The coefficient of friction between the 20 kg box and the floor is 0.2
We'll begin by calculating the acceleration of the box. This can be obtained as follow:
Initial velocity (u) = 10 m/s
Final velocity (v) = 0 m/s
Distance (s) = 25 m
v² = u² + 2as
0² = 10² + (2 × a × 25)
0 = 100 + 50a
Collect like terms
0 – 100 = 50a
–100 = 50a
Divide both side by 50
Finally, we shall determine the coefficient of friction. This can be obtained as follow:
Mass (m) = 20 Kg
Acceleration (a) = –2 m/s²
Acceleration due to gravity (g) = 10 m/s²
Frictional Force (F) = –ma = – (20 × –2) = 40 N
Normal reaction (N) = mg = 20 × 10 = 200 N
Therefore, the coefficient of friction between the box and the floor is 0.2
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The coefficient of friction between the box and the floor is 0.204.
Given data:
The mass of box is, m = 20 kg.
The initial speed of box is, u = 10 m/s.
The sliding distance is, s = 25 m.
The linear force acting on the fox is providing it necessary friction. Then,
Here, a is the linear acceleration and is the coefficient of friction between the box and the floor.
Applying the third kinematic equation of motion as,
Then,
Thus, we can conclude that the coefficient of friction between the box and the floor is 0.204.
Learn more about frictional force here:
B. distance.
C. weight.
D. direction.
The Correct answer to this question for Penn Foster Students is: Direction
A parsec is a unit of distance used in astrophysics to measure the distance between celestial objects. It is equal to 3.26 light-years or approximately 31 trillion kilometers.
A parsec is a unit of distance used in astrophysics to measure the distance between celestial objects. It is equal to 3.26 light-years or approximately 31 trillion kilometers. The concept of a parsec is based on stellar parallax, which is a method used to calculate distances to nearby stars.
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Answer:
.17Hz
Explanation:
The formula for frequency is f= 1/T , where T is the period.
f = 1/6 and 1/6 ≈ .17