Which expression is equivalent to the given expression?12(x – 17)

A.
12x – 29

B.
12 + 12 • 17

C.
12x – 12 • 17

D.
12x – 17

Answers

Answer 1

Answer: 12(x-17)

the answer would be C
12x-12*17

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Answers

Answer:

Step-by-step explanation:

2. What is the value of 6x – 3y if x = 5 and y = 1F.11.
G.33
H.6 with an exponent of 5
I.65

Answers

Step-by-step explanation:

x=5,y=-1

6(5)-3(-1)=30+3=33

answer G .33

Suppose you were exploring the hypothesis that there is a relationship between parents’ and children’s party identification. Would we be correct in inferring that such a relationship also exists in the population? Explain your answer. What is the probability that any relationship we found is due to pure chance?

Answers

Answer:

It could be purely due to chance.

Step-by-step explanation:

A population is defined as the whole group which has the same characteristics. For example a population of the college belongs to the same college . But a sample may be an element of a population.

So it is not necessary for a population to have the same characteristics as the sample.

But it is essential for the sample to have at least one same characteristics as the population.

So we would not be correct in inferring that such a relationship also exists in the population.

It is a hypothesis which can be true or false due to certain conditions or limitations as the case maybe.

For example in a population of smokers some may be in the habit of taking cocaine. But a sample of cocaine users does not mean the whole population uses it.

It could be purely due to chance if we find out that there is a relationship between parents’ and children’s party identification in the population.

The weights, in pounds, of the cats in an animal adoption center are normally distributed. If a random sample of cats is taken and the confidence interval is (7.9,12.7), what is the margin of error

Answers

Answer: 2.4

Step-by-step explanation:

Given : The weights, in pounds, of the cats in an animal adoption center are normally distributed.

The confidence interval is (7.9,12.7) (1)

Let $\overline{x}$ be the sample mean of the weights, in pounds, of the cats in an animal adoption center.

We know that the confidence interval for population mean is given by :-

$(\overline{x}-E,\overline{x}+E)$ (2)

From (1) and (2)

$\overline{x}-E=7.9-------(3)\n\n\overline{x}+E=12.7--------------(4)$

Subtracting (3) from (4), we get

$2E=4.8\n\n\Rightarrow\ E=2.4$

Hence, the margin of error is E = 2.4

Suppose that dP/dt = 0.19P(t) represents a mathematical model for the growth of a certain cell culture, where P(t) is the size of the culture (measured in millions of cells) at time t > 0 (measured in hours). How fast is the culture growing at the time t when the size of the culture reaches 2 million cells?

Answers

Answer: 380000 cells/hour

Step-by-step explanation:

Given that dP/dt = 0.19P(t)

where

P(t) is the size of the culture (measured in millions of cells) at time t > 0 (measured in hours).

The formula above represents a mathematical model for the growth of a certain cell culture. In essence, it represents the time rate of the growth of the cell culture, that is how fast the cell culture is growing.

Therefore, when P = 2 million cells:

dP/dt = 0.19 * 2000000 = 380000 cells/hour

Hence, the cell culture is growing at 380000 cells per hour.

Final answer:

The cell culture is growing at a rate of 0.38 million cells per hour when the size of the culture reaches 2 million cells. This is based on the given differential equation dP/dt = 0.19P(t).

Explanation:

This problem is associated with the concept of differential equations, particularly exponential growth. In this scenario, the rate of change of P(t), the size of the cell culture, is given by the equation dP/dt = 0.19P(t). This can be interpreted as the culture is growing at 19% per unit of time.

To determine how fast the culture is growing when P(t) equals 2 million cells, we need to substitute 2 for P(t) in the given equation: dP/dt = 0.19*2. This calculation returns a value of 0.38 million cells per hour. Therefore, when the size of the culture reaches 2 million cells, it is growing at a rate of 0.38 million cells per hour.