The perimeter of a rectangle is 154 feet. The length of the rectangle is 55 feet. What is the width of the rectangle?

Answers

Answer 1

Answer: Hi there! Okay well to find out the width when you all ready have the perimeter and length just add up both sides of the length, 55+55=110 okay now just subtract 110 from 154, 154-110=44 now since there are to sides for width in a rectangle divide 44 by 2, 44÷2=22 so your width is 22 now to check add up all your side's: 55+22+55+22=154 ANSWER: width = 22ft

Answer 2

Answer:

Answer: if you need help with an answer your but will help you

Step-by-step explanation:

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If (-10) is divided by (-2), what is the quotient? a) 2 b) -2 c) 5 d) -5

Answers

Answer:5

Step-by-step explanation:

we know two negatives divided by each other make a positive so -10/-2 is the equivalent of 10/2= 5

Camillo estimates the weight of his dog. The veterinarian says that the dog weighs 84 pounds. The percent error in Camillo's estimates is less than 10%.Decide whether each of the following weight estimates could have been Camillo's estimate.
a. 80 pounds yes or no
b. 78 pounds yes or no
c. 94 pounds yes or no
d. 77 pounds yes or no
e. 92 pounds yes or no
f. 75 pounds yes or no

Answers

Answer:

A.Yes B.Yes C.No D.Yes E.No F.No

Step-by-step explanation:

10% of 84 is 8.4 and 84-8.4=76.6 and anything between 76.6-84 could have been the estimate.

Final answer:

Camillo's weight estimate could have been 80 pounds, 78 pounds, 77 pounds, or 92 pounds.

Explanation:

The percent error measures the discrepancy between an estimated value and an actual value. It is calculated using the formula: Percent Error = (|Measured Value - Actual Value| / Actual Value) * 100%. Since the given problem states that Camillo's estimate has a percent error less than 10%, we can calculate the percent error for each weight estimate and determine if it is less than 10%.

a. 80 pounds: Percent Error = (|80 - 84| / 84) * 100% = 4.76%, which is less than 10%. So, yes, this could have been Camillo's estimate.
b. 78 pounds: Percent Error = (|78 - 84| / 84) * 100% = 7.14%, which is less than 10%. So, yes, this could have been Camillo's estimate.
c. 94 pounds: Percent Error = (|94 - 84| / 84) * 100% = 11.9%, which is not less than 10%. So, no, this could not have been Camillo's estimate.
d. 77 pounds: Percent Error = (|77 - 84| / 84) * 100% = 8.33%, which is less than 10%. So, yes, this could have been Camillo's estimate.
e. 92 pounds: Percent Error = (|92 - 84| / 84) * 100% = 9.52%, which is less than 10%. So, yes, this could have been Camillo's estimate.
f. 75 pounds: Percent Error = (|75 - 84| / 84) * 100% = 10.71%, which is not less than 10%. So, no, this could not have been Camillo's estimate.

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What is 1/2 of a 3/4 cup of milk?

Answers

1/2 × 3/4 = 3/8 ⇒ 1/2 of 3/4 cup of milk is 3/8

Solve the following system of equations for all three variables.5x−2y+z = 8
−9x+2y+2z = 5
−9x−2y−5z = 4

Answers

  5x - 2y + 1z = 8 ⇒   5x - 2y + 1z = 8
-9x + 2y + 2z = 5 ⇒ -9x + 2y + 2z = 5
-9x - 2y - 5z = 4 -4x + 3z = 13

5x - 2y + 1z = 8
-9x + 2y + 2z = 5 ⇒ -9x + 2y + 2z = 5
-9z - 2y - 5z = 4 ⇒ -9x - 2y - 5z = 4
-18x - 3z = 9

-4x + 3z = 13
  -18x - 3z =   9
-22x = 22
  -22 -22
  x = -1
  -18x - 3z = 9
-18(-1) - 3z = 9
18 - 3z = 9
- 18 - 18
-3z = -9
-3 -3
z = 3

5x - 2y + z = 8
5(-1) - 2y + 3 = 8
-5 - 2y + 3 = 8
-2y - 5 + 3 = 8
-2y - 2 = 8
  + 2 + 2
  -2y = 10
-2   -2
y = -5
  (x, y, z) = (-1, -5, 3)

Line segment DCOE is a diameter of circle O, line segment AB is a chord of the circle, and line segment OD is perpendicular to line segment AB at C. If AB=8 and OC=3, find OB

Answers

i did 8+3 #not sure if thats what u would do or not)

Answer:

Step-by-step explanation:

A pharmaceutical company knows that approximately 5% of its birth-control pills have an ingredient that is below the minimum strength, thus rendering the pill ineffective. What is the probability that fewer than 10 in a sample of 200 pills will be ineffective

Answers

Answer:

The probability that fewer than 10 in a sample of 200 pills will be ineffective is 0.4364

∴ P(X<10)=0.4364

Step-by-step explanation:

Given that the total number of sample pills is 200

ie., n=200

To find the probability that fewer than 10 in a sample of 200 pills will be ineffective:

Let us assume it success if a pill is ineffective.

The probability of success in each trial is $p=5\%$

$p=5\%$

$p=(5)/(100)$

$=0.05$

∴ p=0.05

We know that the total probability is p+q=1

The probability of failure is q

q=1-p

q=1-0.05

∴ q=0.95

Let X be the random variable of the number of ineffective pills in a sample of 200 pills.

Hence X has Binomial distribution with parameter n=200 and p=0.05

The formula for Mean in Binomial distribution is

$\mu=np$

Substitute the values in the above formula we get

$\mu=200(0.05)$

∴ $\mu=10$

The formula for Standard deviation in Binomial distribution is

$\sigma=√(npq)$

Substitute the values in the above formula we get

$\sigma=√((200)(0.05)(0.95))$

$=√(9.5)$

$=3.082$

∴ $\sigma=3.082$

Now we have to find the probability that fewer than 10 in a sample of 200 pills will be ineffective.

That is to find the area to the left of x=9.5

The formula is $z=(x-\mu)/(\sigma)$

Substitute the values in the formula we get

$z=(9.5-10)/(3.082)$

$=(-0.5)/(3.082)$

$=-0.16$

∴ $z=-0.16$

Now P(X<10)=P(Z<-0.16)

=0.4364

∴ P(X<10)=0.4364

Therefore the probability that fewer than 10 in a sample of 200 pills will be ineffective is 0.4364

Final answer:

The probability that fewer than 10 out of 200 birth-control pills will be ineffective is approximately 0.817, or 81.7%.

Explanation:

Probability is a mathematical concept used to quantify the likelihood of an event occurring. It ranges from 0 (impossible) to 1 (certain). It plays a crucial role in statistics and decision-making, helping to predict outcomes, assess risk, and make informed choices. To find the probability that fewer than 10 in a sample of 200 birth-control pills will be ineffective, we can use the binomial probability formula:

P(X < 10) = Σ (n choose k) * p^k * (1-p)^(n-k), where:

n = sample size = 200,

k = number of ineffective pills,

p = probability of a pill being ineffective = 0.05.

Calculating this probability using the formula, we get:

P(X < 10) ≈ 0.817, or 81.7%.

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