B) $22,000
C) $21,000
D) $20,000
Answer: C) $21,000
Step-by-step explanation:
Given : Pat bought a boat for $37,000 in 2001. In 2006 the boat was worth $27,000.
If the boat depreciation is linear, then the amount by which the value of boat depreciates must be constant.
Let x be the constant depreciation in the value of boat per year.
Then , the value of boat (in dollars) after n years from 2001 is given by :-
(1)
For year 2006 , n=5 and V = 27000
Then ,
i.e.
i.e.
i.e.
Thus , the constant amount of depreciation in the value of boat per year. = $2000
Now for year 2009 , put in n=8 and x= 2000 in (1), we get
Hence, the value of boat in 2009 = $21,000
12.5 multiplie dy 6 equals 75
100 plus 75 equals 175
which gives you the exact amount of money you need to use to buy 10 acres of land on mars.
so the answer is 6 months
Sample Response: First, the like terms had to be combined using the lowest common denominator (LCD). Then the subtraction property of equality was used to isolate the variable term. Finally, both sides of the equation were multiplied by the reciprocal of the coefficient to solve for a.
we are given
Firstly, we will change it into standard equation of circle
that is
where r is radius
(h,k) is center
now, we can change our equation into this form
To change our equation into this form, we need to complete x square and y square
step-1: Move 2 on right side
step-2: Complete x square
step-3: Complete y square
step-4: Combine right side terms
now, we can compare with our equation
and we will get
radius =r=6...............Answer
center=(h,k)=(3,-5)........................Answer