total there is 6 chances for rolling and flipping the coin. and there is only 1 chance for both in the odds.

therefore I believe that its is 1/3 or 2/6. I do not know if I am right exactly but that is my thought process.

Хf(x)
What is the initial value of the exponential function
represented by the table?
-2
1
8
e
8
-1
1
4
0
1
2
1
1
1
2
2
2

Answers

Answer:

the answer will be table -1

Step-by-step explanation:

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