MATHEMATICS HIGH SCHOOL

PLEASE HELP! thank you so much! :)Which of the following can form a cross
section?
A a point and a triangle
B a plane and a cone
C a circle and a square
D a line and a

Answers

Answer 1

Answer: A I believe good luck

Answer 2

Answer:

Answer:

Step-by-step explanation:

I did this before and I got it correct

Related Questions

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What is the volume of a sphere with a diameter of 11ft? Round your answer to the nearest cubic foot. 2786 cubic feet 5572 cubic feet 8359 cubic feet 6193 cubic feet
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Okay so I have multiple questions that I need help with so I will put them below and you will get more points! Once you know the answer put in the comments Answer one is so I no what it is answer two is etc.Question number one:
Find the volume of a cylinder with a diameter of 8 inches and a height that is three times the radius. Use 3.14 for pi and round your answer to the nearest hundredth. (Hint: You may only enter numerals, decimal points, and negative signs in the answer blank)

Question 2:
Given a soda can with a volume of 21 and a diameter of 6, what is the volume of a cone that fits perfectly inside the soda can? (Hint: only enter numerals in the answer blank)

Question 3:
Given a cube with a volume of 27 cm3, what is the volume of a square pyramid that can fit perfectly inside the cube?
A)3cm3
B)6cm3
C)9cm3
D)12cm3
If you can answer all of these you will be getting 20 points only one of these you get 5 and only two of these 15 points so answer all three to get more points.

Answers

Vcylinder=hpir^2
Vcone=(1/3)hpir^2

d/2=r

so

1.
d=8
r=8/2=4
h=3r
h=3(4)
h=12
V=12*3.14*4^2
V=602.88 in^2

2. cone that fits has same base area and therefor same radius
d=6
r=6/2=3
rcone=3
find height of can
V=hpir^2
21=h*3.14*3^2
21=h*3.14*9
0.7431=h
so
cone height=0.7431
radius=3
V=(1/3)(0.7431)(3.14)(3^2)
V=7 cubic units

3.
same base
find dimentions
s=s=s
V=s^3
27=s^2
3=s
Vsquarepyramid=(1/3)hs^2
s=legnth of base
h=height
h=side
V=(1/3)(3)(3^2)
V=9
C

1. 602.88 in^2
2. 7 cubic units
3. 9cm^3, C

Simplify each sum or difference. State any restrictions on the variables.19) (-3x)/(x^2 - 9) + 4/(2x-6)

Answers

Simplify 4
2x-6

1.1 Pull out like factors :

2x - 6 = 2 • (x - 3)

-3x Simplify ——3 over x2 -9———— x2 - 9

(-3x)/(x^2 - 9) + 4/(2x-6) = (-3x)/[(x-3)(x+3)] + 4/[2(x-3)] = (-3x)/[(x-3)(x+3)] + 2/(x-3) =
(-3x + 2x + 6)/[(x-3)(x+3)] = (-x+6)/[(x-3)(x+3)];

What is the intersection of plane STXW and plane SVUT

Answers

I think the answer is S because S is in both planes.

Answer:st

Step-by-step explanation:

={125},={#125}andQ={#125},
finda. ∪ b. ∩ c. d.

Answers

Answer:

h3llo

Step-by-step explanation:

hey the answer is in your heart

Statements Reasons 1. BE || CD 1. Given 2. ∠A ≅ ∠A 2. Reflexive Property 3. ∠ACD ≅ ∠ABE 3. Corresponding angles formed by parallel lines and a transversal are ≅. 4. ∠ADC ≅ ∠AEB 4. Corresponding angles formed by parallel lines and a transversal are ≅. 5. ΔABE ∼ ΔACD 5. ??? Fill in the missing reason for the proof. A) SSS Congruence Theorem B) SSS Similarity Theorem C) AA Similarity Postulate D) SAS Congruence Postulate

Answers

Answer:

The correct option is;

C) AA Similarity Postulate

Step-by-step explanation:

The given parameters are;

BE║CD Given

∠A is congruent to ∠A Reflective property

∠ACD is congruent to ∠ABE Corresponding angles formed by parallel lines and a transversal

∠ADC is congruent to ∠AEB Corresponding angles formed by parallel lines and a transversal

ΔABE ~ ΔACD AA Similarity Postulate

When two angles of one triangle are equal to the corresponding two angles of another triangle, given that the third angle of both triangles are also equivalent based on sum of angles of a triangle postulate, the two triangles are said to be similar based on Angle-Angle (AA) Similarity Postulate.

Solve the following proportion forv/11 = 7/3

Round your answer to the nearest tenth.