Find initial velocity and time in air​
find initial velocity and time in air​ - 1

Answers

Answer 1
Answer:

Answer:

The answer to your question is: v = 121.46 m/s

Explanation:

Data

h = 30 m

vo = ?

dx = 300 m

Formula

t = \sqrt{(2h)/(g)}

speed = distance / time

Process

t = \sqrt{(2(30))/(9.81)} \n

t= 2.47 s

speed = 300 / 2.47

speed = v = 121.46 m/s


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NEED ASAP PLEASE !! Billy drops a water balloon from the roof of his house. Since the balloon began with an original velocity of zero, how far above ground was the balloon dropped if it took 2.5 seconds to hit the ground?

A. 30.6 m
B. 122.5 m
C. 12.3 m
D. 49.0 m

Answers

The formula you want is:

           Distance = (1/2) (gravity) (time)²

                           =  (1/2) (9.8 m/s²) (2.5 sec)²

                           =    (4.9 m/s²)  (6.25 sec²)

                           =            30.6 meters

A 2000-kg car traveling at 40m/s hits a wall with a force of 40,000N and comes to a stop what was the impact time?A-0.5s
B-2s
C-400s
D-800s

Answers

Answer:

Option (B)

Explanation:

mass of car, m = 2000 kg, initial velocity of car, u = 40 m/s,

Force, F = 40,000 N, Final velocity, v = 0 m/s

Let the impact time be t.

By use of Newton's second law

F = m a

where, a be the acceleration and m be the mass.

40000 = 2000 x a

a = 20 m/s^2

Acceleration is negative because the car is stopped.

Use first equation of motion,

v = u + a x t

0 = 40 - 20 x t

t = 2 second

D- 800 s I think I did (40,000)(40)/2000 idk if this is the right answer