Answer:
D or A
Step-by-step explanation:
if this helps may i have brain pls
Answer:
The answer is
Step-by-step explanation:
Given,
Hence the result.
Answer:
x = -4
x = -6
Step-by-step explanation:
X^2+10x+24=0
(b/2)^2 = (10/2)^2 = 25
X^2+10x+25=-24+25
(x+5)^2 = 1
(x+5) = ± 1
x = +1 -5 = -4
x = -1 -5 = -6
Answer:
11
Step-by-step explanation:
Let x be your number
Is means equals
2x = 29-7
2x= 22
2x/2 = 22/2
x =11
Answer:
11
Step-by-step explanation:
11*2=22
29-7 =22
To find out how many minutes it will take Shanika to run 13 miles, we can set up a proportion using the given information. Shanika can run 5 miles in 30 minutes, so we can use this ratio to find the missing value. The answer is 78 minutes.
To find out how many minutes it will take Shanika to run 13 miles, we can set up a proportion using the given information.
We know that Shanika can run 5 miles in 30 minutes, so we can set up the proportion:
5 miles / 30 minutes = 13 miles / x minutes.
To solve for x, we can cross multiply and divide.
Cross multiplying gives us 5x = 13 * 30.
Dividing both sides by 5 gives us x = (13 * 30) / 5. Simplifying this further gives us x = 78 minutes.
#SPJ2
Answer: 78
Step-by-step explanation: multiply 13 x 30 which gives you 390 then divide that by 5 giving you 78 minutes.
Answer:
The box which minimizes the cost of materials has a square base of side length 4.45cm and a height of 2.22 cm.
Step-by-step explanation:
Volume of the jewellery box=44cm³
The box has a square base and is to be built with silver plated sides and nickel plated top and base.
Therefore: Volume = Square Base Area X Height = l²h
l²h=44
h=44/l²
Total Surface Area of a Cuboid =2(lb+lh+bh)
Since we have a square base
Total Surface Area =2(l²+lh+lh)
The Total Surface Area of the box =2l²+4lh
Nickel plating costs $1 per cm³
Silver Plating costs $2 per cm³
Since the sides are to be silver plated and the top and bottom nickel plated:
Therefore, Cost of the Material for the jewellery box =1(2l²)+2(4lh)
Cost, C(l,h)=$(2l²+8lh)
Recall earlier that we derived:
h=44/l²
Substituting into the formula for the Total Cost
Cost, C(l)=2l²+8l(44/l²)
C=2l²+352/l
C=(2l³+352)/l
The minimum costs for the material occurs at the point where the derivative equals zero.
C'=(4l³-352)/l²
4l³-352=0
4l³=352
Divide both sides by 4
l³=88
l=4.45cm
Recall:
h=44/l²=44/4.45²=2.22cm
The box which minimizes the cost of materials has a square base of side length 4.45cm and a height of 2.22 cm.