The approximate size of a galaxy can be measured by using the doppler effect. true or false.

Answers

Answer 1

Answer:

Answer: The correct answer is False.

Explanation:

Scientists use the Doppler effect to understand the universe by determining the motion of the object.

Doppler effect: It is the phenomenon in which there is relative motion between the source and listener or source or observer.

Red shift and blue shift can be explained by using the concept of Doppler effect.

From red shift and blue shift, one can conclude that galaxies or stars are moving towards us or going away from us.

The light is shifted to longer wavelength which is red in the case of red shift. The light is shifted to shorter wavelength which is blue in the case of blue shift.

Therefore, "the approximate size of a galaxy can be measured by using the Doppler effect", the given statement is false.

Answer 2

Answer: Doppler effect just helps us in measuring the deviation of sound when observer or source of sound is in motion. Same thing can be observe in case of electromagnetic radiations but Irregular galaxies are different from elliptical and spiral galaxies because the contain very few stars. Just 'cause of that deviations, we can't use Doppler effect in measuring the size of galaxy

In short, Your Answer would be "False"

Hope this helps!

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If a force of 12 n is applied to an object with a mass of 2kg the object will accelerate at

Answers

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An object is released from rest at time t = 0 and falls through the air, which exerts a resistive force such that the acceleration a of the object is given by a = g bv, where v is the object's speed and b is a constant. If limiting cases for large and small values of t are considered, which of the following is a possible expression for the speed of the object as an explicit function of time? A) v = g(1-e^-bt)/b B) v = (ge^bt)/b C) v = (g+a)t/b

Answers

Answer:

A) $(g)/(b)(1-e^(-bt))$

Explanation:

Since a = g - bv,

We can substitute a = dv/dt into the equation.

Then, the equation will be like dv/dt = g - bv.

So we got first order differential equation.

As known, v = 0 at t = 0, and v = g/b at t = ∞.

Since $(dv)/(dt)= g - bv = b( (g)/(b) - v)$ ⇒ $(dv)/( (g)/(b) - v)= bdt$

So take the integral of both side.

$- ln ((g)/(b) - v) = bt + C$

Since for t=0, v = 0 ⇒ $C =- ln ((g)/(b))$

$v = (g)/(b) + e^{-bt-ln((g)/(b))} = (g)/(b)- (g)/(b)e^(-bt) = (g)/(b)(1-e^(-bt))$

The correct option for the expression of speed as an explicit function of time is option A

A) v = g·(1 - $e^{-b \cdot t$ )/b

The reason why option A is correct is given as follows;

Known:

The initial velocity of the object at time t = 0 is v = 0 (object at rest)

The function that represents the acceleration is a = g - b·v

Where;

v = The speed of the object at the given instant

b = A constant term

By considering the limiting case for time t, we have;

At very large values of t, the velocity will increase such that we have;

$\lim \limits_(t \to \infty) a = 0$ therefore, $\lim \limits_(t \to \infty) g - b\cdot v = 0$ and $\lim \limits_(t \to \infty) \left( v_(max) = (g)/(b) \right)$

The given equation can be rewritten as follows, to express the equation in terms the velocity;

$a = b \cdot \left((g)/(b) - v \right) = b \cdot \left(v_(max) - v \right)$

$Acceleration, \ a = (dv)/(dt)$

Therefore;

$(dv)/(dt) = b \cdot \left((g)/(b) - v \right)$

The above differential equation gives;

$(dv)/( \left((g)/(b) - v \right)) = b \cdot dt$

Which gives;

$\displaystyle \int\limits {(dv)/( \left((g)/(b) - v \right)) } = \int\limits {b \cdot dt} = b \cdot t + C$

$\displaystyle \int\limits {(dv)/( \left((g)/(b) - v \right)) } = -\ln \left((g)/(b) - v \right)$ and $\displaystyle\int\limits{b \cdot dt} = b \cdot t + C$

Therefore

$\displaystyle -\ln \left((g)/(b) - v \right) =b \cdot t + C$

At t = 0, v = 0, therefore;

$\displaystyle -\ln \left((g)/(b) - 0 \right) =b * 0 + C$

$C = \displaystyle -\ln \left((g)/(b) \right)$

Which gives;

$\displaystyle -\ln \left((g)/(b) - v \right) =b \cdot t \displaystyle -\ln \left((g)/(b) \right)$

$\displaystyle \ln \left((g)/(b) - v \right) =-b \cdot t \displaystyle +\ln \left((g)/(b) \right)$

$\displaystyle (g)/(b) - v = e^{-b \cdot t \displaystyle +\ln \left((g)/(b) \right)} = e^(-b \cdot t) * e^\ln \left((g)/(b) \right)} = e^(-b \cdot t) * (g)/(b)$

$\displaystyle (g)/(b) - e^(-b \cdot t) * (g)/(b) = v$

$\displaystyle (g)/(b) \cdot \left(1 - e^(-b \cdot t) \right) = v$

∴ v = g·(1 - $e^{-b \cdot t$ )/b

The correct option is option (A)

Learn more about differential equation here;

brainly.com/question/13309100

Light has properties of both a particle and a wave. true or false

Answers

true light has both the properties

A product _____ is a group of products offered by a firm that are closely related to each other, either in terms of how they work, or the customers they serve. Select one:a. mix
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Answers

A product line is a group of products offered by a firm that are closely related to each other, either in terms of how they work, or the customers they serve. An example is the production of wine, beer, spirit, whiskey, vodka. These products may be different but they are related because they are all alcohol liquor.

What did the protoplanets become?a. nebulae
b. planets
c. solar nebulae
d. planetesimals

Answers

What did the protoplanets become?

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d. planetesimals

The protoplanets become nebulae. The answer is letter A. The rest of the choices do not answer the question above.

The answer is B. Planets

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