The boiling point will be lowered.
The boiling point will be unaffected.
None of the above.
2.00 g of PbCl2 at 80°C
100.2 g of NaNO3 at 60°C
128 g of KI at 0°C
75.5 g of LiCl at 20°C
8.22 g of Ba(OH)2 at 40°C
Answer:
1) unsaturated
2) unsaturated
3) saturated
4) unsaturated
5) saturated
Explanation:
A solution with solute that dissolves until it is unable to dissolve anymore, leaving the undissolved substances at the bottom., is called saturated. Each solution has a certain amount of mass that can dissolve at certain temperature.
A solution with less solute than the saturated solution, that completely dissolves, leaving no remaining substances., is called unsaturated.
A solution ,with more solute than the saturated solution, that contains more undissolved solute than the saturated solution, is called oversaturated.
A) 2.00 g of PbCl2 at 80°C
⇒ At 80 °C this solution is saturated when there is 2.54 grams of PbCl2 in solution
2.00 < 2.54 This solution is unsaturated
B) 100.2 g of NaNO3 at 60°C
⇒ At 60 °C this solution is saturated when there is 122 grams of NaNO3 in solution
100.2 < 122
This solution is unsaturated
C) 128 g of KI at 0°C
⇒ At 0 °C this solution is saturated when there is 128 grams of KI in solution
This solution is saturated
D) 75.5 g of LiCl at 20°C
⇒ At 20 °C this solution is saturated when there is 83.5 grams of LiCl3 in solution
75.5 < 83.5
This solution is unsaturated
E) 8.22 g of Ba(OH)2 at 40°C
⇒ At 40 °C this solution is saturated when there is 8.22 grams of Ba(OH)2 in solution
This solution is saturated
B. convection
C. conduction
D. vaporization
A. In liters of water per moles of a dissolved substance
B. In liters of water per gram of a dissolved substance
O
C. In moles of a substance for 1 g of that substance
D. In moles of a substance dissolved in 1 L of water
Answer:
D. In moles of a substance dissolved in 1 L of water
Explanation:
Just took the test
Molarity is measured in moles of a substance dissolved in 1 L of water.
The molarity is measured in moles of a substance dissolved in 1 liter of water, so the correct option is D. In moles of a substance dissolved in 1 L of water. Molarity is a measure of the concentration of a solute in a solution. It is calculated by dividing the number of moles of solute by the volume of the solution in liters.
Molarity (M) is indeed a measure of the concentration of a solute in a solution and is defined as the number of moles of solute per liter of solution. This means it is measured in "moles of a substance dissolved in 1 liter of solution" or simply "moles/L" or "mol/L." Molarity is a fundamental concept in chemistry and is widely used in various chemical calculations and experiments to express the concentration of a substance in a solution.
#SPJ3
Answer: a)
b) 92.1 g
Explanation:
To calculate the moles, we use the equation:
a) moles of
b) moles of
According to stoichiometry :
1 mole of require 2 moles of
Thus 1.173 require= of
Thus is the limiting reagent as it limits the formation of product. Thus will run out first.
is the excess reagent as (3.500-2.346)= 1.154 moles are left unreacted.
2 moles of require 1 mole of
3.500 moles of require= of
Moles of required = (1.750-1.173) = 0.577
Mass of
Thus he should order 92.1 g of the limiting reactant.
Answer:
92.41g
Explanation: