Match the polygons formed by the sets of points with their perimeters ( rounded to the nearest hundredth). Please Help me I don't understand this question. Thank youA( 1, 1), B(6,13), C(8,13), D(16,-2) E(1, -2 )
38 units
K(4,2), L(8,2), M(12,5), N(6,5), O(4,4)
50 units
F(14,-10), G(16, -10), H(19,-6), I (14,-2), J(11,-6)
25.4 units
P(7,2), Q (12,2), R(12,6), S(7,10), T(4,6)
19.24 units
U(4, -1), V(12, -1), W(20,-7), X(8, -7), Y(4,-4)

Answers

Answer 1

Answer:

Answer with explanation:

→→Using the Distance formula, $\sqrt{(x_(2)-x_(1))^2+(y_(2)-y_(1))^2$ finding the distance between two points that is between two vertices

The Points which are vertices of Polygons are

1.→ A( 1, 1), B(6,13), C(8,13), D(16,-2) E(1, -2 )

$AB=√((6-1)^2+(13-1)^2)\n\nAB=√(5^2+12^2)\n\n AB=√(25+144)\n\n AB=√(169)\n\n AB=13$

$BC=√((8-6)^2+(13-13)^2)\n\n BC=√(2^2)\n\n BC=2$

$CD=√((16-8)^2+(-2-13)^2)\n\n CD=√(8^2+15^2)\n\nCD=√(64+225)\n\nCD=√(289)\n\nCD=17\n\nDE=√((16-1)^2+(-2+2)^2)\n\nDE=√(15^2)\n\nDE=15 \n\nAE=√((1-1)^2+(-2-1)^2)\n\n AE=√(3^2)\n\n AE=3$

→→AB+BC+CD+DE+EA= 13+2+17+15+3

=50 units

2. K(4,2), L(8,2), M(12,5), N(6,5), O(4,4)

$KL=√((8-4)^2+(2-2)^2)=√(4^2)=4\n\n LM=√((8-12)^2+(2-5)^2)=√(4^2+3^2)=√(5^2)=5\n\nMN=√((12-6)^2+(5-5)^2)=√(6^2)=6\n\nNO=√((6-4)^2+(5-4)^2)=√(2^2+1^2)=√(5)\n\nKO=√((4-4)^2+(4-2)^2)=√(2^2)=2$

→KL+LM+MN+NO+OK=4+5+6+√5+2

=17+2.24

= 19.24 units

3. F(14,-10), G(16, -10), H(19,-6), I (14,-2), J(11,-6)

$FG=√((16-14)^2+(-10+10)^2)=√(2^2)=2\n\n GH=√((19-16)^2+(-6+10)^2)=√(4^2+3^2)=√(5^2)=5\n\nHI=√((19-14)^2+(-6+2)^2)=√(5^2+4^2)=√(25+16)=√(41)\n\nIJ=√((14-11)^2+(-2+6)^2)=√(3^2+4^2)=√(5^2)=5\n\nJF=√((14-11)^2+(-10+6)^2)=√(3^2+4^2)=√(5^2)=5$

→FG+GH+HI+IJ+JF=2+5+√41+5+5=19+6.40=25.40

4.→ P(7,2), Q (12,2), R(12,6), S(7,10), T(4,6)

$PQ=√((12-7)^2+(2-2)^2)=√(5^2)=5\n\n QR=√((12-12)^2+(-6+2)^2)=√(4^2+0^2)=√(4^2)=4\n\nRS=√((12-7)^2+(-6+10)^2)=√(5^2+4^2)=√(25+16)=√(41)\n\nST=√((7-4)^2+(-10+6)^2)=√(3^2+4^2)=√(5^2)=5\n\nPT=√((7-4)^2+(-2+6)^2)=√(3^2+4^2)=√(5^2)=5$

PQ+QR+RS+ST+TP=5+4+√41+5+5

=19+6.40

= 25.40 units

5.→U(4, -1), V(12, -1), W(20,-7), X(8, -7), Y(4,-4)

$UV=√((12-4)^2+(-1+1)^2)=√(8^2)=8\n\n VW=√((20-12)^2+(-7+1)^2)=√(8^2+6^2)=√(64+36)=√(100)=10\n\nWX=√((20-8)^2+(-7+7)^2)=√(12^2+0^2)=12\n\nXY=√((8-4)^2+(-7+4)^2)=√(3^2+4^2)=√(5^2)=5\n\nYU=√((4-4)^2+(-4+1)^2)=√(3^2+0^2)=√(3^2)=3$

UV +V W+W X+XY+YU

= 8+10+12+5+3

=38 units

Answer 2

Answer:

38 units-U(4, -1), V(12, -1), W(20,-7), X(8, -7), Y(4,-4)

25.4 units-P(7,2), Q (12,2), R(12,6), S(7,10), T(4,6)

50 units-A( 1, 1), B(6,13), C(8,13), D(16,-2) E(1, -2 )

19.24 units-K(4,2), L(8,2), M(12,5), N(6,5), O(4,4)

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Answers

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Answers

Answer:

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Step-by-step explanation:

Percentage change can be calculated from ...

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Answers

The value of x will be;

⇒ x = 7/2

What is an expression?

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

BD is an angle bisector.

Now,

In ΔBFG and ΔBFE;

∠G = ∠E = 90°

BF is common line.

∠GBF = ∠ FBE

Thus, ΔBFG ≅ ΔBFE

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Thus, The value of x will be;

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Learn more about the mathematical expression visit:

brainly.com/question/1859113

#SPJ2

2x+6=4x-1
add 1 to both sides
2x+7=4x
subtract 2x from both sides
7=2x
divide both sides by 2
3.5=x

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Answers

Answer:

a = 25m^2

b = 5m

d = 35.73 m^2

c = 7.94m

Step-by-step explanation:

First, remember that the area of a square of side length L is:

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L = √(16m^2) = 4m

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K^2 = 9m^2

K = √(9m^) = 3m

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b^2 = (4m)^2 + (3m)^2

b^2 = 16m^2 + 9m^2 = 25m^2

b = √(25m^2) = 5m

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a = b^2 = 25m^2

Now let's go to the other image.

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H^2 = 144m^2

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L^2 = 81m^2

The other cathetus will have a sidelength c, such that:

c^2 = area of the purple square

By the Pythagorean's theorem we have:

144m^2 = 81m^2 + c^2

144m^2 - 81m^2 = c^2

63m^2 = c^2

(√63m^2) = c = 7.94m

And the area of a triangle rectangle is equal to the product between the catheti divided by two.

We know that one cathetus is equal to c = 7.94m

And the other on is equal to the square root of 81m^2

√(81m^2) = 9m

then the area of the triangle is:

d = (7.94m)*(9m)/2 = 35.73 m^2

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