Answer : The incorrect option is, Condensation occurs at .
Explanation :
Absolute zero on Kelvin scale is .
This statement is correct because at the temperature in degree Celsius will be,
Liquefaction of the gas occurs at approximately .
This statement is correct. From the given graph the liquification of gas occurs at .
The gas follows a linear relationship between volume and temperature.
This statement is correct. According to the Charles law, the volume of gas is directly proportional to the temperature of the gas. So, gas follow the linear relationship between the volume and temperature.
Condensation occurs at .
This statement is incorrect because condensation occurs at . and the condensation is a process in which the phase changes from the gaseous state to liquid state at constant temperature.
As we know that condensation is a reverse process of vaporization. Both the process occurs at constant temperature .
Hence, the incorrect option is, Condensation occurs at .
NaCl
H2S
C2H4
If we have 3.50 moles of hydrogen and 5.00 moles of nitrogen to produce ammonia, 39.66g ammonia is produced.
Avogadro's number is the number of units in one mole of any substance and equals to 6.02214076 × 10²³. The units can be electrons, atoms, ions, or molecules.
No. of moles is defined as a particular no. of particles that we can calculate with the help of Avogadro’s number.
Mass of a particular product is also find out by stoichiometry of a reaction as per the no. of mole given in the reaction.
Given,
3H₂ + N₂ --> 2NH₃
3.50 moles of hydrogen
5.00 moles of nitrogen
Limiting reagent for the reaction is H₂.
3 moles of H₂ produce 2 moles NH₃
1 moles of H₂ produce 2/3 moles NH₃.
3.5 moles of H₂ produce (2÷3)×3.5 moles NH₃ = 2.33 moles
1 mole of NH₃ = 17g of NH₃
2.33 mole of NH₃ = 39.66g of NH₃
Therefore, If we have 3.50 moles of hydrogen and 5.00 moles of nitrogen to produce ammonia, 39.66g ammonia is produced.
Learn more about mole concept, here:
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B. vitamin
c.
C. energy.
D. boron.
Answer: 2.93 L
Explanation:
AI-generated answer
To find the volume occupied by 0.108 mol of helium gas at a pressure of 0.909 atm and a temperature of 306 K, we can use the ideal gas law equation:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
Rearranging the equation to solve for V:
V = (nRT) / P
Plugging in the given values:
n = 0.108 mol
R = 0.0821 L·atm/(mol·K) (the ideal gas constant)
T = 306 K
P = 0.909 atm
V = (0.108 mol * 0.0821 L·atm/(mol·K) * 306 K) / 0.909 atm
Calculating this expression, we find that the volume occupied by 0.108 mol of helium gas at a pressure of 0.909 atm and a temperature of 306 K is approximately 2.93 L.
Now, let's consider the second part of the question: Would the volume be different if the gas was argon (under the same conditions)?
The volume would be the same for argon gas.
According to the ideal gas law, at the same temperature, pressure, and number of moles, the volume occupied by a gas is the same regardless of the gas's identity. Therefore, if we replaced helium gas with argon gas while keeping the same conditions of pressure, temperature, and number of moles, the volume occupied by argon gas would be the same, approximately 2.93 L.
B) C8H8
C) C10H12
D) C6H6
E) none of these
i got C8H8 because i did
MWEF=n
but it says the answer should be C2H4
how is that possible?