Order the following from least to greatest: 100% 1/100 0.001% 1/10 0.001 1.1 10 and 10,000/100

Answer:

The surface area of a solid object is a measure of the total area that the surface of the object occupies. The mathematical definition of surface area in the presence of curved surfaces is considerably more involved than the definition of arc length of one-dimensional curves, or of the surface area for polyhedra (i.e., objects with flat polygonal faces), for which the surface area is the sum of the areas of its faces. Smooth surfaces, such as a sphere, are assigned surface area using their representation as parametric surfaces. This definition of surface area is based on methods of infinitesimal calculus and involves partial derivatives and double integration.

Step-by-step explanation:

Answer: if I am correct it is 39%

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

-2,4 and 6,4

u add 6 + 2 = 8

easyy

Hello,

The median of the temperatures at Springwood is 86. (median is at the middle).

the median of the temperatures at Meadows is 73. (median is at the middle).

The (IQR) interquartile range of the temperatures at Meadows is 12. (You have to subtract both of the IQR left and right 80 - 68 = 12).

The (IQR) interquartile range of the temperatures at Springwood is 14. (You have to subtract both of the IQR left and right 91 - 77 = 14).

the difference of the medians as a multiple of their average interquartile range is 79.5 is average median and 13 average IQR.

Answer: The median of the temperatures at Springwood is 86.    

The median of the temperatures at Meadows is 73.  

The interquartile range of the temperatures at Meadows is 12.  

The interquartile range of the temperatures at Springwood is 14.

The difference of the medians as a multiple of their average interquartile range as : Difference in medians = 13= 1 x 13

i.e. Difference in medians  = 1 x (Average interquartile range)

Step-by-step explanation:

In a box - whisker plot , the vertical line in box represents the median value.

The left end of box denotes Lower quartile and the right end of the box Upper quartile.

By considering the given picture,

For Meadows ,

Median = 73

The median of the temperatures at Meadows is 73.                           (1)

Lower quartile = 68

Upper quartile = 80

Interquartile range = Upper quartile- Lower quartile

Interquartile range=80-68 = 12

The interquartile range of the temperatures at Meadows is 12.     (2)

For Springwood,

Median = 86

The median of the temperatures at Springwood is 86.                 (3)

Lower quartile = 77

Upper quartile = 91

Interquartile range = Upper quartile- Lower quartile

= 91-77 = 14

The interquartile range of the temperatures at Springwood is 14.         (4)

Difference in medians = 86-73 = 13              [From (1) and (3)]

Average interquartile range =    [From (2) and (4)]

The difference of the medians as a multiple of their average interquartile range as : Difference in medians = 13= 1 x 13

i.e. Difference in medians = 1 x (Average interquartile range)