Answer:
travel Horizontally
Explanation:
Answer:
To find the distance traveled by the bicyclist during the given time, we can use the formula:
Distance = (Initial Velocity * Time) + (0.5 * Acceleration * Time^2)
Since the bicyclist starts from rest, the initial velocity is 0 m/s.
Given:
Initial velocity (u) = 0 m/s
Final velocity (v) = 11.0 m/s
Time (t) = 3.40 s
Using the formula, we can calculate the distance traveled:
Distance = (0 * 3.40) + (0.5 * Acceleration * 3.40^2)
To find the acceleration, we can use the equation:
Acceleration = (Final Velocity - Initial Velocity) / Time
Acceleration = (11.0 - 0) / 3.40
Acceleration = 11.0 / 3.40
Now, we substitute the value of acceleration into the distance formula:
Distance = (0 * 3.40) + (0.5 * (11.0 / 3.40) * 3.40^2)
Simplifying further:
Distance = 0 + (0.5 * (11.0 / 3.40) * 11.56)
Distance = (0.5 * (11.0 / 3.40) * 11.56)
Distance = (0.5 * 11.0 * 3.40)
Distance = 0.5 * 37.4
Distance = 18.7 meters
Therefore, the bicyclist traveled a distance of 18.7 meters during the given time of 3.40 seconds.
Answer:
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Explanation:
The x - component of the initial velocity is given as:
Ux = Vi cos theta
Ux = 100cos 60
Ux = 50m/s
Answer:
True
Explanation:
i took the quiz
a. 2
b. 4
c. 6
d. 8
A. 200 J
B. 330 J
C. 352 J
D. 220 J
Answer: Option (C) is the correct answer.
Explanation:
Work is defined as the energy required when force is applied in a certain direction.
The expression for work, force and distance is as follows.
W = F × d
where, W = work
F = force
d = distance
It is given that force applied to drag the box is 22 N and distance is 16 meters. Therefore, calculate work done as follows.
W = F × d
= 22 N × 16 meters
= 352 Nm (1 Newton meter = 1 joule)
or, W = 352 J
Thus, we can conclude that amount of work done is 352 J.