The magnitude of the kayaker's resultant velocity is 4.96 m/s.
The direction of the kayaker’s resultant velocity from the triangle is 20⁰ South of west.
The magnitude of the kayaker's resultant velocity is calculated by drawing the vector representation of the velocity to form a triangle, with side lengths of 3.7 m/s and 4 m/s, with 80⁰ angle between the two sides.
Let the resultant velocity = R
The direction of the kayaker’s resultant velocity from the triangle is 20⁰ South of west (alternate angles).
Learn more about resultant velocity here: brainly.com/question/24767211
Answer:
7.2 m/s
49 south of west
Explanation:
I got it correct on Edge. :)
B.) general relativity
C.) law of conservation of momentum
D.) thermodynamics
Answer:
Once a well has reached the water table, it will not run dry true or false? -earth science
Explanation: IT IS FALSE!!! HAVE A GREAT DAY
B) sand, silt, and clay
C) sand, clay, and pebbles
D) boulders, clay, and silt
AContrast
BFaces
CColors
Improving the contrast of an image (making the dark regions darker and the light regions lighter) helps us to identify:
AThe edges of objects
BThe center of objects
CThe color of an object
What assumption does our visual system make in order to see curved surfaces (domes, holes)?
ALight comes from above
BCurved surfaces are always evenly lit
CCurved surfaces are always easy to see, no assumptions are made
Which part of the face does our brain pay the most attention to?
AEyes and mouth
BEyes and ears
CEyes and chin
If all these assumptions sometimes lead to mistakes, for example in these optical illusions, why do we make them?
AIt helps us see things faster
BIt helps us see things correctly
CIt helps us pay attention to what's important
DAll of the above
Explanation :
Given that,
Velocity of the car, v = 20 m/s
Kinetic energy of the car,
Kinetic energy is given by :
So,
m = 900 kg
Hence, the mass of the car is 900 kg
Answer: 3.4s
Explanation:
There are three stages in the motion of the ball, so you have to calculate the times for every stage.
1) Ball dropping from 9.5m: free fall
d = Vo + gt² / 2
Vo = 0 ⇒ d = gt² / 2 ⇒ t² = 2d / g = 2 × 9.5 m / 9.81 m/s² = 1.94 s²
⇒ t = √ (1.94 s²) = 1.39s
2) Ball rising 5.7m (vertical rise)
i) Determine the initial speed:
Vf² = Vo² - 2gd
Vf² = 0 ⇒ Vo² = 2gd = 2 × 9.81 m/s² × 5.7m = 111.8 m²/s²
⇒ Vo = 10.6 m/s
ii) time rising
Vf = Vo - gt
Vf = 0 ⇒ Vo = gt ⇒
t = Vo / g = 10.6 m/s / 9.81 m/s² = 1.08 s
3) Ball dropping from 5.7 m to 1.20m above the pavement (free fall)
i) d = 5.7m - 1.20m = 4.5m
ii) d = gt² / 2 ⇒ t² = 2d / g = 2 × 4.5 m / 9.81 m/s² = 0.92 s²
⇒ t = √ (0.92 s²) = 0.96s
4) Total time
t = 1.39s + 1.08s + 0.96s = 3.43s ≈ 3.4s