MATHEMATICS COLLEGE

Which statement is true about the ordered pair (5 , 2)? A. To plot the ordered pair (5 , 2), travel two units to the right on the x-axis and five units up on the y-axis, from the origin. B. To plot the ordered pair (5 , 2), travel five units to the right on the x-axis and two units up on the y-axis, from the origin. C. To plot the ordered pair (5 , 2), travel five units to the right on the y-axis and two units up on the x-axis, from the origin. D. To plot the ordered pair (5 , 2), travel two units to the right on the y-axis and two units up on the x-axis, from the origin.

Answers

Answer 1
Answer:

Answer:

b

Step-by-step explanation:

you can tell because it cant be D or C because you cant go right on the y axis and up on the x axis. it cant be A because 5 is the x and 2 is the y. A says that 5 is the y and 2 is the x. so it has to be B.
Answer 2
Answer:

Answer:

B

Step-by-step explanation:

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2(x + 25) =100 hellppppppp meee
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Sam wants to meet his friend Beth at a restaurant before they go to the theater.The restaurant is 9km south of the theater.

Answers

Okay now I know its 9km from the theater, but what is the question? Or what ties to this?

Answer:


Step-by-step explanation:

Find the marking point for both Sam and Beth and u got ur answer

Find the zeros of f(x) =x^3+2x^2-3x

Answers

Answer: 0, 1, -3

Step-by-step explanation:

f(x) = x^3 +2x^2 -3x

f(x) = x(x^2 +2x-3)

f(x) = x(x-1)(x+3)

to find zeroes, plug into f(x) and solve for each value of x. doing this gives 0, 1, and -3

Which table represents the statement “An airplane is flying at a speed of 525 miles per hour “?

Answers

Answer: B

Step-by-step explanation:

I got it right

Answer:

The correct answer is B. d = 525h

Convert 2 2/3 into an improper fraction​

Answers

Answer: 8/3

Step-by-step explanation:

Pleeease open the image and hellllp me

Answers

1. Rewrite the expression in terms of logarithms:

y=x^x=e^(\ln x^x)=e^(x\ln x)

Then differentiate with the chain rule (I'll use prime notation to save space; that is, the derivative of y is denoted y' )

y'=e^(x\ln x)(x\ln x)'=x^x(x\ln x)'

y'=x^x(x'\ln x+x(\ln x)')

y'=x^x\left(\ln x+\frac xx\right)

y'=x^x(\ln x+1)

2. Chain rule:

y=\ln(\csc(3x))

y'=\frac1{\csc(3x)}(\csc(3x))'

y'=\sin(3x)\left(-\cot^2(3x)(3x)'\right)

y'=-3\sin(3x)\cot^2(3x)

Since \cot x=(\cos x)/(\sin x), we can cancel one factor of sine:

y'=-3(\cos^2(3x))/(\sin(3x))=-3\cos(3x)\cot(3x)

3. Chain rule:

y=e^{e^(\sin x)}

y'=e^{e^(\sin x)}\left(e^(\sin x)\right)'

y'=e^{e^(\sin x)}e^(\sin x)(\sin x)'

y'=e^{e^(\sin x)+\sin x}\cos x

4. If you're like me and don't remember the rule for differentiating logarithms of bases not equal to e, you can use the change-of-base formula first:

\log_2x=(\ln x)/(\ln2)

Then

(\log_2x)'=\left((\ln x)/(\ln 2)\right)'=\frac1{\ln 2}

So we have

y=\cos^2(\log_2x)

y'=2\cos(\log_2x)\left(\cos(\log_2x)\right)'

y'=2\cos(\log_2x)(-\sin(\log_2x))(\log_2x)'

y'=-\frac2{\ln2}\cos(\log_2x)\sin(\log_2x)

and we can use the double angle identity and logarithm properties to condense this result:

y'=-\frac1{\ln2}\sin(2\log_2x)=-\frac1{\ln2}\sin(\log_2x^2)

5. Differentiate both sides:

\left(x^2-y^2+\sin x\,e^y+\ln y\,x\right)'=0'

2x-2yy'+\cos x\,e^y+\sin x\,e^yy'+\frac{xy'}y+\ln y=0

-\left(2y-\sin x\,e^y-\frac xy\right)y'=-\left(2x+\cos x\,e^y+\ln y\right)

y'=(2x+\cos x\,e^y\ln y)/(2y-\sin x\,e^y-\frac xy)

y'=(2xy+\cos x\,ye^y\ln y)/(2y^2-\sin x\,ye^y-x)

6. Same as with (5):

\left(\sin(x^2+\tan y)+e^(x^3\sec y)+2x-y+2\right)'=0'

\cos(x^2+\tan y)(x^2+\tan y)'+e^(x^3\sec y)(x^3\sec y)'+2-y'=0

\cos(x^2+\tan y)(2x+\sec^2y y')+e^(x^3\sec y)(3x^2\sec y+x^3\sec y\tan y\,y')+2-y'=0

\cos(x^2+\tan y)(2x+\sec^2y y')+e^(x^3\sec y)(3x^2\sec y+x^3\sec y\tan y\,y')+2-y'=0

\left(\cos(x^2+\tan y)\sec^2y+x^3\sec y\tan y\,e^(x^3\sec y)-1\right)y'=-\left(2x\cos(x^2+\tan y)+3x^2\sec y\,e^(x^3\sec y)+2\right)

y'=-(2x\cos(x^2+\tan y)+3x^2\sec y\,e^(x^3\sec y)+2)/(\cos(x^2+\tan y)\sec^2y+x^3\sec y\tan y\,e^(x^3\sec y)-1)

7. Looks like

y=x^2-e^(2x)

Compute the second derivative:

y'=2x-2e^(2x)

y''=2-4e^(2x)

Set this equal to 0 and solve for x :

2-4e^(2x)=0

4e^(2x)=2

e^(2x)=\frac12

2x=\ln\frac12=-\ln2

x=-\frac{\ln2}2

If 2/3x+1/2y=5 what is the value of 4x+3y

Answers

Final answer:

To find the value of 4x + 3y, the given equation can be solved by clearing the fractions and simplifying the expression. The value of 4x + 3y is 30.

Explanation:

To find the value of 4x + 3y, we need to first solve the given equation for either x or y. Let's solve the equation for x:

2/3x + 1/2y = 5

Multiplying both sides of the equation by 6 to clear the fractions gives us:

4x + 3y = 30

Therefore, the value of 4x + 3y is 30.

Learn more about Solving Equations here:

brainly.com/question/18322830

#SPJ11
Slope=
2.000
2.667
​
=1.333
x−intercept=
4
30
​
=
2
15
​
=7.50000
y−intercept=
−3
30
​
=
−1
10
​
=−10.00000
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