A ball rolls along the floor with a constant velocity of 6 m/s. How far will it have gone after 50 seconds?

Answers

Answer 1
Answer:

Answer:

300 m

Explanation:

The ball moves with constant velocity, so the distance it covers is given by:

d=vt

where

v=6 m/s is the ball's velocity

t=50 s is the time

Substituting these numbers into the equation, we find

d=(6 m/s)(50 s)=300 m

Answer 2
Answer: 6 m/s * 50s = 300 m assuming no friction or air resistance

Related Questions

A current is always developed in the secondary of a transformer. true or false
The Coriolis effect is the result of which of the following? A. winds spinning off the equator B. the rotation of the earth on its axis C. the different air movements north and south of the equator D. the friction that slows down winds near the earth’s surface
The equation E=mc^2 relates energy and.a. Force.b. Mass.c. Gravity.d. Work.
Objects on the moon's surface have an acceleration due to gravity one-sixth that on the earth's. What would the 40 kg boy weigh on the moon? (Round answer to nearest tenth.)
Energy of an object due to its motion

Europa, a satellite of Jupiter, is believed to have an ocean of liquid water (with the possibility of life) beneath its icy surface. Europa is 3130 km in diameter and has a mass of 4.78×10²² kg. In the future, we will surely want to send astronauts to investigate Europa.In planning such a future mission, what is the fastest that such an astronaut could walk on the surface of Europa if her legs are 0.960 m long?

Answers

Answer:

1.12 m/s

Explanation:

We are given that

Diameter of Europa=d=3130 Km

Radius of Europa =r=(d)/(2)=\fra{3130}{2}=1565 Km=1565* 10^3 m

1 km=10^3 m

Mass of Europa,m=4.78* 10^(22) kg

We have to find the velocity of astronaut on the surface of Europa if her legs are 0.960 m long.

d=0.960 m

Acceleration due to gravity on the surface of Europa

g=(GM)/(r^2)

Where G=6.67* 10^(-11)Nm^2/kg^2

Substitute the values

a=(6.67* 10^(-11)* 4.78* 10^(22))/((1565* 10^3)^2)

g=1.3 m/s^2

v=√(gd)=√(1.3* 0.960)=1.12 m/s

Which initial quantity is the same for all three cannonballs? Option 1: Mass Option 2: Volume Option 3: Density Option 4: Velocity

Answers

Answer:

Velocity:  At rest they all have zero velocity.

Explanation:

Is there more information (e.g., mass, volume, etc.) for the cannonballs?

Assuming they are at rest, their velocity is the same:  0

An object placed in water will float if the weight of the object is MORE THAN the buoyant force of the water.True
False

Answers

False


If the object weighs more than the buoyant force then the object will sink.

This is because the buoyant force "pushes" the object upwards and the weight of the object "pushes" the object downwards.  Since the force downwards is greater than the force upwards the item will sink, so this statement is False.

~~~Brainliest would be appreciated~~~

I think the answer is true

If a substance forms crystals when it solidifies, its _______ points are the same. a. melting and freezing
b. melting and condensation
c. evaporation and freezing
d. evaporation and condensation

Answers

I think the correct answer is A. If a substance forms crystals when it solidifies, its melting and freezing points are the same. For most substances, it is known that the freezing and the melting points are equal. Freezing happens by crystallization, formation of crystals from the liquid form. 

Answer:

Option (a): Melting point and freezing point are will be the same when crystallization.

Explanation:

When crystals form from the mechanism of crystal growth, it’s known as crystallization. A crystal is a solid type of material which is having a regular pattern of atoms and molecules.

Temperature of a compound which changes its physical state from solid state to liquid state is known as melting point temperature.  

Temperature of a compound which changes its physical state from liquid state to solid state is known as the freezing point temperature.  

Most of the liquids are freeze by the method of crystallization. The temperature of the system remains nearly equal to melting point.

Further Explanation:

Basically there are two types of crystallization processes. They are the cooling and evaporation crystallization.  

Salts, sugar and gemstones are some examples for crystals.  

Crystallization consists with two steps; Nucleation and Crystal growth. In nucleation; solute molecules dispersed in the solvent are gather in to clusters. These clusters need to reach a critical size to become stable nuclei, by factors such as temperature and super saturation.  

After nucleation, crystal growth happens. In this process the nuclei increases its size to a critical cluster size.  

In crystal growth solute molecules precipitate out of solution. Then they dissolve back into solution.  

Learn more:

1. Freezing point brainly.com/question/155317 (answer byTenishaTon)

2. Melting point brainly.com/question/13688040 (answer by olowookereboyede)

Keywords:

Melting point, freezing, crystallization

Which of the following is an example of diffraction? A. Hearing a band play through an open doorway without seeing them. B. Sitting in a room and watching a band play. C. Playing in a band. D. None of these examples show diffraction.

Answers

A because diffraction is the bending of waves around small obstacles or openings. That’s why you can hear a band through an open doorway without seeing them

A force of 2.0 n exerted on an object for 0.1 seconds increases the objects velocity by 1.0 m/s you what is the mass of the object?

Answers

Answer:

The mass of the object is 0.2 kg

Explanation:

The magnitude of the applied force = 2.0 N

The duration of application of the force = 0.1 second

The increase in velocity given to the body by the force = 1.0 m/s

From the equation of motion under acceleration, we have;

v = u + a·t

Therefore;

a = (v - u)/t

Where;

v = The final velocity

u = The initial velocity

t = The time taken for the change in velocity = 0.1 s

Given that the change in velocity = 1 m/s, we have;

v - u = 1 m/s

∴ a = (v - u)/t = 1 m/s/(0.1 s) = 10 m/s²

The acceleration, a = 10 m/s²

The equation for the applied force, F is F = Mass, m × Acceleration, a

Therefore, when the applied force, F = 2.0 N, and the acceleration, a is a = 10 m/s², we have;

F = Mass, m × Acceleration, a

2.0 N = Mass of the object × 10 m/s²

∴ Mass of the object = 2.0 N/10 m/s² = 0.2 kg

The mass of the object = 0.2 kg.