b. mixture
c. solution
d. molecules
Answer: D. calcium chloride
Explanation:
In reaction equations, reactants are on the left side of the arrow and products are on the right side of the arrow. So, our reactants are the elements calcium and chlorine, and our product is the compound calcium chloride.
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In the given chemical reaction equation, the product is calcium chloride as it is formed from the reaction of calcium and chlorine.
In a chemical reaction, substances that are formed as a result of the reaction are known as products. In the given chemical equation, calcium (Ca) reacts with chlorine (Cl2) to produce calcium chloride (CaCl2). Therefore, in this reaction equation, the product is calcium chloride. The reactants, substances that exist before the reaction, are calcium and chlorine. So, the correct answer to your question is D. calcium chloride.
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B. arsenic (As)
C. bromine (Br)
D. calcium (Ca)
Answer:
A. Potassium (K)
Explanation:
The trend of atomic radius goes:
As group number increases, radius decreases
As period number increases, radius increases
Answer:
francium
Explanation:
Atomic radii vary in a predictable way across the periodic table. As can be seen in the figures below, the atomic radius increases from top to bottom in a group, and decreases from left to right across a period. Thus, helium is the smallest element, and francium is the largest.
Ca²⁺
Ionization energy is defined as the minimum amount of energy required to knock out the electron from valence shell of an atom in its gaseous state. While, second Ionization energy is defined as the amount of energy required to knock out the second electron from an ion containing +1 charge in gaseous state.
Among given options Ca²⁺ is the correct choice because the calcium has lost two electrons i.e. first electron was removed by providing first ionization energy i.e.
Ca + 1st IE → Ca¹⁺ + 1 e⁻
and second electron is was removed by providing second ionization energy i.e.
Ca ¹⁺ + 2nd IE → Ca²⁺ + 1 e⁻
is formed by providing the second ionization energy to remove an electron.
Further Explanation:
The energy that is needed to remove the most loosely bound valenceelectrons from the isolated neutral gaseous atom is known as the ionization energy. It is denoted by IE. The value of IE is related to the ease of removing the outermost valence electrons. If these electrons are removed so easily, small ionization energy is required and vice-versa. It is inversely proportional to the size of the atom.
Ionization energy is further represented as first ionization, second ionization and so on. When the first electron is removed from a neutral, isolated gaseous atom, the energy needed for the purpose is known as the first ionization energy, written as . Similarly, when the second electron is removed from the positively charged species (cation), the ionization energy is called the second ionization energy and so on.
The neutral atom corresponding to is calcium. If second ionization energy is supplied to calcium atom, it results in the removal of two electrons and thus is formed. So can be formed by providing second ionization energy. to the neutral atom.
The neutral atom corresponding to is nitrogen. If second ionization energy is supplied to nitrogen, it results in the formation of, not . So cannot be formed by providing the second ionization energy to the neutral atom.
The neutral atom corresponding to is iron. If second ionization energy is supplied to the iron atom, it results in the formation of , not . So cannot be formed by providing the second ionization energy to the neutral atom.
The neutral atom corresponding to is sulfur. If second ionization energy is supplied to the sulfur atom, it results in the formation of , not . So cannot be formed by providing the second ionization energy to the neutral atom.
Therefore, the only ion that can be formed by supplying the second ionization energy is .
Learn more:
1. Which is the oxidation-reduction reaction:
2. What is the mass of 1 mole of viruses: brainly.com/question/8353774
Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Periodic classification of elements
Keywords: second ionization energy, Ca2+, N3-, Fe3+, S2-, IE1, IE2, first electron, second electron, neutral atom., nitrogen, calcium, iron, sulfur.