MATHEMATICS HIGH SCHOOL

For the function f(x) = 3(x − 1)2 + 2, identify the vertex, domain, and range.The vertex is (1, 2), the domain is all real numbers, and the range is y ≥ 2.
The vertex is (1, 2), the domain is all real numbers, and the range is y ≤ 2.
The vertex is (–1, 2), the domain is all real numbers, and the range is y ≥ 2.
The vertex is (–1, 2), the domain is all real numbers, and the range is y ≤ 2.

Answers

Answer 1
Answer: f(x)=3(x-1)^2+2\ It's\ a\ quadratic\ function\n\ntherefore\ Domain:\boxed{D:x\in\mathbb{R}\ all\ real\ numbers}\n\nvertex:\nthe\ vertex\ form:\ y=a(x-h)^2+k\nwhere\ (h;\ k)h\ and\ k\ are\ the\ x\ and\ y\ coordinates\ of\ the\ vertex\n\boxed{vertex:(1;\ 2)}
range:\na=3 \ \textgreater \ 0\ therefore\ the\ parabola\ ope ns\ upward\nso\nrange\ is\ [vertex\ (y);\ infinity)\nrange:\boxed{y\geq2\y\in[2;\ \infty)}\n\nYour\ answer:\n\boxed{The\ vertex\ (1;\ 2);\ domain\ is\ all\ real\ number\ (x\in\mathbb{R});\ range\ y\geq2}
Answer 2
Answer: f(x)=3(x-1)^(2)+2 \n \n f(x)=a(x-p)^(2)+q \n \n W=(p,q) \n \n W=(1,2) \n \n D: x \in R \n \n a \ \textgreater \ 0 \n \n Range: y \in [2,+\infty)

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Pls help with number 16...

Answers

a. Area of a square= side length squared
=> A= (x-3)^2
= x^2-6x+9
b. Area of rectangle= larger side length* smaller side length
=> A= x(x-5)
= x^2-5x
c. If both areas equal then expressions for areas equal as well.
x^2-5x= x^2-6x+9
=>x=9

Solve for m in the following equation:
x= 3k(n + m)

Answers

The correct answer is m=x/3k-n

If o is in the middle of l t, where exactly is it located? If l t =16 cm, what is l o and o t

Answers

Answer:

LO = OT = 8cm

Step-by-step explanation:

Given

LT = 16cm

Required

Determine LO and OT

First, we have:

LO + OT = LT

From the question, we understand that O is the middle of LT

This implies that LO = OT

Substitute OT for LO in the above formula

OT + OT = LT

2OT = LT

Divide both sides by 2

OT = (1)/(2)LT

Substitute 16cm for LT

OT = (1)/(2) * 16cm

OT = 8cm

Recall that LO = OT

So;

LO = OT = 8cm

Karen will rent a car for the weekend. She can choose one of two plans. The first plan has an initial fee of $49 and costs an additional $0.15 per mile driven. The second plan has an initial fee of $38 and costs an additional $0.17 per mile driven.

Answers

Is there more to the question?

Avi's pet hamster Chubby loves to run in his hamster wheel. During one "race", Avi counts 100 rotations of the wheel. She wants to know how far Chubby ran, so she measures the diameter of the wheel and finds that it is 20 cm. How far did Chubby run? Round your answer to the nearest cm

Answers

Answer:

Chubby ran a distance of 6,283 m

Step-by-step explanation:

The length of one run is simply equal to the circumference of the circle

Mathematically, C = pi * d

C = 22/7 * 20 = 62.83 cm

So if one rotation is a distance of 62.83 cm, then 100 rotations will be a distance of;

62.83 * 100 = 6,283 m

Answer:

its 6280!

the answer above is wrong. this answer is from khan academy. :)

Help please!! I will give crown! :D

Answers

Answer:

C. Please mark Brainliest!!!!!!

Step-by-step explanation:

You move it 5 over, so it is 3.844x10^5

Answer:

answer is c

bc you multiply 3.844 by 100000 to get 38440

Step-by-step explanation:
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