MATHEMATICS HIGH SCHOOL

The dimensions in inches of a shipping box can be expressed as width x, length x + 1, and height x - 4. The volume is 84 ft^3. Find the dimensions of the box in feet. 1, 1, 4
2, 2, 21
2, 6, 7
3, 4, 7

Please help? If somebody can help put this into an equation for me, I can do the rest. Thanks

Answers

Answer 1
Answer:

Answer:

The dimensions of the box are

2,6,7

Step-by-step explanation:

we know that

The volume of a box in the shape of a cube is equal to

V=W*L*H

where

W is the width of the box

L is the length of the box

H is the height of the box

In this problem we have

V=84\ ft^(3)

W=x\ ft

L=x+1\ ft

H=x-4\ ft

Substitute the values in the formula of volume

84=x*(x+1)*(x-4)

84=(x^(2)+x)*(x-4)\n84=x^(3) -4x^(2)+x^(2)-4x\n84=x^(3)-3x^(2)-4x\nx^(3)-3x^(2)-4x-84=0

Using a graphing tool

Solve the cubic function

see the attached figure

The value of x is equal to

x=6\ ft

the dimensions of the box are

W=x\ ft=6\ ft

L=x+1\ ft=6+1=7\ ft

H=x-4\ ft=6-4=2\ ft
Answer 2
Answer: 84ft^3= (x-1)•x-4(x)

Maybe, then you would need to solve get the solution of x and plug it in for the demensions, hope this helps! (Not exactly positive that is my is correct but believe it is at least close!)

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