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just c Thank you sm!!! WILL GIVE BRAINLIEST!! - 1

Answers

Answer 1
Answer: 1/6??? I’m not sure but I learned it in school lol

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The following measurements were recorded for the drying time, in hours, of a certain brand of latex paint: 3.4, 2.5, 4.8, 2.9, 3.6, 2.8, 3.3, 5.6, 3.7, 2.8, 4.4, 4.0, 5.2, 3.0, 4.8. Assuming that the measurements represent a random sample from a normal population, find a 95% prediction interval for the drying time for the next trial of the paint.

Answers

Answer:

The 95% confidence interval for the mean is (3.249, 4.324).

We can predict with 95% confidence that the next trial of the paint will be within 3.249 and 4.324.

Step-by-step explanation:

We have to calculate a 95% confidence interval for the mean.

As the population standard deviation is not known, we will use the sample standard deviation as an estimation.

The sample mean is:

M=(1)/(15)\sum_(i=1)^(15)(3.4+2.5+4.8+2.9+3.6+2.8+3.3+5.6+3.7+2.8+4.4+4+5.2+3+4.8)\n\n\n M=(56.8)/(15)=3.787

The sample standard deviation is:

s=\sqrt{(1)/((n-1))\sum_(i=1)^(15)(x_i-M)^2}\n\n\ns=\sqrt{(1)/(14)\cdot [(3.4-(3.787))^2+(2.5-(3.787))^2+(4.8-(3.787))^2+...+(4.8-(3.787))^2]}\n\n\ns=\sqrt{(1)/(14)\cdot [(0.15)+(1.66)+(1.03)+...+(1.03)]}

s=\sqrt{(13.197)/(14)}=√(0.9427)\n\n\ns=0.971

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=3.787.

The sample size is N=15.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

s_M=(s)/(√(N))=(0.971)/(√(15))=(0.971)/(3.873)=0.2507

The t-value for a 95% confidence interval is t=2.145.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=2.145 \cdot 0.2507=0.538

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 3.787-0.538=3.249\n\nUL=M+t \cdot s_M = 3.787+0.538=4.324

The 95% confidence interval for the mean is (3.249, 4.324).

Using the figure below, what is the trigonometric ratio of cos C?

Answers

Answer:

8/9 (choice b)

Step-by-step explanation:

The trigonometric ratios are based on the ratios of different sides.

If you remember SOH CAH TOA =

sine (sin) opposite hypotenuse

cosine (cos) adjacent hypotenuse

tangent (tan) opposite adjacent

__________________________

This is a nuemonic for these ratios.

the opposite side is the side that is directly across from the reference angle, the hypotenuse is the longest side, and the adjacent side is the side other than these two.

So cos C = adjacent side / hypotenuse side.

Since 18 is greater than 16 and 9, 18 is the hypotenuse.

the adjacent side is the side other than the opposite side and the hypotenuse which is 16

therefore cos C = 16 / 18 = 8 / 9.

Please help

13 through 16​

Answers

Answer:

13. C

14. B

15. C

16. D

Step-by-step explanation:

In tilapia, an important freshwater food fish from Africa, the males actively court females. They have more incentive to court a female who has already laid all of her eggs, but can they tell the difference? an experiment was done to measure the male tilapia's response to the smell of female fish. Water containing feces from females that were either pre-ovulatory (they still had eggs) or post-ovulatory (they had already laid their eggs) was washed over the gills of males hooked up to an electro-olfactogram machine which measured when the senses of the males were excited. The amplitude of the electro-olfactogram was used as a measure of the excitability of the males in the two different circumstances. Six males were exposed to the scent of pre-ovulatory females; their readings average 1.51 with a standard deviation of .25. Six different males were exposed to post-ovulatory females; their average readings of 0.87 with standard deviation is .31. Assume that the electro-olfactogram readings were approximately normally distributed within the groups.(A) test for a difference in the excitability of the males with exposure to these two types of females
(B) what is the estimated average difference in electro-olfactogram readings between the two groups? What is the 95% confidnece limit for the difference between population means?

Answers

Answer:

a) t=\frac{1.51-0.87}{\sqrt{(0.25^2)/(6)+(0.31^2)/(6)}}=3.936  

"=T.INV(1-0.025,10)", and we got t_(critical)=\pm 2.28  

Statistical decision  

Since our calculated value is higher than our critical value,z_(calc)=3.936>2.28=t_(critical), we have enough evidence to reject the null hypothesis at 5% of significance.

b) (\bar X_1  -\bar X_2) \pm t_(\alpha/2)\sqrt{(s^2_(1))/(n_(1))+(s^2_(2))/(n_(2))}

The degrees of freedom are given:

df = n_1 + n_2 -2 = 6+6-2 = 10

(1.51 -0.87) - 2.28\sqrt{(0.25^2)/(6)+(0.31^2)/(6)}= 0.269

(1.51 -0.87) + 2.28\sqrt{(0.25^2)/(6)+(0.31^2)/(6)}= 1.010

Step-by-step explanation:

Part a

Data given and notation    

\bar X_(1)=1.51 represent the mean for scent of pre ovulatory

\bar X_(2)=0.87 represent the mean for post ovolatory

s_(1)=0.25 represent the sample standard deviation for preovulatory

s_(2)=0.31 represent the sample standard deviation for postovulatory

n_(1)=6 sample size for the group preovulatory

n_(2)=6 sample size for the group postovulatory

z would represent the statistic (variable of interest)  

p_v represent the p value    

Concepts and formulas to use    

We need to conduct a hypothesis in order to check if the mean's are different, the system of hypothesis would be:    

H0:\mu_(1) = \mu_(2)    

H1:\mu_(1) \neq \mu_(2)    

If we analyze the size for the samples both are lower than 30, so for this case is better apply a t test to compare means, and the statistic is given by:  

t=\frac{\bar X_(1)-\bar X_(2)}{\sqrt{(s^2_(1))/(n_(1))+(s^2_(2))/(n_(2))}} (1)    

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.    

Calculate the statistic    

We have all in order to replace in formula (1) like this:    

t=\frac{1.51-0.87}{\sqrt{(0.25^2)/(6)+(0.31^2)/(6)}}=3.936  

Find the critical value  

We find the degrees of freedom:

df = n_1 + n_2 -2 = 6+6-2 = 10

In order to find the critical value we need to take in count that we are conducting a two tailed test, so we are looking for thwo values on the t distribution with df =10 that accumulates 0.025 of the area on each tail. We can us excel or a table to find it, for example the code in Excel is:  

"=T.INV(1-0.025,10)", and we got t_(critical)=\pm 2.28  

Statistical decision  

Since our calculated value is higher than our critical value,z_(calc)=3.936>2.28=t_(critical), we have enough evidence to reject the null hypothesis at 5% of significance.

Part b

For this case the confidence interval is given by:

(\bar X_1  -\bar X_2) \pm t_(\alpha/2)\sqrt{(s^2_(1))/(n_(1))+(s^2_(2))/(n_(2))}

The degrees of freedom are given:

df = n_1 + n_2 -2 = 6+6-2 = 10

(1.51 -0.87) - 2.28\sqrt{(0.25^2)/(6)+(0.31^2)/(6)}= 0.269

(1.51 -0.87) + 2.28\sqrt{(0.25^2)/(6)+(0.31^2)/(6)}= 1.010

The sphere at the right fits snugly inside a cube with 4-in. edges. What is the approximate volume of the space between the sphere and cube?

Answers

As given by the question

There are given that the inside edge is 4 in.

Now,

Since sphere fits snugly inside a cube therefore diameter of sphere will be equal to side of the cube

So,

\begin{gathered} \text{diameter}=4\text{ inches} \n \text{radius}=(dameter)/(2) \n \text{radius}=(4)/(2) \n \text{radius}=2 \end{gathered}

Then,

Volume of the sphere is given by:

\begin{gathered} (4)/(3)*\pi* r^3=(4)/(3)*3.14*2^3 \n =(4)/(3)*3.14*8 \n =33.5 \end{gathered}

And,

The volume of a cube is:

\begin{gathered} \text{Volume of cube=side}* side* side \n =4*4*4 \n =64\text{ inches} \end{gathered}

Then,

The volume of the space between the sphere and cube = 64-33.5 = 30.5.

Hence, the answer is 30.5 cube inches.

In the figure below, lines p and s are parallel.

Answers

Answer:

c

Step-by-step explanation:

i used a calculator (they never lie)

Answer:

22

Step-by-step explanation:

60+6x-12= 180

6x = 180 -48

x= 132/6= 22