To get the minimum amount of fencing, the farmer should use the equation P = x + 2*(2000/x), representing the total fence length, where x is the length of the fence parallel to the river, and solve this to find the minimum.
The problem involves resolving a mathematical problem using functions in optimization. The farmer's goal is to minimize the fencing used which means minimizing the perimeter of the pen. Considering that one side of the pen will be a river, we are essentially looking for the dimensions of a rectangle (with one side along the river) which uses the least amount of fencing. Let's say the length of the fence parallel to the river is x, and the length of the fence perpendicular to the river is y.
Since area (A) is given by A = x*y, which must be 2,000 m2, we can rewrite y equation in terms of x as y = 2,000/x. The total fence length (perimeter, P) is calculated as P = x + 2y and substituting the new equation for y, we get P = x + 2*(2000/x), which is the function that the farmer needs to optimize in order to use the least amount of fencing.
#SPJ12
Thank you btw!
Answer:
D.
Step-by-step explanation:
To get from one point to the other, you have to go down 7 points and right 6 points, resulting in a negative slope. The y-intercept (where it crosses the y-axis, or the line in the middle going up and down) is at y=-7. Hope this helps!
Answer:
The answer is d
Step-by-step explanation:
The equation for slope is y=mx+b
First find the y-intercept (b) which is -7
Then you pick two points on the line to find the rise and run of the line (the slope which is m). The slope of this line in -7/6
Answer: Proper order form least to greatest is given by
Step-by-step explanation:
Since we have given that
We need to write it in proper order from least to greatest.
For this we are required to take the L.C.M. of denominators:
1) L.C.M. of 2,6,7,2 = 42
2) Make the denominator 42:
From least to greatest :
B) $33
C) $37
D) $55
E) $70