we know that
If two lines are perpendicular then, the product of their slopes is equal to minus one, that means that their slopes are negative reciprocals
so
Step
Find the slope of the line HJ
we know that
the slope between two points is equal to
substitute the values
Step
Find the slope of the line HJ
we know that
the slope between two points is equal to
substitute the values
Step
Verify if the two lines are perpendicular
Find the product m1 by m2
so
--------> the slopes are not negative reciprocals
therefore
the answer is the option
D.They are not perpendicular because their slopes are not negative reciprocals
Answer:
x is the variable that's representing a number so -7 would not become posting
Please help me with with this science question
How does potassium dihydrogen phosphate affect soil, water, and air?
Step-by-step explanation:
Let be the probability of winning.
Let be the probability of loosing.
Given that we win once in thousand times.
So,
Since
Since we win noting if we loose,
expected payoff is product of probability of winning and the prize.
Let be the prize.
Given,
Expected payoff is
So,$ is the expected payoff each time.
Answer:
$0.4
Step-by-step explanation:
Answer: Scalene, Right Triangle
Step-by-step explanation:
There are three main terms that describe triangles by their side length: equilateral (all three sides are the same length), isosceles (two sides are the same length), scalene (all three sides are different lengths).
Since all of the sides are different lengths, this is a scalene triangle.
There are three main terms that describe triangles by their angles: acute triangle (all three angles are acute), obtuse triangles (one obtuse angle and two acute angles) and right triangles (on right angle, which means the other two will be acute).
Since this triangle has a right angle (indicated by the square symbol on angle A), it must be a right triangle.
Answer:
Right angle triangle
Step-by-step explanation:
b. Find the co-ordinates of the midpoint of AB.
Please answer fast
a. ((x2-x1)^2 + (y2-y1)^2)^(1/2)
(-4-8)^2 + (1-5)^2 144+16= 160
160^(1/2)= 12.64
b. (8-4)/2 & (5+1)/2
4/2=2 6/2=3
(2,3) is the midpoint of AB