One cubic foot (1 ft3 ) of seawater weighs about 64 pounds. Suppose you pour one cubic foot of seawater into a light plastic bag, tie the bag closed with no air bubbles inside, and lower it into the ocean via a light attached string. When the bag of seawater is completely submerged, how much force do you have to exert on the sting to hold it up: a. 0 lbs b. 32 lbs c. 64 lbs d. 128 lbs e. You have to push it down because it tends to come up. Please circle your answer and explain your reasoning.

Answers

Answer 1

Answer: The correct answer for the question that is being presented above is this one: "b. 32 lbs." Suppose you pour one cubic foot of seawater into a light plastic bag, tie the bag closed with o air bubbles inside, and lower it into the ocean via a light attached string. When the bag of seawater is completely submerged the force will be 32 lbs.

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Heat in a substance is an example of _____ energy?

Answers

Heat in a substance is still an example of heator thermal energy. Heat or thermal energy is further defined as the amount ofavailable molecules of kinetic energy transferred in a specific amount of time.Heat is nothing if it is not transferred from one object to another. There aremany uses of heat energy. When we are cooking using our stoves, there is heatenergy. When we pour hot water onto our cup of coffee, there is heat energy.

Which state of matter is most likely represented in the image?

Answers

It’s a liquid state !

Answer: plasma

Explanation:

Plz give Brainlies. I have 0.

The peak intensity of radiation from Star Beta is 350 nm. What is the average surface temperature of Star Beta rounded to the nearest whole number? 121 K 6,547 K 8,285 K 10,348 K

Answers

Wien's Displacement Law is:
peak x surface temperature = 2.898 x 10^-3 m K

So,
surface temperature = 2.898 x 10^-3 m K / peak = 2.898 x 10^-3 m K / 350 x 10 -9 m
surface temperature = 8280 K

The closest to the choices is 8285 K.

Answer:

8285 K.

Explanation:

Calculate the average force that must be exerted on a 0.145 kg baseball in order to give it an acceleration of 130 m/s2.

Answers

Answer:

F = 18.9 N

Explanation:

m = 0145 kg

a = 130 m^2

F = ma = (0.145kg)(130m/s^2) = 18.9N

A golfer is on the edge of a 12.5 m bluff overlooking the 18th hole which is located 60 m from the base of the bluff. She launches a horizontal shot that lands in the hole on the fly. The gallery erupts in cheers.

Answers

Answer:

The ball impact velocity i.e(velocity right before landing) is 6.359 m/s

Explanation:

This problem is related to parabolic motion and can be solved by the following equations:

$x=V_(o)cos \theta t$ ----------------------(1)

$y=y_(o)+V_(o) sin \theta t - (1)/(2)gt^(2)$ ---------(2)

$V=V_(o)-gt$ ----------------------- (3)

Where:

x = m is the horizontal distance travelled by the golf ball

$V_(o)$ is the golf ball's initial velocity

$\theta=0\°$ is the angle (it was a horizontal shot)

t is the time

y is the final height of the ball

$y_(o)$ is the initial height of the ball

g is the acceleration due gravity

V is the final velocity of the ball

Step 1: finding t

Let use the equation(2)

$t=\sqrt{(2 y_(o))/(g)}$

$t=\sqrt{(2 (12.5 m))/(9.8 m/s^(2))}$

$t=1.597$ s

Substituting (6) in (1):

$67.1 =V_(o) cos(0\°) 1.597$ -------------------(4)

Step 2: Finding $V_(o)$ :

From equation(4)

$67.1 =V_(o)(1) 1.597$

$V_0 = (6.71)/(1.597)$

$V_(o)=42.01$ m/s (8)

Substituting $V_(o)$ in (3):

$V=42.01 -(9.8)(1.597)$

v =42 .01 - 15.3566

V=26.359 m/s

If Inability to maintain posture while standing still would indicate a problem with which equilibrium receptor?

Answers

The inability to maintain posture while standing still would indicate a problem with the static equilibrium receptors. Static equilibrium receptors provide information about body position relative to the force of gravity: standing upright v. being upside done. Hope this helps.

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