The conversion of carbon dioxide to oxygen by plants is called _____. A. polysynthesis B. photosynthesis C. amino-acid synthesis D. amino-acid production

Answers

Answer 1

Answer: The conversion of carbon dioxide to oxygen by plants is called photosynthesis.

Answer 2

Answer: The answer would be B, photosynthesis.
Using the process of elimination, the answer is easy to find.

Polysynthesis - The act or process of combining many separate elements into a whole (Free Dictionary)

Amino-acid Synthesis - No definition, but this is clearly not the answer as amino acid has nothing to do with carbon dioxide or oxygen.

Amino-acid Production - This doesn't work for the same reason as the last one. Amino acid is irrelevant.

Therefore, the answer is photosynthesis.

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A rigid, 2.50 L bottle contains 0.458 mol He. The pressure of the gas inside the bottle is 1.83 atm. If 0.713 mol Ar is added to the bottle and the pressure increases to 2.05 atm, what is the change in temperature of the gas mixture?The initial temperature of the gas is ______ K.
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An Earth satellite in orbit emits a radio signal of constant frequency. Compared to the emitted frequency, the frequency of the signal received by a stationary observer will appear to be:a) higher as the satellite approaches
b) higher as the satellite moves away
c) lower as the satellite approaches
d) unaffected by the satellite's motion

Answers

The best and most correct answer among the choices provided by your question is the first choice or letter A.

Compared to the emitted frequency, the frequency of the signal received by a stationary observer will appear to be: higher as the satellite approaches

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

What are the three parts of a nucleotide

Answers

The building blocks of nucleic acids, nucleotides are composed of a nitrogenous base, a five-carbon sugar (ribose or deoxyribose), and at least one phosphate group.

Answer: an organic base, a phosphate group, and a sugar

Explanation:

80123.00 in scientific notation then rounded up to 3 sig figs

Answers

not exactly sure what the last part of the question is but in regular scientific notation it would be " 8.0123x10 (to the 4th power)"

there wasnt a sign for the exponent lol

You kick a ball with a speed of 14 m/s at an angle of 51 degrees. How far away does the ball land?A. 21.3 m
B. 19.6 m
C. 1.8 m
D. 3.96 m

Answers

Answer: The ball will land at 19.6 m

Explanation:

To calculate the horizontal range of the ball, we use the formula:

$R=(v^2\sin 2\theta)/(g)$

where,

v = velocity of the ball = 14 m/s

$\theta$ = angle at which the ball is thrown = 51°

g = acceleration due to gravity = $9.8m/s^2$

Putting values in above equation, we get:

$R=((14)^2* \sin (2* 51))/(9.8)\n\nR=19.6m$

Hence, the ball will land at 19.6 m

d may be the correct answer because speed is very low so ball should cover less distance but angle is not very high so it can cover little much distance

Which of the following is not a state of matter?a. solid
b. liquid
c. water
d. plasma

Answers

Water doesn't belong on that list.

If it's removed, then there's a space to add GAS, which does belong.

Two charged objects, A and B, exert an electric force on each other. What happens if the distance between them is increased?

Answers

The correct answer to the question will be that the electric force between them will be decreased.

EXPLANATION:

Let us consider the charge contained by A and B are denoted as Q and Q' respectively.

Let R is the separation distance between them.

As per Coulomb's law in electrostatics, the force of attraction or repulsion between the two charge bodies A and B will be -

Coulombic force F = $(1)/(4\pi \epsilon) (QQ')/(R^2)$

Here, $\epsilon$ is the permittivity of the medium in which the charges are present.

From above, we see that electric force is inversely proportional to the square of separation distance between them.

Mathematically it can be written: $F\ \alpha\ (1)/(R^2)$

As per the question, the distance between A and B is increased.

Hence, the electric force between A and B will be decreased.

I agree with Hussein but I would like to add that when the distance between two charged objects increase, the force decreases by the Coulomb` s Law:
F= k * Q1*Q2 / r^2
where k is constant Q1, Q2-quantity of electricity and r- distance between two charged objects. So when you increase r, you divide with greater number and result decreases.
$F=k(q1 * q2)/( r^(2) )$

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