MATHEMATICS HIGH SCHOOL

Divide. Express your answer in simplest form.
8 divided by 2 4/9

Answers

Answer 1
Answer: 8 divided by 2 4/9 is equal to 36/11. 
2 4/9 = 22/9 
8 : 22/9 = 8* 9/22= 36/11
Answer 2
Answer:

Answer:

3 (3/12) or 3 (6/22)

Step-by-step explanation:

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What is the answer to 3 times 4 plus 10 times 5

Answers

(3×4)+(10×5)=x
You multiply the numbers first
12+50=x
You add them
62=x
Your answer is 62
thats easy
(3 times 4) +(10 times 5)
12+50
62
so your final answer is 62

Find the product of 2x4(4x2 + 3x + 1). 8x6 + 6x5 + 2x4

8x8 + 3x4 + 2x4

2x4 + 6x5 + 8x6

6x6 + 5x5 + 3x4

Answers

Answer:

The product of the 2x^(4)(4x^(2)+3x+1) is 8x^(6)+6x^(5)+2x^(4) .

Step-by-step explanation:

As given the expression in the question be

= 2x^(4)(4x^(2)+3x+1)

First open the bracket

= 2x^(4)* 4x^(2)+2x^(4)* 3x+2x^(4)* 1

Now by using the property

x^(a)* x^(b)=x^(a+b)

= 8x^(6)+6x^(5)+2x^(4)

Therefore the product of the 2x^(4)(4x^(2)+3x+1) is 8x^(6)+6x^(5)+2x^(4) .
2x^4(4x^2 + 3x + 1)=\n\n(2x^4)(4x^2)+(2x^4)(3x)+(2x^4)(1)=\n\n8x^6 + 6x^5+2x^4

The answer is A.

How many triangles exist with the given side lengths?12 in, 15 in, 18 in
A) No triangle exists with the given side lengths.
B) Exactly one unique triangle exists with the given side lengths.
C) More than one triangle exists with the given side lengths.

Answers

According to triangle inequality theorem, “The sum of the length of two sides of a triangle should be greater than the third side”. In order to verify the mentioned theorem, some calculations are performed below.

 12 + 15 > 18

15 + 18 > 12

12 + 18 > 15

As the triangle inequality theorem satisfied, so there is only one triangle possible with the given sides length. No more than one triangle is possible, because the angles are not given, and the sides length are fixed.

So option “B” is correct. 

Answer:

it is b

Step-by-step explanation:

Jake mowed 216 sq.yd. of lawn in 3 hr. Ricky mowed 108 sq.yd. of lawn in 2 hr.Can you fill in the values for Ricky?



Ricky’s square yards mowed:

Ricky’s time (hr.):

Answers

Final answer:

To find Ricky's values, set up a proportion and solve for Ricky's square yards mowed and time.

Explanation:

To find the values for Ricky, we can use a proportion. Since Jake mowed 216 sq.yd. in 3 hr, we can set up the proportion as 216/3 = Ricky's square yards mowed/2. To solve for Ricky's square yards mowed, we can cross multiply and divide: 216 * 2 = 3 * Ricky's square yards mowed. Therefore, Ricky's square yards mowed = 432 sq.yd. Next, we can find Ricky's time by setting up another proportion: 216/3 = 432/Ricky's time. Cross multiplying and dividing gives us Ricky's time = 6 hr.

Learn more about Proportion here:

brainly.com/question/32430980

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Answer:

108 Square Yards

2 Hours

Step-by-step explanation:

PLEASE MARK BRAINLIEST

All you do is look at the question and it says he mowed 108 square yards in 2 hours.

D=RT for D, if T=5hours and T=65mph

Answers

D = RT

Since R = 65 and T = 5, just plug those numbers into the equation and solve.

D = 65 • 5 
D = 325 miles
325 Miles because all you do is multiple. If you mean R =5 hours, then just multiple. The units cancel out as 5hours*65m/h =325 miles.

Let f(x,y)=x^2 + ln(y).Calculate the instantaneous rate of change at (3,1) to (1,2).

Answers

To find the instantaneous rate of change of the function f(x,y) = x^2 + ln(y) at (3,1) to (1,2), we can use the partial derivatives with respect to x and y:

fx(x,y) = 2x

fy(x,y) = 1/y

Then, we can use the gradient vector to find the direction of maximum increase:

∇f(x,y) = <fx(x,y), fy(x,y)> = <2x, 1/y>

At point (3,1), the gradient vector is:

∇f(3,1) = <6, 1>

At point (1,2), the gradient vector is:

∇f(1,2) = <2, 1/2>

To find the instantaneous rate of change from (3,1) to (1,2), we can use the formula for directional derivative:

Dv(f) = ∇f(x,y) · v

where v is the unit vector in the direction from (3,1) to (1,2). The direction vector v is given by:

v = <1, 2> - <3, 1> = <-2, 1>

To make v a unit vector, we need to normalize it by dividing it by its length:

|v| = sqrt((-2)^2 + 1^2) = sqrt(5)

u = v/|v| = <-2/sqrt(5), 1/sqrt(5)>

Then, the instantaneous rate of change from (3,1) to (1,2) is:

Dv(f) = ∇f(3,1) · u = <6, 1> · <-2/sqrt(5), 1/sqrt(5)> = (-12/sqrt(5)) + (1/sqrt(5)) = -11/sqrt(5)

Therefore, the instantaneous rate of change of the function f(x,y) = x^2 + ln(y) from (3,1) to (1,2) is -11/sqrt(5).

To learn more about instantaneous rate of change refer below:

brainly.com/question/31011769

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