Answer:
Step-by-step explanation:
See attachment.
all real numbers greater than or equal to 1
all real numbers less than or equal to 5
all real numbers less than or equal to 1
all real numbers
Answer:
"all real numbers"
Step-by-step explanation:
The domain is the set of x-values for which the function is defined.
Domain is also the input of the function (graph).
The graph shown has arrows in both directions. It means that the graph goes on in both directions. If we were to think correctly, we would say the graph would go on-and-on in both +ve x and -ve x directions. So there would be values of x for all real numbers (going to infinity and negative infinity)
Hence, the domain is all real number, the last answer choice is right.
Line through (5, -6)
Answer:
y = -2x + 4
Step-by-step explanation:
We are given that a line has a slope (m) of -2 and passes through (5, -6).
We want to write the equation of the line.
There are three ways to write the equation of the line:
Any of these forms will work, however let's put it into slope-intercept form as that is the most common way.
As we are already given the slope, we can immediately plug that into the equation.
Substitute m with -2.
y = -2x + b
Now, we need to solve for b.
As the equation passes through (5, -6), we can use its values to help solve for b.
Substitute 5 as x and -6 as y.
-6 = -2(5) + b
Multiply.
-6 = -10 + b
Add 10 to both sides.
4 = b
Substitute 4 as b.
y = -2x + 4
every dog
pet store
there are 3 cats at the pet store. What's the ratio?
Answer:
1/3?
Step-by-step explanation:
AC =
BD =
Please help!
Answer:
AC=BD
3(x-5)=x+11
3x-15 = x+11
2x=26
x= 13
AC= 3(13 -5)= 24
BD= 13+11 = 24
Step-by-step explanation:
Answer:
y=20x+25, this equation is linear, the rate of change is constant
Step-by-step explanation:
She starts with 25$, that doesn't change so its our constant. Let x represent each week. Each week she ears 20$
So, let y represent the total amount of money she has
y=20x+25, this equation is linear, the rate of change is constant
This question is incomplete, the complete question is;
find the critical points and classify them as local maxima, local minima, saddle points, or none of these.
f(x,y) = (x + y)(xy + 1)
Answer:
(x,y) = (-1, 1), (1, -1) area critical points
f(xx) =2y, fyy =2x,f(xy) =2x + 2y, D = f(xx)fyy - f(xy²)
at (-1, 1)
f(xx) = 2 ,fyy =-2,f(xy) = 0, D = -4 < 0 saddle point
at (1, -1)
f(xx) = -2, fyy =2,f(xy) =0, D = -4 < 0 saddle point
Step-by-step explanation:
Given that;
f(x,y) = (x + y)(xy + 1)
f(x,y) =x²y + xy² + x + y
for critical points fx =0 ,fy =0
fx = 2xy + y² + 1 = 0, fy = x² + 2xy + 1 = 0
2xy + y² + 1 = 0, x²+ 2xy + 1 = 0
2xy + y² + 1 - x² - 2xy - 1 = 0
x² = y²
=> x = y, x = -y
2xy + y² + 1 = 0, x = y
2yy + y² + 1 = 0
3y² = -1 , no solution
2xy + y² + 1 = 0, x = -y
-2yy + y² + 1 = 0
=> -y2 + 1 = 0
=> y = -1, y = 1
y = -1 => x = 1, y = 1 => x = -1
(x,y) = (-1, 1), (1, -1) area critical points
f(xx) =2y, fyy =2x,f(xy) =2x + 2y, D = f(xx)fyy - f(xy²)
at (-1, 1)
f(xx) = 2 ,fyy =-2,f(xy) = 0, D = -4 < 0 saddle point
at (1, -1)
f(xx) = -2, fyy =2,f(xy) =0, D = -4 < 0 saddle point