PLEASE HELP!!!Amy, Dan, and Mike are competing in a cooking competition. They all used different amounts of milk from a container holding 6 gallons of milk.
Amy used 13% of the total milk in the container.
Dan used 0.14 of the total milk in the container.
Mike used 0.5 gallon of the total milk in the container.
Who used the greatest amount of milk from the container? Show your work and explain your answer in words.
Must use inverse operations
Answers
I'm not sure what your teacher means by "must use inverse operations".
Anyways, Amy uses 13% of the total milk (6 gallons). So she uses 0.13*6 = 0.78 gallons.
Then we're told that Dan used 0.14 of the total milk. So 0.14*6 = 0.84 to indicate Dan used more than Amy. Dan also used more than Mike because 0.84 gallons is larger than 0.5 gallons.
Answer: Dan used the most milk (0.84 gallons)
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A survey of the mean number of cents off that coupons give was conducted by randomly surveying one coupon per page from the coupon sections of a recent San Jose Mercury News. The following data were collected: 20¢; 75¢; 50¢; 65¢; 30¢; 55¢; 40¢; 40¢; 30¢; 55¢; $1.50; 40¢; 65¢; 40¢. Assume the underlying distribution is approximately normal. (a) Determine the sample mean in cents (Round to 3 decimal places)
Hhgggfgn help hellpme
The domain of a function f(x) is x 20, and the range is ys-1. What are thedomain and range of its inverse function, F1(x)?
Answers
Answer:
30 feet in 10 seconds
Step-by-step explanation:
2. Regular pentagon PENTA has side lengths that are 9 meters long. To the nearest square meter, find the area of the pentagon.
Area of pentagon PENTA = _____square centimeter
Answers
Given
1) Trapezoid BEAR with bases 11.5 and 6.5 and height 8.5, all in cm.
2) Regular pentagon PENTA with side lengths 9 m
Find
The area of each figure, rounded to the nearest integer
Solution
1) The area of a trapezoid is given by
... A = (1/2)(b1 +b2)h
... A = (1/2)(11.5 +6.5)·(8.5) = 76.5 ≈ 77
The area of BEAR is about 77 cm².
2) The conventional formula for the area of a regular polygon makes use of its perimeter and the length of the apothem. For an n-sided polygon with side length s, the perimeter is p = n·s. The length of the apothem is found using trigonometry to be a = (s/2)/tan(180°/n). Then the area is ...
... A = (1/2)ap
... A = (1/2)(s/(2tan(180°/n)))(ns)
... A = (n/4)s²/tan(180°/n)
We have a polygon with s=9 and n=5, so its area is
... A = (5/4)·9²/tan(36°) ≈ 139.36
The area of PENTA is about 139 m².
Answer:139 cm squared
The area of a trapezoid is given by
... A = (1/2)(b1 +b2)h
... A = (1/2)(11.5 +6.5)·(8.5) = 76.5 ≈ 77
The area of BEAR is about 77 cm².
The conventional formula for the area of a regular polygon makes use of its perimeter and the length of the apothem. For an n-sided polygon with side length s, the perimeter is p = n·s. The length of the apothem is found using trigonometry to be a = (s/2)/tan(180°/n). Then the area is ...
... A = (1/2)ap
... A = (1/2)(s/(2tan(180°/n)))(ns)
... A = (n/4)s²/tan(180°/n)
We have a polygon with s=9 and n=5, so its area is
... A = (5/4)·9²/tan(36°) ≈ 139.36
The area of PENTA is about 139 m².
B. 12/37
C. 12/35
D. 35/37
Answers
Answer:
A
Step-by-step explanation:
Use the SOH CAH TOA
Tangent = Opposite / adjacent
tan (a) = 35 / 12
Answer:
the answer is obviously going to be a
Answers
Answer:
parethses is expressed of the sign air water land etc
Step-by-step explanation:
Answers
Answer:
B. False
Step-by-step explanation:
1 minute/60 seconds
Therefore, the answer is B. False.
Hope this will helpful.
Thank you.
Answers
Answer:
College town race is 31% of the home town race.
Step-by-step explanation:
Length of hometown race = 3 miles
Length of college town race = 1492 meters
Since 1 meter = 0.0006214 miles
Therefore, 1492 = 0.93 miles
Percentage of college town race to the hometown race,
=
=
= 31%
Therefore, the college town race is 31% of the home town race.
The college town race is approximately 46.31% of the hometown race in length.
First, let's convert both race distances to a common unit of measurement. We'll convert the 2-mile hometown race to meters since the college town race is already in meters.
1 mile is approximately equal to 1609.34 meters. So, the 2-mile hometown race is:
2 miles * 1609.34 meters/mile = 3218.68 meters
Now, we can calculate the length ratio between the college town race and the hometown race:
College Town Race Length: 1492 meters
Hometown Race Length: 3218.68 meters
To find the percentage of the college town race length compared to the hometown race length, we can use the following formula:
(Length of College Town Race / Length of Hometown Race) * 100
(1492 meters / 3218.68 meters) * 100 ≈ 46.31%
So, the college town race is approximately 46.31% of the length of the hometown race.
To know more about percentage here
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