tonya works part time in a store at the mall. She is paid about$200 per week before takes and social security. Tonya pays about $40 out of each weekly checks for taxes and social security total. What percent of the $200 weekly pay is Tonya paying for taxes and social security

Answers

Answer 1
Answer: Hey there,

200-40=160 
so 200-20%=160 

so the answer is he takes out 20% per week!

Hope this helped

Related Questions

Consider f(x)=2|x|What is the rate of change over the interval 0≤x≤4?How is the rate of change over this interval related to the form of the function?
The value x = 3 is a solution to each of the following except which?(1) 4x-1=2x +5(3) 5x +4<19(2) 2x-8(4) (x+1)(x-3)=0
Evaluate A2 for A = 2.3.
David recycles 5 cans every week. Which expression shows the total number of cans he recycles in w weeks?A.5wB.w/5C.5 + wD.5 + 5w
mike has 350.75 while jane has 250.25 .if they spent together a total amout of 295.50 and saved remaining amount how much they put together in the saving box?

Evaluate the 6 trigonometric functions of theta for 540 degrees

Answers

540 degrees is equivalent to 180 degrees. Cotangent and cosecant are invalid, sine, secant, tangent are all 0 and cosine is -1.

What are the answers to all these questions?

Answers

For example exc. 4!

V = x(6 - 2x)(10 - 2x) = (6x - 2x^2)(10 -2x) = 60x - 12x^2 - 20x^2 + 4x^3 = 4x^3 - 32x^2 + 60x;

What is the measure of DE?
51

56

68

85

Answers

Answer:

(C)68

Step-by-step explanation:

Given: From the given figure, it is given that arcDC=112° and arcAB=72°.

To find: the measure of DE.

Solution: From the given figure, it is given that arcDC=112° and arcAB=72°.

Now, it is given that ∠DOC=112° and ∠EOC=180° (straight line)

thus, using the property that the sum of angles around a point is 360°, therefore

∠EOD+∠DOC+∠EOC=360°

⇒∠EOD+112°+180°=360°

⇒∠EOD=68°

Thus, the measure of DE is 68.

Hence, option (C) is correct.

Write a set of parametric equations for y=x^2+1 given the parameter t=x-2

Answers

t=x-2\ \ \ \Rightarrow\ \ \ x=t+2\n \ny=x^2+1\ \ \ \Rightarrow\ \ \ y=(t+2)^2+1=t^2+4t+5\n \n \left \{ {{x=t+2\ \ \ \ \ } \atop {y=t^2+4t+5}} \right.

Write an equation for the line below. Show work

Answers

x=3 is your answer. This is because it only crosses the x-axis and this occurs at positive 3. y=3 on the other hand would be a horizontal line that only touches positive 3 on the y-axis.

Function f(x) = ax^{2}+bx+c, where a, b, and c are some constants. Define functions g and h as follows:g(x) = f(x+ 1)−f(x)
h(x) = g(x+ 1)−g(x)
Find algebraic form of h(x)
Can anyone explain how to make it step by step?

Answers

g(x) = f(x+1) - f(x)
=[ a(x+1)^2+b(x+1)+c ] - [ax^2+bx+c]
=[ a(x^2+2x+1) +bx + b + c ] - [ax^2 + bx + c]
=[ ax^2 + 2ax + a + bx + b + c ] - [ax^2 + bx + c]
= ax^2 + 2ax + a + bx + b + c - ax^2 - bx - c
= 2ax + a + b
Therefore g(x) = 2ax + a + b
h(x) = g(x+1) - g(x)
=2a (x+1) + a + b - [2ax+a+b]
=2ax + 1 + a +b - 2ax - a - b
Therefore h(x) = 1