AA′ = 33 m and BC = 7.5 m. The span is divided into six equal parts at E, G, C, I, and K. Find the length of A′B.
Answers
The image of this triangle is an isosceles triangle with the base being 33m (from angle A to angle A') and the right leg is 7.5 m long (BC) the span or width of the triangle is divided by 6 vertical lines with equal distances from eachother. so we need to find the length of the left leg AB.
Related Questions
The height of players on a football team is normally distributed with a mean of 74 inches, and a standard deviation of 1 inch. If there are 50 football players on the team, how many are less than 74 inches tall?
What is the distance between points (5, 5) and (1, 5) on a coordinate plane? units
Kyle ran 2/3 mi on Monday,1 1/6 mi on Tuesday, and 7/12 mi on Wednesday.How many total miles did Kyle run?Express the answer in simplest form.
Find the product. 4x3y(-2x2y) Evaluate b2c-1 for b = -4 and c = 2. Find the product. (n 3)3 · (n 4)5
Answers
Answer:
The answer is 1
Step-by-step explanation:
Remember PEMDAS, 1+2 is 3. 2x3 is 6, then 6 divided by 6 is 1.
Answer:
1
Step-by-step explanation:
6 / 2(1 + 2)
6 / 2(3)
6 / 6 = 1
your fractions as much as possible!!!!!!! SHOW ALL WORK!!!
1) (4,5) and (-4,3)
2) (-2,-4) and (6,7)
3) (2, -4) and (10,12) 4) (1/2,2) and (1,2/3) 5) (1/4,5) and (5/4,12)
Answers
Answer:
1) slope of the line
2) slope of the line
3) slope of the line m =2
4) slope of the line
5) slope of the line m =7
Step-by-step explanation:
1)
Given points are (4,5) and (-4,3)
slope of the line Formula
2)
Given points are (-2,-4) and (6,7)
slope of the line Formula
3)
Given points are (2, -4) and (10,12)
slope of the line Formula
4) Given points are
(1/2,2) and (1, 2/3)
slope of the line Formula
5)
Given points are
(1/4,5) and (5/4 , 12)
slope of the line Formula
Answers
y = 2x - 3
(1, -1)
-1 = 2(1) - 3
-1 = 2 - 3
-1 = -1
So (1, -1) satisfies the equation.
(-3, 0)
0 = 2(-3) - 3
0 = -6 - 3
0 = -9
So (-3, 0) does not satisfy the equation.
(5, 4)
4 = 2(5) - 3
4 = 10 - 3
4 = 7
So (5, 4) does not satisfy the equation.
Therefore your answer is the first one, (1, -1).
(I have a graphing calculator capble of matrices so yo don't have to solve the system of equations by hand, use rref (reduced row echelon form))
values of a, b, and c and the equation of the graph of the parabola
y=ax^2+bx+c
such that is passes through the points
(2,-15)
(-5,-29)
(-3,5)
rewrite it in the form (x-h)^2=4P(y-k)
show all work
if I were to sub the points in I would ge
(2,-15): -15=4a+2b+c
(-5,-29): -29=25a-5b+c
(-3,5): 5=9a-3b+c
then solve for a, b and c
I don't know how to solve, please help
(if I don't undestand your answer, I will either report or ask you to explain more)
Answers
y =ax² + bx + c
Since parabola passes through the point (2,−15) then
−15 = 4a + 2b + c
Since parabola passes through the point (-5,-29), then
−29 = 25a − 5b + c
Since parabola passes through the point (−3,−5), then
−5 = 9a − 3b + c
Thus, we obtained following system:
4a + 2b + c = −15
25a − 5b + c = −29
9a − 3b + c = −5
Solving it we get that
a = −2, b = −4, c = 1
Thus, equation of parabola is
y = −2x²− 4x + 1
____________________
Rewriting in the form of
(x - h)² = 4p(y - k)
i) -2x² - 4x + 1 = y
ii) -3x² - 7x = y - 11
(-3x² and -7x are isolated)
iii) -3x² - 7x - 49/36 = y - 1 - 49/36
(Adding -49/36 to both sides to get perfect square on LHS)
iv) -3(x² + 7/3x + 49/36) = y - 3
(Taking out -3 common from LHS)
v) -3(x + 7/6)² = y - 445/36
vi) (x + 7/6)² = -⅓(y - 445/36)
(Shifting -⅓ to RHS)
vii) (x + 1)² = 4(-1/12)(y - 445/36)
(Rewriting in the form of 4(-1/12) ; This is 4p)
So, after rewriting the equation would be -
(x + 7/6)² = 4(-⅛)(y - 445/36)
__________________
I hope this is what you wanted.
Regards,
Divyanka♪
__________________
y =ax² + bx + c
Since parabola passes through the point (2,−15) then
−15 = 4a + 2b + c
Since parabola passes through the point (-5,-29), then
−29 = 25a − 5b + c
Since parabola passes through the point (−3,5), then
5 = 9a − 3b + c
Thus, we obtained following system:
4a + 2b + c = −15
25a − 5b + c = −29
9a − 3b + c = 5
Solving it we get that
a = −3, b = −7, c = 11
Thus, equation of parabola is
y = −3x²− 7x + 11
____________________
Rewriting in the form of
(x - h)² = 4p(y - k)
i) -3x² - 7x + 11 = y
ii) -3x² - 7x = y - 11
(-3x² and -7x are isolated)
iii) -3x² - 7x - 147/36 = y - 11 - 147/36
(Adding -147/36 to both sides to get perfect square on LHS)
iv) -3(x² + 7/3x + 49/36) = y - 543/36
(Taking out -3 common from LHS)
v) -3(x + 7/6)² = y - 181/12
vi) (x + 7/6)² = -⅓(y - 181/12)
(Shifting -⅓ to RHS)
vii) (x + 1)² = 4(-1/12)(y - 181/12)
(Rewriting in the form of 4(-1/12) ; This is 4p)
So, after rewriting the equation would be -
(x + 7/6)² = 4(-1/12)(y - 181/12)
_________________
I have corrected the answer and wrote again since the time to correct the answer from that account was expired.
- Divyanka
16.90x + 4y = 36.35
1. What does the solution to the system represent?
Answers
Answer:
See below.
Step-by-step explanation:
It represents the coordinates of the point of intersection of the lines represented by the 2 equations.
Do you want them solved?
Answers
Answer:
{x | x R, x = 7 }
Step-by-step explanation:
x - 6 = 1
x - 6+6 = 1+6
x=7
{x | x R, x = 7 }