Answer: 25 students per teacher and 12 students per tutor. They need 2.4 tutors for the school
Answer:
Step-by-step explanation:
We are given that ∠FEA is supplementary to ∠HGD
Supplementary angles : Sum of pair of angles is 180°
⇒∠FEA +∠HGD = 180° -- 1
In figure 1 :
∠FEA +∠FEB= 180° (linear pairs) --2
Since ∠HGD is supplement to ∠FEA So, ∠FEB cannot be supplement to ∠HGD (refer figure)
So, A is false
Subtract 1 from 2
⇒∠FEA +∠FEB - ∠FEA +∠HGD = 180° - 180°
⇒∠FEB =∠HGD
So, B is true : ∠HGD≅∠FEB
Now In figure 2 :
∠HGC +∠HGD= 180° (linear pairs) --3
By part B
∠HGC +∠FEB= 180°
So, part C is true
Now subtract 3 from 1 :
⇒∠FEA +∠HGD -∠HGC-∠HGD = 180° -180°
⇒∠FEA =∠HGC
So, part D is true :∠FEA≅∠HGC
Answer:
Step-by-step explanation:
The volume of a right circular cone is given by the formula,
where is the height of the cone.
We can deduce the radius from the circumference of the cone.
It was given that the circumference is 8.3 in.
The volume of the cone now becomes;
The volume of the cone to the nearest tenth is 35.4 cubic inches to the nearest tenth.
By calculating the radius from the given circumference, we can find the volume of a right circular cone with the height of 19.4 inches and a base with a circumference of 8.3 inches to be 33.3 cubic inches.
To calculate the volume of a right circular cone, we need to know the radius, r, and the height, h.
The formula to find the volume, V, of a cone is V = 1/3*π*r²*h.
Given that the height, h, is 19.4 inches, we need to find the radius.
Since the given circumference, C, is 8.3 inches and the formula for circumference is 2*π*r, we can calculate the radius. Solving 8.3 inches = 2*π*r for r gives us r≈1.3 inches.
Then, inserting the values of r and h in the volume formula gives V = 1/3*π*(1.3)²*19.4≈ 33.3 cubic inches.
Rounding to the nearest tenth gives the volume as approximately 33.3 in³.
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Answer:
77
Step-by-step explanation:
Betty has $17 and Ann has $43.
This problem is a basic algebraic equation. Let's denote Betty's amount as x. From the problem information, we know that Ann's amount is twice Betty's plus $9, so we can denote it as 2x + $9. It's also told in the problem that together they have $60, so we can form the equation: x (Betty's money) + 2x + $9 (Ann's money) = $60.
Solving this equation, we combine like terms, which gives us 3x + $9 = $60. Subtract $9 from both sides to get 3x = $51. Divide each side by 3, we get x = $17. So, Betty has $17. We substitute x = $17 into the equation 2x + $9 to find Ann's money, which gives us 2*$17 + $9 = $43. So, Ann has $43.
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